# a, b and c can do a piece of work in 20 days, 30 days and 40 days respectively. they began the work together but c left 5 days before the completion of the work. in how many days was the work completed?

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get a, b and c can do a piece of work in 20 days, 30 days and 40 days respectively. they began the work together but c left 5 days before the completion of the work. in how many days was the work completed? from screen.

## A,B and c can do a piece of work in 24,30 and 40 days respectively. The began the work together but C left the work four days before the completion of the work. The work was completed in

Click here👆to get an answer to your question ✍️ A,B and c can do a piece of work in 24,30 and 40 days respectively. The began the work together but C left the work four days before the completion of the work. The work was completed in

Question

## A,B and c can do a piece of work in 24,30 and 40 days respectively. The began the work together but C left the work four days before the completion of the work. The work was completed in

**A**

## 9 days

**B**

## 10 days

**C**

## 11 days

**D**

## 14 days

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Updated on : 2022-09-05

Solution Verified by Toppr

Correct option is C)

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## A, B and C can do a piece of work in 24 days, 30 d

Time and Work Questions & Answers : A, B and C can do a piece of work in 24 days, 30 days and 40 days respectively. They began the work together but C left 4 days before the completion o

709 Q:

A, B and C can do a piece of work in 24 days, 30 days and 40 days respectively. They began the work together but C left 4 days before the completion of the work. In how many days was the work completed?

A) 11 days B) 12 days

C) 13 days D) 14 days

Answer: A) 11 days

Explanation:

One day's work of A, B and C = (1/24 + 1/30 + 1/40) = 1/10.

C leaves 4 days before completion of the work, which means only A and B work during the last 4 days.

Work done by A and B together in the last 4 days = 4 (1/24 + 1/30) = 3/10.

Remaining Work = 7/10, which was done by A,B and C in the initial number of days.

Number of days required for this initial work = 7 days.

Thus, the total numbers of days required = 4 + 7 = 11 days.

Subject: Time and Work - Quantitative Aptitude - Arithmetic Ability

## A, B, and C can do a piece of work in 24, 30, and 40 days, respectively. They began to work together, but C left 4 days before the completion of the work. In how many days was the work done?

Answer (1 of 22): A=24 days B= 30 days C= 40 days( LCM =120) A’s efficiency =5 B’s efficiency =4 C’s efficiency = 3 In 1 day they can produce 12 units of work. Total work=120 units However 4 days before completion C leaves which means A+B work for 4 days alone producing 9 units per day = 3...

A, B, and C can do a piece of work in 24, 30, and 40 days, respectively. They began to work together, but C left 4 days before the completion of the work. In how many days was the work done?

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Sort Rohan

Studies at Brilliant Study Centre, Pala (Expected 2023)1y

Related

A can work 24 days, B can work 30 days, and C can work 40 days. They started their work altogether, so C went out before four days. How many days did the work finish?

A takes 24 days B takes 30 days C takes 40 days LCM(24,30,40) =120 A’s efficiency =5 B’s efficiency =4 C’s efficiency = 3

In 1 day they can produce 12 units of work.

Total work=120 units

However 4 days before completion C leaves which means

A+B work for 4 days alone producing 9 units per day = 36 units.

Therefore

Work completed by A+B+C= (120-36)

= 84 units

Hence A+B+C worked for 7 days producing 84 units and A+B worked for 4 days producing 36 units Total 7+4=11 days.

Comment if any doubt.

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Uma Subramanian

Studied at Mumbai, Maharashtra, India (Graduated 1977)Author has 2.9K answers and 2.1M answer views2y

A=24 days B= 30 days

C= 40 days( LCM =120)

A’s efficiency =5 B’s efficiency =4 C’s efficiency = 3

In 1 day they can produce 12 units of work. Total work=120 units

However 4 days before completion C leaves which means A+B work for 4 days alone producing 9 units per day = 36 units. Therefore work completed by A+B+C= (120-36) 84 units

Hence A+B+C worked for 7 days producing 84 units and A+B worked for 4 days producing 36 units Total 7+4=11 days.

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Ankita Singh

Studied Bachelor of Technology in Information Technology (Graduated 2015)2y

Take lcm of 24, 30 and 40. It will come 120.

So, A's one day work will be 5 unit, B's 4 unit and C's will be 3 unit.

C left, 4 days before it means 4 days A and B only worked together i.e

(A + B)'s 4 day work will be = 4 *(5+4)= 36 unit

Remaining work = (120 - 36) = 84 unit

Remaining work will be done by all of them together i.e = 84/12 = 7 days

Total days = 7 + 4 = 11 days

Ranjan Karnad

Former Retired Banker (1972–2000)Author has 5.7K answers and 2.5M answer views1y

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A can work 24 days, B can work 30 days, and C can work 40 days. They started their work altogether, so C went out before four days. How many days did the work finish?

Let them finish the work in x days

x/24 + x/30 + (x-4) /40 = 1

5x + 4x + 3( x-4) = 120

12x = 132 x = 11 days ANSWER CHECK

11/24 +11/30 + 7/40 = (55+ 44 +21) /120 = 120/120 =1

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A can work 24 days, B can work 30 days, and C can work 40 days. They started their work altogether, so C went out before four days. How many days did the work finish?

Guys, does anyone know the answer?