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    a block of mass 50 kg slides down an incline of inclination 30° and length 10 m. find the work done by the force of gravity.

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    A block of mass 5.0 kg slides down an incline of inclination 30^0 and length 10 m. Find the work done by the force of gravity in joules?

    Click here👆to get an answer to your question ✍️ A block of mass 5.0 kg slides down an incline of inclination 30^0 and length 10 m. Find the work done by the force of gravity in joules?

    A block of mass 5.0 kg slides down an incline of inclination 30

    Question 0

    and length 10 m. Find the work done by the force of gravity in joules?

    A

    245

    B

    300

    C

    350

    D

    400

    Medium Open in App

    Updated on : 2022-09-05

    Solution Verified by Toppr

    Correct option is A)

    We have, the mass of the block, M=5kg

    Angle of inclination isθ=30

    0

    The gravitational force acting the block, F=mg

    Work done by the force of gravity depends on the height of the object, not on the path length covered by the object.

    Height of the object, H=10×sin30

    0 =10× 2 1 ​ =5m Since,

    Work was done by the force of gravity,

    W=mgh=5×9.8×5=245J

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    A block of mass 5.0 kg slides down an incline of inclination 30^0 and length 10 m. The work done by the force of gravity (in joule) is

    M=5 kg, theta=30^0,S=10m, F=mg so, workdone by the force of gravity, omega=mgh=5xx9.8xx5 =245J

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    A block of mass 5.0 kg slides ...

    A block of mass 5.0 kg slides down an incline of inclination

    30 0 300

    and length 10 m. The work done by the force of gravity (in joule) is

    Updated On: 27-06-2022

    00 : 30

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    Text Solution Open Answer in App Answer

    The correct Answer is B::D

    Solution M=5kg,θ= 30 0 ,S=10m,F=mg

    M=5kg,θ=300,S=10m,F=mg

    so, workdone by the force of gravity,

    ω=mgh=5×9.8×5 ω=mgh=5×9.8×5 =245J =245J

    Answer

    Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

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    A Block of Mass 5.0 Kg Slides Down an Incline of Inclination 30° and Length 10 M. Find the Work Done by the Force of Gravity.

    A Block of Mass 5.0 Kg Slides Down an Incline of Inclination 30° and Length 10 M. Find the Work Done by the Force of Gravity.

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    A block of mass 5.0 kg slides down an incline of inclination 30° and length 10 m. Find the work done by the force of gravity.

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    SOLUTION

    Mass of the block, M = 5 kg

    Mass of the block, M = 5 kg

    Angle of inclination

    Angle of inclination ,θ=30∘

    Gravitational force acting on the block,

    F=mg

    Work done by the force of gravity depends only on the height of the object, not on the path length covered by the object.

    Height of the object , h

    Height of the object , h =10×sin⁡30∘

    =10×12=5m

    Work done by the force of gravity, w = mgh

    ∴ Work done by the force of gravity, w = mgh

    =5×9.8×5=245J

    Concept: Work Done by a Constant Force and a Variable Force

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    Chapter 8: Work and Energy - Exercise [Page 132]

    Q 4 Q 3 Q 5

    APPEARS IN

    HC Verma Class 11, Class 12 Concepts of Physics Vol. 1

    Chapter 8 Work and Energy

    Exercise | Q 4 | Page 132

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