# a bag contains 20 balls marked 1 to 20. one ball is drawn at random. find the probability that it is marked with a number multiple of 5 or 7?

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## A bag contains 20 balls numbered 1 to 20 . One ball is down at random. Find the probability that it is marked with a number which is a multiple of 5 or 7

Click here👆to get an answer to your question ✍️ A bag contains 20 balls numbered 1 to 20 . One ball is down at random. Find the probability that it is marked with a number which is a multiple of 5 or 7

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## A bag contains 20 balls numbered 1 to 20. One ball is down at random. Find the probability that it is marked with a number which is a multiple of 5 or 7

Total NUmbers of Balls =20Medium Open in App Solution Verified by Toppr

Number of balls that are multiple of 5 and 7 are =5,7,10,14,15,20=6

Probability=

Total Number of balls

Number of balls multiple of 5 and 7

P(probability that it is marked with a number which is multiple of 5 or 7)=

20 6

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## A bag contains 20 balls marked 1 to 20. One ball is drawn at random. What is the probability that it is marked with a number multiple of 5 or 7?

Answer (1 of 4): Multiple of 5 ={5,10,15,20) Multiple of7 ={7,14) There is no common element among these. P(multiple of 5). =4/20 P(multiple of 7) = 2/20 Required probability= 4/20. +2/20 =6/20

A bag contains 20 balls marked 1 to 20. One ball is drawn at random. What is the probability that it is marked with a number multiple of 5 or 7?

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Sort Divakaran Anandarao

MSc from Kerala, India (Graduated 1975)Author has 733 answers and 986.7K answer views3y

Multiple of 5 ={5,10,15,20)

Multiple of7 ={7,14)

There is no common element among these.

P(multiple of 5). =4/20

P(multiple of 7) = 2/20

Required probability= 4/20. +2/20 =6/20

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Why are people asking these very basic probability questions ? If this question is beyond your logic, you should really only study junior school Maths.

Anyhow here goes there are (OBVIOUSLY !!! ) 4 multiples of 5 ie 5,10,15,20—and 2 multiples of 7 ie 7,14, which satisfy the question.

Therefore the prob. of selecting one of these is 6/20=3/10=0.3=30% NEXT !

Jaisal Rana 3y

As we have 20 balls the favourable balls numbers would be 5, 7, 10, 14, 15, 20 which is 6 in total. So the provabiltiy for our favourable balls would be favourable balls / total balls that is 6 / 20 = 0.3

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The way the question is worded is slightly ambigious. It asks for 5 or 7 instead of 5 and 7. So using the former we get 2 possibilities whereas the latter would be a 5 answer possibility. With a ratio of 3 to 2 or 20%

Ramaswamy Arunachalam

Former PROFESSOR OF MECHANICAL ENGINEERING at Government College of Technology, Tamil Nadu, India (1983–1997)Author has 5.6K answers and 1.5M answer views1y

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## [Solved] A bag contains 20 balls marked 1 to 20. One ball is drawn at

A bag contains 20 balls marked 1 to 20 So, total number of events = numbers from 1 to 20 = 20 Multiples of 5 or 7 between 1 and 20 are 5, 7, 10, 14, 15 and 2

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## Question

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## A bag contains 20 balls marked 1 to 20. One ball is drawn at random. Find the probability that it is marked with a number multiple of 5 or 7.

310 710 111 23

## Answer (Detailed Solution Below)

Option 1 : 310 Crack with

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## Detailed Solution

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A bag contains 20 balls marked 1 to 20

So, total number of events = numbers from 1 to 20

= 20

Multiples of 5 or 7 between 1 and 20 are 5, 7, 10, 14, 15 and 20

Number of favorable events = number of multiples of 5 or 7 between 1 and 20

= 6 i.e. (5, 7, 10, 14, 15, 20)

∵ Probability of favorable events =

number of favorable eventsnumber of total events

∴ Probability that ball is marked with a number multiple of 5 or 7 =

620=310

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