# a ball is thrown vertically upwards. then is its momentum at the highest point is

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A ball is thrown vertically upwards. What is its momentum at the highest point?

Posted by Neshok Ls 1 year, 10 months ago

CBSE > CLASS 09 > SCIENCE

2 answers

Deepender Sheoran 1 year, 10 months ago

Momentum is zero momentum is that product of mass and velocity of a particular material and when ball is thrown vertically upwards its velocity at highest point is zero P=m.v=m.0=0

0Thank You

Gaurav Seth 1 year, 10 months ago

The momentum is zero.

**Explanation:**

momentum is the product of mass and velocity of a particular material . And when ball is thrown vertically upwards its velocity at highest point is zero . Therefore momentum P = m× v = m × 0 =0.

2Thank You ANSWER

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## A ball is thrown vertically upwards. What is its momentum at the highest point?

At the highest point velocity, v=0 Thus, p=mv=Zero.

Home > English > Class 9 > Physics > Chapter >

Forces And Laws Of Motion

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A ball is thrown vertically up...

A ball is thrown vertically upwards. What is its momentum at the highest point?

Updated On: 27-06-2022

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At the highest point velocity,

v=0 v=0 Thus, p=mv=Zero p=mv=Zero . Answer

Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

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## A stone is thrown vertically upwards. What is the momentum at its highest point?

Answer (1 of 2): Well, when a stone is thrown upwards, it has a velocity which is opposite to the acceleration of gravity. This means that the stone will slow down as it gets higher. So, it's easy to see that the stone will have no velocity at its highest point. Because the stone must stop before...

A stone is thrown vertically upwards. What is the momentum at its highest point?

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Sort Karan Chopra

Studied at Podar International School, Pimpri4y

We know,

Momentum =Mass x velocity

When the stone reaches the highest point,we find that before beginning it's downward motion it stops for a while.

If we measure momentum at that point we find that velocity=0.

Hence, Momentum=0.

Long story short…. Momentum is 0.

Thanks. KC Related questions

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What is the velocity of a stone thrown vertically upwards at its maximum height?

A stone is thrown vertically upward and it returns to the ground after 10 seconds. What is the maximum height reached (take g=9.8ms-2)?

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David Tregurtha

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If a ball is thrown vertically upwards from a moving car, where does it fall?

Well, let us review the evidence:

The take away message here is that the ball will fall back to the exact same point on the car from which it was thrown. This is the basis of Newton’s first law of motion: an object will maintain its current state of motion in the absence of an unbalanced force.

Though a force was applied upwards, there is no change in the forces applied along the horizontal direction, therefore the ball maintains its horizontal velocity relative to the car. For the cases shown, a small drag force due to the air is present, but it is so small it has almost no effect.

Also intermin Aditya Kondapuram

Studied at Parkview Education Centre (Graduated 2019)Author has 152 answers and 128.1K answer views4y

Well, when a stone is thrown upwards, it has a velocity which is opposite to the acceleration of gravity. This means that the stone will slow down as it gets higher. So, it's easy to see that the stone will have no velocity at its highest point. Because the stone must stop before falling down.

Momentum is measured as a product of mass and velocity. If the velocity is zero, the momentum of the object is zero. So even though the stone has mass, it has no momentum at its highest point.

Ayan Biswas

Pursuing MBBS - Medical college and hospital, Kolkata (2023)Author has 61 answers and 213.9K answer views3y

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A 40 N object is released from a height of 10 m. Just before it hits the ground, what will be its K.E.?

So, according to the question, the weight ( not mass ) of the body is 40N.

And, at the height of 10m the body, has gained some potential energy.

Now, when the body falls from the height of 10m, the body looses a part of its potential energy, which is instead converted to kinetic energy, to keep the total energy constant ( provided that we neglect the energy loss due to opposing force by air ).

Now, just before the body hits the ground, the entire potential energy that the body had at the height of 10m will be converted into kinetic energy.

So, potential energy at the height ( h ) of 10m

= m×g×h = we Sponsored by USAFIS

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