if you want to remove an article from website contact us from top.

    a body is dropped from a height h when loss in its potential energy

    Mohammed

    Guys, does anyone know the answer?

    get a body is dropped from a height h when loss in its potential energy from screen.

    A body is dropped from a height h . When loss in its potential energy is U then its velocity is v . The mass of the body is:

    Click here👆to get an answer to your question ✍️ A body is dropped from a height h . When loss in its potential energy is U then its velocity is v . The mass of the body is:

    Question

    A body is dropped from a height h. When loss in its potential energy is U then its velocity is v. The mass of the body is:

    A

    2v U 2 ​

    B

    U 2v ​

    C

    U 2 2v ​

    D

    v 2 2U ​ Medium Open in App

    Updated on : 2022-09-05

    Solution Verified by Toppr

    Correct option is D)

    loss in PE=gain in KE

    U= 2 1 ​ mv 2 m= v 2 2U ​

    Was this answer helpful?

    53 9

    स्रोत : www.toppr.com

    " A body is dropped form a height h.When loss in its potential energy is "'U'," its velocity is "V" .The mass of the body is "

    2U/V^2" A body is dropped form a height h.When loss in its potential energy is "'U'," its velocity is "V" .The mass of the body is "

    Home > English > Class 12 > Physics > Chapter > Work And Energy >

    " A body is dropped form a hei...

    " A body is dropped form a height h.When loss in its potential energy is "'U'," its velocity is "V" .The mass of the body is "

    Updated On: 27-06-2022

    00 : 010

    UPLOAD PHOTO AND GET THE ANSWER NOW!

    Text Solution Open Answer in App Solution 2U/V^2

    Answer

    Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

    Related Videos

    648117209 0 5.4 K

    A body is dropped from a certain height. When it loses U amount of its potential energy it acquires a velocity v. The mass of the body is

    644155379 39 5.7 K 1:44

    एक पिंड को पृथ्वी की सतह के ऊपर एक निश्चित ऊंचाई से गिराया जाता हैI जब यह अपनी स्थितिज ऊर्जा की U मात्रा खो देता है, तो यह एक वेग v प्राप्त करता हैI पिंड का द्रव्यमान कितना है?

    642730114 0 6.1 K

    A body is dropped from a height of 16 m. The body strikes the ground and losses 25% of its velocity. The body rebounds to a height of

    642853880 9 2.0 K

    A body is dropped from a height of 16m. The body strikes the ground and losses 25% of its velocity. The body rebounds to a height of

    642727727 0 4.3 K

    A body is dropped from a height of 16 m. The body strikes the ground and losses 25% of its velocity. The body rebounds to a height of

    612648072 0 6.5 K

    A body is dropped from a height of 16 m. The body strikes the ground and losses 25% of its velocity. The body rebounds to a height of

    Show More Comments

    Add a public comment...

    Follow Us:

    Popular Chapters by Class:

    Class 6 Algebra

    Basic Geometrical Ideas

    Data Handling Decimals Fractions Class 7

    Algebraic Expressions

    Comparing Quantities

    Congruence of Triangles

    Data Handling

    Exponents and Powers

    Class 8

    Algebraic Expressions and Identities

    Comparing Quantities

    Cubes and Cube Roots

    Data Handling

    Direct and Inverse Proportions

    Class 9

    Areas of Parallelograms and Triangles

    Circles Coordinate Geometry Herons Formula

    Introduction to Euclids Geometry

    Class 10

    Areas Related to Circles

    Arithmetic Progressions

    Circles Coordinate Geometry

    Introduction to Trigonometry

    Class 11 Binomial Theorem

    Complex Numbers and Quadratic Equations

    Conic Sections

    Introduction to Three Dimensional Geometry

    Limits and Derivatives

    Class 12

    Application of Derivatives

    Application of Integrals

    Continuity and Differentiability

    Determinants

    Differential Equations

    Privacy Policy

    Terms And Conditions

    Disclosure Policy Contact Us

    स्रोत : www.doubtnut.com

    A body is dropped from a height $h$. When the loss in its potential energy is $U$ then its velocity is $v$. The mass of the body is:A) $\\dfrac{{{U^2}}}{{2v}}$B) $\\dfrac{{2v}}{U}$C) $\\dfrac{{2v}}{{{U^2}}}$D) $\\dfrac{{2U}}{{{v^2}}}$

    A body is dropped from a height $h$. When the loss in its potential energy is $U$ then its velocity is $v$. The mass of the body is:A) $\\dfrac{{{U^2}}}{{2v}}$B) $\\dfrac{{2v}}{U}$C) $\\dfrac{{2v}}{{{U^2}}}$D) $\\dfrac{{2U}}{{{v^2}}}$. Ans: Hint The ...

    A body is dropped from a height

    h h

    . When the loss in its potential energy is

    U U

    then its velocity is

    v v

    . The mass of the body is:

    A) U 2 2v U22v B) 2v U 2vU C) 2v U 2 2vU2 D) 2U v 2 2Uv2 Answer Verified 222k+ views

    Hint The law of conservation of energy relates the body’s kinetic and potential energy. When the body is at a height

    h h

    , it will only have potential energy and when it's falling and has lost potential energy

    U U

    it will have some kinetic energy. We will use this relation to equate the loss in potential energy of the body with the gain in kinetic energy of the body as it accelerates downwards.

    In this solution, we will use the following formula

    Kinetic energy of a body:

    K= 1 2 m v 2 K=12mv2 where m m is its mass and v v is its velocity.

    Complete step by step answer

    The law of conservation of energy tells us that energy cannot be created or destroyed but it can only be converted from one form to the other.

    We’ve been given that a body is dropped from a height

    h h

    . When the loss in its potential energy is

    U U

    , the amount of energy will have converted into kinetic energy. We know that the kinetic energy of a body travelling with velocity

    v v and mass m m

    can be calculated as:

    ⇒K= 1 2 m v 2 ⇒K=12mv2

    So, the loss in the potential energy

    U U

    is converted into kinetic energy so we can write

    ⇒U= 1 2 m v 2 ⇒U=12mv2

    Dividing both sides by

    v 2 /2 v2/2 , we get m= 2U v 2 m=2Uv2

    which corresponds to option (D).

    Note

    Here we have assumed that there is no air resistance however in an actual scenario, air resistance will decrease the kinetic energy of the body due to frictional losses. We can also select the correct option since only option (D) has the dimensions of mass while the rest of the options have different dimensions which are not the dimensions of mass.

    स्रोत : www.vedantu.com

    Do you want to see answer or more ?
    Mohammed 7 day ago
    4

    Guys, does anyone know the answer?

    Click For Answer