10 men and 15 women together can complete a work in 6 days. it takes 100 days for one man alone to complete the same work. how many days will be required for one woman alone to complete the same work?
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10 men and 15 women together can complete a work in 6 days. It takes 100 days for 1 man alone to complete the same work. How many days will be required for one woman alone to complete the same work?
10 men and 15 women together can complete a work in 6 days. It takes 100 days for 1 man alone to complete the same work. How many days will be required for one woman alone to complete the same work?
Byju's Answer Other
Quantitative Aptitude
Time & Work 10 men and 15... Question
10 men and 15 women together can complete a work in 6 days. It takes 100 days for 1 man alone to complete the same work. How many days will be required for one woman alone to complete the same work?
A 90 B 125 C 145 D 150 E None of these Open in App Solution
The correct option is B
None of these
1 man's 1 day's work
= 1 100
(10 men + 15 women)'s 1 day's work
= 1 6
15 women's 1 day's work
= ( 1 6 − 10 100 ) = ( 1 6 − 1 10 ) = 1 15
1 woman's 1 day's work
= 1 225 ∴
1 woman alone can complete the work in 225 days.
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If 10 men and 15 women finish a work in 6 days. One man alone finishes that work in 100 days. In how many days will a women finish the work?
Click here👆to get an answer to your question ✍️ If 10 men and 15 women finish a work in 6 days. One man alone finishes that work in 100 days. In how many days will a women finish the work?
Question
If 10 men and 15 women finish a work in 6 days. One man alone finishes that work in 100 days. In how many days will a women finish the work?
A125 days
B150 days
C90 days
D225 days
Medium Open in App
Updated on : 2022-09-05
Solution Verified by Toppr
Correct option is D)
1 man can finish the whole work in 100 days∴ 1 man's 1 days' work =
100 1
⇒ 10 men's 1 days' work =10×
100 1 = 10 1
Let the time taken by one woman to finish the work be x days.
Then, 1 woman's 1 days' work =
x 1
⇒ 15 women's 1 days' work =
x 15
Given, (10 men's + 15 women's ) 1 days' work =
6 1 ⇒ 10 1 + x 15 = 6 1 ⇒ x 15 = 6 1 − 10 1 = 30 5−3 = 30 2 = 15 1 ⇒x=225 days.
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10 men and 15 women together can complete a work i
Time and Work Questions & Answers for AIEEE,Bank Exams,CAT,GATE, Analyst,Bank Clerk,Bank PO,Database Administration,IT Trainer : 10 men and 15 women together can complete a work in 6 days. It takes 100 days for one man alone to complete the same work. How many days will be requi
38 Q:
10 men and 15 women together can complete a work in 6 days. It takes 100 days for one man alone to complete the same work. How many days will be required for one woman alone to complete the same work?
A) 215 days B) 225 days
C) 235 days D) 240 days
Answer: B) 225 days
Explanation: Given that
(10M + 15W) x 6 days = 1M x 100 days=> 60M + 90W = 100M => 40M = 90W => 4M = 9W.
From the given data,
1M can do the work in 100 days
=> 4M can do the same work in 100/4= 25 days.
=> 9W can do the same work in 25 days.
=> 1W can do the same work in 25 x 9 = 225 days.
Hence, 1 woman can do the same work in 225 days.
Subject: Time and Work - Quantitative Aptitude - Arithmetic Ability
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO , Database Administration , IT Trainer
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