a body dropped from top of tower covers a distance 7x
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A body dropped from the top of a tower covers a distance 7 x in the last second of its journey where X is the distance covered in first second. How much time does it take to reach the ground Take g =10 m / s 2 ? A. 3 sB. 4 sC. 5 sD. 6 s
A body dropped from the top of a tower covers a distance 7 x in the last second of its journey where X is the distance covered in first second. How much time does it take to reach the ground Take g =10 m / s 2 ? A. 3 sB. 4 sC. 5 sD. 6 s
Byju's Answer Standard XII Physics Dropping Objects A body droppe... Question
A body dropped from the top of a tower covers a distance
7 x
in the last second of its journey where
x
is the distance covered in first second. How much time does it take to reach the ground (Take
g = 10 m / s 2 )? A 3 s B 4 s C 5 s D 6 s Open in App Solution
The correct option is B
4 s
In first second, distance travelled
x = 1 2 × g × t 2 = 5 m (for g = 10 m / s 2 )
Distance travelled in last second
= 7 x = 35 m We know that S n = u + 1 2 a ( 2 n − 1 ) or 35 = 0 + 10 2 × ( 2 n − 1 ) ⇒ n = 4 ∴ t = 4 s Suggest Corrections 26
SIMILAR QUESTIONS
Q. A body dropped from the top of the tower covers a distance7 x
in the last second of its journey, where
x
is the distance covered in first second. How much time does it take to reach the ground ? (in seconds)
Q. A body dropped from the top of a tower covers a distance7 x
in the last second of its journey, where
x
is the distance covered in the first second. How much time does it take to reach the ground?
Q. A body dropped from the top of a tower covers the distance7 x
in the last second of its journey, where
x
is the distance covered in
1 st
sec. How much time does it take to reach the ground ?
Q. A body dropped from the top of a tower covers a distance7 h
in the last second of its journey where h is the distance covered in the first second. How much time does it take to reach the ground?
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Standard XII Physics
A body dropped from the top of the tower covers a distance 7x in the last second of its journey, where x is the distance covered in first second. How much time does it takes to reach the ground?
Click here👆to get an answer to your question ✍️ A body dropped from the top of the tower covers a distance 7x in the last second of its journey, where x is the distance covered in first second. How much time does it takes to reach the ground?
Question
A body dropped from the top of the tower covers a distance 7x in the last second of its journey, where x is the distance covered in first second. How much time does it takes to reach the ground?
A3 s
B4 s
C5 s
D6 s
Medium Open in App
Updated on : 2022-09-05
Solution Verified by Toppr
Correct option is B)
∵d=2 1 gt 2
Therefore distance covered in 1
st second is = 2 1 g
Let it fall for n sec
∴7x=0+ 2 g (2n−1) ⇒7× 2 g = 2 g (2n−1)⇒2n=8⇒n=4 s Video Explanation
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A bolldropped from the top of a tower covers a distance 7x in the last second of its journey, where x is the distance coverd int the first second. How much time does it take to reach to ground?.
Given 7x=(g)/(2) (2n-1) and x(1)/(2)g(1)^(2). Solving these two equations, we get n=4 s.
A bolldropped from the top of a tower covers a distance
7 x
in the last second of its journey, where
x
is the distance coverd int the first second. How much time does it take to reach to ground?.
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Updated On: 27-06-2022
Text Solution A 3 s B 4 s C 5 s D 6 s Answer
The correct Answer is B
Solution Given 7 x = g 2 ( 2 n − 1 ) and x 1 2 g ( 1 ) 2 .
Solving these two equations, we get
n = 4 s . Answer
Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.
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Guys, does anyone know the answer?