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    a body of mass 2kg moving on a horizontal surface with an initial velocity of 4m/s

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    A body of mass 2kg moving on a horizontal surface with an initial velocity of 4ms ^

    Click here👆to get an answer to your question ✍️ A body of mass 2kg moving on a horizontal surface with an initial velocity of 4ms ^ - ^1 comes to rest in 2 seconds. If one wants to keep the body moving on the same surface with the velocity of 4 ms ^ - ^1 , the force required is :

    A body of mass 2kg moving on a horizontal surface with an initial velocity of 4ms

    Question − 1

    comes to rest in 2 seconds. If one wants to keep the body moving on the same surface with the velocity of 4 ms

    − 1

    , the force required is :

    A

    Zero

    B

    4 N

    C

    8 N

    D

    16 N

    Hard Open in App

    Updated on : 2022-09-05

    Solution Verified by Toppr

    Correct option is B)

    From above figure

    A→B

    u = 4m/s             v=0            t=2sec            a=?

    v=u+at 0=4+a(2) a=−2m/s 2 so, force = ma =2×2=4N

    Hence (B) is the correct answer

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    स्रोत : www.toppr.com

    A body of mass 2 kg moving on a horizontal surface with an initial velocity of 4 m / sec comes to rest after 2 sec. If one wants to keep this body moving on the same surface with a velocity of 4 m / sec, the force required isA. 2 NB. 4 NC. 8 ND. Zero

    A body of mass 2 kg moving on a horizontal surface with an initial velocity of 4 m / sec comes to rest after 2 sec. If one wants to keep this body moving on the same surface with a velocity of 4 m / sec, the force required isA. 2 NB. 4 NC. 8 ND. Zero

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    A body of mass 2 kg moving on a horizontal surface with an initial velocity of 4 m / sec comes to rest after 2 sec. If one wants to keep this body moving on the same surface with a velocity of 4 m / sec, the force required isA. 2 NB. 4 NC. 8 ND. Zero

    Question

    A body of mass 2 kg moving on a horizontal surface with an initial velocity of 4 m/sec comes to rest after 2 sec. If one wants to keep this body moving on the same surface with a velocity of 4 m/sec, the force required is

    A 8 N B 4 N C Zero D 2 N Open in App Solution

    The correct option is B

    4 N

    u=4 m/s, v=0, t= 2sec

    v=u+at ⇒ 0=4+2a ⇒ a = − 2 m / s 2 ∴

    Retarding force = ma =2

    × 2= 4 N

    This force opposes the motion. If the same amount of force is applied in forward direction, then the body will move with constant velocity.

    Suggest Corrections 19

    SIMILAR QUESTIONS

    Q. A body of mass

    2 k g

    moving on horizontal surface with an initial velocity of

    4 m / s e c comes to rest after 2 s e c

    . If one wants to keep this body moving on the same surface with a velocity of

    4 m / s e c

    , then the force required is:-

    Q. A body of mass

    2 k g

    moving on a horizontal surface with an initial velocity of

    4 m / s comes to rest after 2 s

    . If one wants to keep this body moving on the same surface with a velocity of

    4 m / s

    , the force required is:

    Q. A body of mass

    2 k g

    moving on a horizontal surface with an initial velocity of

    4 m s − 1

    , comes to rest after

    2 s

    . If one wants to keep this body moving on the same surface with a velocity of

    4 m s − 1

    , the force required is:

    Q. A body of mass 2 kg moving on a horizontal surface with an initial velocity of 4 m/s comes to rest after 2 s. If one wants to keep this body moving on the same surface with a velocity of 4 m/s, the force required is:Q. A body of mass

    5 k g

    moving on a horizontal surface with a velocity of

    10 m s − 1 comes to rest in 2 s

    . The force required to make this body move with a velocity of

    10 m s − 1

    on the same surface is:

    View More

    स्रोत : byjus.com

    A body of mass 2kg moving on a horizontal surface with an initial velocity of 4 ms^(

    F=2xx(4)/(2)=4NA body of mass 2kg moving on a horizontal surface with an initial velocity of 4 ms^(-1) comes to rest after 2 second. If one wants to keep this body moving on the same surface with a velocity of 4 ms^(-1) the force required is

    Home > English > Class 12 > Physics > Chapter >

    Newtons Laws Of Motion

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    A body of mass 2kg moving on a...

    A body of mass 2kg 2kg

    moving on a horizontal surface with an initial velocity of

    4m s −1 4ms-1 comes to rest after 2 2

    second. If one wants to keep this body moving on the same surface with a velocity of

    4m s −1 4ms-1

    the force required is

    Updated On: 27-06-2022

    00 : 30

    UPLOAD PHOTO AND GET THE ANSWER NOW!

    Text Solution Open Answer in App A 8N B 4N C Zero D 2 N Answer

    The correct Answer is B

    Solution F=2× 4 2 =4N F=2×42=4N

    Answer

    Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

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    स्रोत : www.doubtnut.com

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    Mohammed 6 day ago
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