1. a 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. calculate the percentage composition of the compound by weight.
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Question 1 A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.
Question 1 A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.
Byju's Answer Standard IX Chemistry
Discovery and Occurence of Hydrogen
Question 1 A ... Question
Question 1A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.
Open in App Solution
Total mass of compound = 0.24 g (given)
Mass of boron = 0.096 g (given)
Mass of oxygen = 0.144 g (given)
Percent composition of compond:
G i v e n m a s s o f e l e m e n t T o t a l m a s s o f c o m p o u n d × 100
Thus, percentage of boron by weight in the compound
= 0.096 0.24 × 100 % = 40 %
And, percentage of oxygen by weight in the compound
= 0.144 0.24 × 100 % = 60 % Suggest Corrections 346 SIMILAR QUESTIONS
Q. Question 1A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.
Q. Question 1A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.
Q. A0.24 g
of sample of compound of oxygen and boron was found by analysis to contain
0.096 g boron and 0.144 g
of oxygen. Calculate the percentage composition of boron and oxygen by mass.
Q. 0.48 g of a sample of a compound containing boron and oxygen contains 0.192 g of boron and 0.288 g of oxygen. What will be the percentage composition of the compound?A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.
Click here👆to get an answer to your question ✍️ A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.
Question
A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.
Hard Open in App
Updated on : 2022-09-05
Solution Verified by Toppr
Mass of the given sample compound = 0.24g
Mass of boron in the given sample compound = 0.096g
Mass of oxygen in the given sample compound = 0.144g
% composition of compound = % of boron and % of oxygen
Therefore % of boron = (mass of boron)/(mass of the sample compound) x 100
= 40%
Therefore % of oxygen = (mass of oxygen) / (mass of the sample compound) x 100
= 60% Video Explanation
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A 0.24 g sample of compound of oxygen and boron was found by analysis
A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.AnswerGiven mass of the compound = 0.24gMass of Boron in the given sample = 0.096gMass of Oxygen in the given sample
NCERT Question 1 - Chapter 3 Class 9 - Atoms And Molecules (Term 2)
Last updated at June 19, 2021 by Teachoo
A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.
AnswerGiven mass of the compound = 0.24g
Mass of Boron in the given sample = 0.096g
Mass of Oxygen in the given sample = 0.144g
Percentage composition = (Mass of one element / Mass of given sample) x 100 Percentage of Boron = (Mass of one Boron / Mass of given sample) x 100= (0.096 / 0.24) x 100
= 40%
Percentage of Oxygen = (Mass of one Oxygen / Mass of given sample) x 100= (0.144 / 0.24) x 100
= 60%
Hence percentage composition of the sample is 40% Boron and 60% Oxygen
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Guys, does anyone know the answer?