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    1. a 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. calculate the percentage composition of the compound by weight.

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    Question 1 A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.

    Question 1 A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.

    Byju's Answer Standard IX Chemistry

    Discovery and Occurence of Hydrogen

    Question 1 A ... Question

    Question 1

    A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.

    Open in App Solution

    Total mass of compound = 0.24 g (given)

    Mass of boron = 0.096 g (given)

    Mass of oxygen = 0.144 g (given)

    Percent composition of compond:

    G i v e n m a s s o f e l e m e n t T o t a l m a s s o f c o m p o u n d × 100

    Thus, percentage of boron by weight in the compound

    = 0.096 0.24 × 100 % = 40 %

    And, percentage of oxygen by weight in the compound

    = 0.144 0.24 × 100 % = 60 % Suggest Corrections 346 SIMILAR QUESTIONS

    Q. Question 1

    A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.

    Q. Question 1

    A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.

    Q. A

    0.24 g

    of sample of compound of oxygen and boron was found by analysis to contain

    0.096 g boron and 0.144 g

    of oxygen. Calculate the percentage composition of boron and oxygen by mass.

    Q. 0.48 g of a sample of a compound containing boron and oxygen contains 0.192 g of boron and 0.288 g of oxygen. What will be the percentage composition of the compound?

    स्रोत : byjus.com

    A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.

    Click here👆to get an answer to your question ✍️ A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.

    Question

    A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.

    Hard Open in App

    Updated on : 2022-09-05

    Solution Verified by Toppr

    Mass of the given sample compound = 0.24g

    Mass of boron in the given sample compound = 0.096g

    Mass of oxygen in the given sample compound = 0.144g

    % composition of compound = % of boron and % of oxygen

    Therefore % of boron = (mass of boron)/(mass of the sample compound) x 100

    = 40%

    Therefore % of oxygen = (mass of oxygen) / (mass of the sample compound) x 100

    = 60% Video Explanation

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    A 0.24 g sample of compound of oxygen and boron was found by analysis

    A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.AnswerGiven mass of the compound = 0.24gMass of Boron in the given sample = 0.096gMass of Oxygen in the given sample

    Check sibling questions

    NCERT Question 1 - Chapter 3 Class 9 - Atoms And Molecules (Term 2)

    Last updated at June 19, 2021 by Teachoo

    A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.

    Answer

    Given mass of the compound = 0.24g

    Mass of Boron in the given sample = 0.096g

    Mass of Oxygen in the given sample = 0.144g

    Percentage composition = (Mass of one element / Mass of given sample) x 100 Percentage of Boron = (Mass of one Boron / Mass of given sample) x 100

    = (0.096 / 0.24) x 100

    = 40%

    Percentage of Oxygen = (Mass of one Oxygen / Mass of given sample) x 100

    = (0.144 / 0.24) x 100

    = 60%

    Hence percentage composition of the sample is 40% Boron and 60% Oxygen

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