# a block of mass 50 kg slides down an incline of inclination 30° and length 10 m. find the work done by the force of gravity.

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## A block of mass 5.0 kg slides down an incline of inclination 30^0 and length 10 m. Find the work done by the force of gravity in joules?

Click here👆to get an answer to your question ✍️ A block of mass 5.0 kg slides down an incline of inclination 30^0 and length 10 m. Find the work done by the force of gravity in joules?

A block of mass 5.0 kg slides down an incline of inclination 30Question 0

and length 10 m. Find the work done by the force of gravity in joules?

**A**

## 245

**B**

## 300

**C**

## 350

**D**

## 400

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Updated on : 2022-09-05

Solution Verified by Toppr

Correct option is A)

We have, the mass of the block, M=5kg

Angle of inclination isθ=30

0

The gravitational force acting the block, F=mg

Work done by the force of gravity depends on the height of the object, not on the path length covered by the object.

Height of the object, H=10×sin30

0 =10× 2 1 =5m Since,

Work was done by the force of gravity,

W=mgh=5×9.8×5=245J

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## A block of mass 5.0 kg slides down an incline of inclination 30^0 and length 10 m. The work done by the force of gravity (in joule) is

M=5 kg, theta=30^0,S=10m, F=mg so, workdone by the force of gravity, omega=mgh=5xx9.8xx5 =245J

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A block of mass 5.0 kg slides ...

A block of mass 5.0 kg slides down an incline of inclination

30 0 300

and length 10 m. The work done by the force of gravity (in joule) is

Updated On: 27-06-2022

00 : 30

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Text Solution Open Answer in App Answer

The correct Answer is B::D

Solution M=5kg,θ= 30 0 ,S=10m,F=mg

M=5kg,θ=300,S=10m,F=mg

so, workdone by the force of gravity,

ω=mgh=5×9.8×5 ω=mgh=5×9.8×5 =245J =245J

Answer

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## A Block of Mass 5.0 Kg Slides Down an Incline of Inclination 30° and Length 10 M. Find the Work Done by the Force of Gravity.

A Block of Mass 5.0 Kg Slides Down an Incline of Inclination 30° and Length 10 M. Find the Work Done by the Force of Gravity.

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A block of mass 5.0 kg slides down an incline of inclination 30° and length 10 m. Find the work done by the force of gravity.

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### SOLUTION

Mass of the block, M = 5 kg

Mass of the block, M = 5 kg

Angle of inclination

Angle of inclination ,θ=30∘

Gravitational force acting on the block,

F=mg

Work done by the force of gravity depends only on the height of the object, not on the path length covered by the object.

Height of the object , h

Height of the object , h =10×sin30∘

=10×12=5m

Work done by the force of gravity, w = mgh

∴ Work done by the force of gravity, w = mgh

=5×9.8×5=245J

Concept: Work Done by a Constant Force and a Variable Force

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Chapter 8: Work and Energy - Exercise [Page 132]

Q 4 Q 3 Q 5

### APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 1

Chapter 8 Work and Energy

Exercise | Q 4 | Page 132

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