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# a block b of mass 5kg is placed on a slab a of mass 20kg

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## A block B of mass 5 kg is placed on a slab A of mass 20 kg which lies on a frictionless surface as shown in the figure. The coefficient of static friction between the block and the slab is 0.4 and that of kinetic friction is 0.2 . If a force F = 25 N acts on B , the acceleration of the slab will be (g = 10 ms^

Click here👆to get an answer to your question ✍️ A block B of mass 5 kg is placed on a slab A of mass 20 kg which lies on a frictionless surface as shown in the figure. The coefficient of static friction between the block and the slab is 0.4 and that of kinetic friction is 0.2 . If a force F = 25 N acts on B , the acceleration of the slab will be (g = 10 ms^-2) .

A block B of mass 5 kg is placed on a slab A of mass 20 kg which lies on a frictionless surface as shown in the figure. The coefficient of static friction between the block and the slab is 0.4 and that of kinetic friction is 0.2. If a force F=25 N acts on B, the acceleration of the slab will be (g=10 ms

Question −2 ).

A0.4 ms

−2

B0.5 ms

−2

C1 ms

−2

D

## Zero

Medium Open in App

Updated on : 2022-09-05

Solution Verified by Toppr

Correct option is B)

Maximum magnitude of static friction force=0.4×5×10m/s

2 =20N

Now the force applied on the block is 25N, while the static frictional force is 20N, this implies that both the slab & box will move at different acceleration rates.

From Newton's second law,

N sb ​ =m block ​ ×g F−f k ​ =m block ​ ×g Also, f k ​ =m slab ​ ×a slab ​ and f k ​ =μ k ​ ×N sb ​ ⇒m slab ​ ×a slab ​ =μ k ​ ×N sb ​ ⇒m slab ​ ×a slab ​ =μ k ​ ×m block ​ ×g ⇒a slab ​ = m slab ​ μ k ​ ×m block ​ ×g ​ = 20 0.2×5×10 ​ =0.5m/s 2

20 4

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## A block B of mass 5kg is placed on a slab A of mass 20kg which lies on a frictionless surface as shown in the figure. The coefficient of static friction between the block and the slab is 0.4 and that of kinetic friction is 0.2. If a force F = 25N acts on B, the acceleration of the slab will be

Get an expert solution to A block B of mass 5kg is placed on a slab A of mass 20kg which lies on a frictionless surface as shown in the figure. The coefficient of static friction between the block and the slab is 0.4 and that of kinetic friction is 0.2. If a force F = 25N acts on B, the acceleration of the slab will be

Two block problem Question

A block B of mass 5kg is placed on a slab A of mass 20kg which lies on a frictionless surface as shown in the figure. The coefficient of static friction between the block and the slab is 0.4 and that of kinetic friction is 0.2. If a force F = 25N acts on B, the acceleration of the slab will be

Easy Solution

Maximum force up to which A and B will move together is given by μ

μ Fmax=μsmg(1+m/M)

where m = mass of B and M = mass of A.

∴Fmax=0.4×5×10(1+5/20)N⇒25N

A and B will move together and their acceleration is

a=2520+5m/s2=1m/s2 Similar Questions

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## A block B of mass 5kg is placed on a slab A of mass 20kg which lies on a frictionless surface as shown in the figure. The coefficient of static friction between the block and the slab is 0.4 and that of kinetic friction is 0.2. If a force F = 25N acts on B, the acceleration of the slab will be:

A block B of mass 5kg is placed on a slab A of mass 20kg which lies on a frictionless surface as shown in the figure. The coefficient of static friction betwe

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A block B of mass 5kg is place...

A block B of mass 5kg is placed on a slab A of mass 20kg which lies on a frictionless surface as shown in the figure. The coefficient of static friction between the block and the slab is 0.4 and that of kinetic friction is 0.2. If a force F = 25N acts on B, the acceleration of the slab will be:

Updated On: 27-06-2022

00 : 30

Text Solution Open Answer in App A 0.4m s −2 0.4ms-2 B 0.5m s −2 0.5ms-2 C 1m s −2 1ms-2 D zero Answer

Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

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A block B of mass 5kg is placed on a slab A of mass 20kg which lies on a frictionless surface as shown in the figure. The coefficient of static friction between the block and the slab is 0.4 and that of kinetic friction is 0.2. If a force F = 25N acts on B, the acceleration of the slab will be:

576405393 300 5.9 K 3:30

A block B of mass 5 kg is placed on a slab A of mass 20 kg which lies on a frictionless surface as shown in the figure. The coefficient of satic friction between the block and the slab is 0.4 and that of kinetic friction is 0.2. If a force F = 25N acts on B, the acceleration of the slab will be

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A block of mass M = 10kg is placed on a slab of mass

M 2 =30kg. M2=30kg.

The slab lies on a friction less horizontal surface as shown in figure. The coefficient of static friction between the block and slab is 4, = 0.4 and that of dynamic friction is My = 0.15. The acceleration with which the slab will move is

(g=10m s −1 ) (g=10ms-1)

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A block of mass M = 10kg is placed on a slab of mass

M 2 =30kg. M2=30kg.

The slab lies on a friction less horizontal surface as shown in figure. The coefficient of static friction between the block and slab is 4, = 0.4 and that of dynamic friction is My = 0.15. The acceleration with which the slab will move is

(g=10m s −1 ) (g=10ms-1)

641279435 0 600 4:18 चित्रानुसार क्षैतिज

M द्रव्यमान के एक स्लेब पर m द्रव्यमान का एक ब्लॉक रखा गया है। ब्लॉक और स्लेब के मध्य स्थैतिज घर्षण गुणांक

μ μ है।

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A 40kg slab rests on a frictionless floor as shown in the figure. A 10kg block rests on the top of the slab. The static coefficient of friction between the block and slab is

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while the kinetic friction is

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. The 10kg block is acted upon by a horizontal force 100N. if

, the resulting acceleration of the slab will be.

g=9.8m/ s 2 g=9.8m/s2

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Mohammed 8 day ago

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