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    a, b and c can do a piece of work in 20 days, 30 days and 40 days respectively. they began the work together but c left 5 days before the completion of the work. in how many days was the work completed?

    Mohammed

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    get a, b and c can do a piece of work in 20 days, 30 days and 40 days respectively. they began the work together but c left 5 days before the completion of the work. in how many days was the work completed? from screen.

    A,B and c can do a piece of work in 24,30 and 40 days respectively. The began the work together but C left the work four days before the completion of the work. The work was completed in

    Click here👆to get an answer to your question ✍️ A,B and c can do a piece of work in 24,30 and 40 days respectively. The began the work together but C left the work four days before the completion of the work. The work was completed in

    Question

    A,B and c can do a piece of work in 24,30 and 40 days respectively. The began the work together but C left the work four days before the completion of the work. The work was completed in

    A

    9 days

    B

    10 days

    C

    11 days

    D

    14 days

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    Updated on : 2022-09-05

    Solution Verified by Toppr

    Correct option is C)

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    A, B and C can do a piece of work in 24 days, 30 d

    Time and Work Questions & Answers : A, B and C can do a piece of work in 24 days, 30 days and 40 days respectively. They began the work together but C left 4 days before the completion o

    709 Q:

    A, B and C can do a piece of work in 24 days, 30 days and 40 days respectively. They began the work together but C left 4 days before the completion of the work. In how many days was the work completed?

    A) 11 days B) 12 days

    C) 13 days D) 14 days

    Answer:   A) 11 days

    Explanation:

    One day's work of A, B and C = (1/24 + 1/30 + 1/40) = 1/10.

    C leaves 4 days before completion of the work, which means only A and B work during the last 4 days.

    Work done by A and B together in the last 4 days = 4 (1/24 + 1/30) = 3/10.

    Remaining Work = 7/10, which was done by A,B and C in the initial number of days.

    Number of days required for this initial work = 7 days.

    Thus, the total numbers of days required = 4 + 7 = 11 days.

    Subject: Time and Work - Quantitative Aptitude - Arithmetic Ability

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    A, B, and C can do a piece of work in 24, 30, and 40 days, respectively. They began to work together, but C left 4 days before the completion of the work. In how many days was the work done?

    Answer (1 of 22): A=24 days B= 30 days C= 40 days( LCM =120) A’s efficiency =5 B’s efficiency =4 C’s efficiency = 3 In 1 day they can produce 12 units of work. Total work=120 units However 4 days before completion C leaves which means A+B work for 4 days alone producing 9 units per day = 3...

    A, B, and C can do a piece of work in 24, 30, and 40 days, respectively. They began to work together, but C left 4 days before the completion of the work. In how many days was the work done?

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    A can work 24 days, B can work 30 days, and C can work 40 days. They started their work altogether, so C went out before four days. How many days did the work finish?

    A takes 24 days B takes 30 days C takes 40 days LCM(24,30,40) =120 A’s efficiency =5 B’s efficiency =4 C’s efficiency = 3

    In 1 day they can produce 12 units of work.

    Total work=120 units

    However 4 days before completion C leaves which means

    A+B work for 4 days alone producing 9 units per day = 36 units.

    Therefore

    Work completed by A+B+C= (120-36)

    = 84 units

    Hence A+B+C worked for 7 days producing 84 units and A+B worked for 4 days producing 36 units Total 7+4=11 days.

    Comment if any doubt.

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    Uma Subramanian

    Studied at Mumbai, Maharashtra, India (Graduated 1977)Author has 2.9K answers and 2.1M answer views2y

    A=24 days B= 30 days

    C= 40 days( LCM =120)

    A’s efficiency =5 B’s efficiency =4 C’s efficiency = 3

    In 1 day they can produce 12 units of work. Total work=120 units

    However 4 days before completion C leaves which means A+B work for 4 days alone producing 9 units per day = 36 units. Therefore work completed by A+B+C= (120-36) 84 units

    Hence A+B+C worked for 7 days producing 84 units and A+B worked for 4 days producing 36 units Total 7+4=11 days.

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    Ankita Singh

    Studied Bachelor of Technology in Information Technology (Graduated 2015)2y

    Take lcm of 24, 30 and 40. It will come 120.

    So, A's one day work will be 5 unit, B's 4 unit and C's will be 3 unit.

    C left, 4 days before it means 4 days A and B only worked together i.e

    (A + B)'s 4 day work will be = 4 *(5+4)= 36 unit

    Remaining work = (120 - 36) = 84 unit

    Remaining work will be done by all of them together i.e = 84/12 = 7 days

    Total days = 7 + 4 = 11 days

    Ranjan Karnad

    Former Retired Banker (1972–2000)Author has 5.7K answers and 2.5M answer views1y

    Related

    A can work 24 days, B can work 30 days, and C can work 40 days. They started their work altogether, so C went out before four days. How many days did the work finish?

    Let them finish the work in x days

    x/24 + x/30 + (x-4) /40 = 1

    5x + 4x + 3( x-4) = 120

    12x = 132 x = 11 days ANSWER CHECK

    11/24 +11/30 + 7/40 = (55+ 44 +21) /120 = 120/120 =1

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    A can work 24 days, B can work 30 days, and C can work 40 days. They started their work altogether, so C went out before four days. How many days did the work finish?

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    Mohammed 15 day ago
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