# a body of mass m starting from rest is acted on by a force producing a velocity

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## A body of mass 'm' starting from rest is acted upon by a force producing a velocity v=k√s.,where 's' is dislpacement.the work done by the force in the first 't'seconds is. a) m^2k^2t^2/8. B) m^2k^2t^2/4. C)mk^2t^2/8. D)m^2k^2t/4.?

Dec 25,2022 - A body of mass 'm' starting from rest is acted upon by a force producing a velocity v=k√s.,where 's' is dislpacement.the work done by the force in the first 't'seconds is. a) m^2k^2t^2/8. B) m^2k^2t^2/4. C)mk^2t^2/8. D)m^2k^2t/4.? | EduRev NEET Question is disucussed on EduRev Study Group by 623 NEET Students.

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A body of mass 'm' starting from rest is acted upon by a force producing a velocity v=k√s.,where 's' is dislpacement.the work done by the force in the first 't'seconds is. a) m^2k^2t^2/8. B) m^2k^2t^2/4. C)mk^2t^2/8. D)m^2k^2t/4.?

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Parvez Ahamad Nov 23, 2018 Related

A body of mass 'm' starting from rest is acted upon by a force producing a velocity v=k√s.,where 's' is dislpacement.the work done by the force in the first 't'seconds is. a) m^2k^2t^2/8. B) m^2k^2t^2/4. C)mk^2t^2/8. D)m^2k^2t/4.?

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Explore Courses Shreya Singh Nov 23, 2018 V=k√s. v^2=k^2×s.

(we know , v^2-u^2=2as.......v^2=2as..)

2as=k^2×s. a=k^2/2..

w=1/2m(v^2final-v^2initial).

from,v=at...and on substituting

a=k^2/2...

w=1/2×m((at)^2-(0)^2).

w=1/2m( k^2/2×t)^2..

w=mk^2t^2/8. Upvote | 3 Reply Share with a friend Answer this doubt

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A body of mass 'm' starting from rest is acted upon by a force producing a velocity v=k√s.,where 's' is dislpacement.the work done by the force in the first 't'seconds is. a) m^2k^2t^2/8. B) m^2k^2t^2/4. C)mk^2t^2/8. D)m^2k^2t/4.? for NEET 2022 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A body of mass 'm' starting from rest is acted upon by a force producing a velocity v=k√s.,where 's' is dislpacement.the work done by the force in the first 't'seconds is. a) m^2k^2t^2/8. B) m^2k^2t^2/4. C)mk^2t^2/8. D)m^2k^2t/4.? covers all topics & solutions for NEET 2022 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass 'm' starting from rest is acted upon by a force producing a velocity v=k√s.,where 's' is dislpacement.the work done by the force in the first 't'seconds is. a) m^2k^2t^2/8. B) m^2k^2t^2/4. C)mk^2t^2/8. D)m^2k^2t/4.?.

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## A body of mass 'm' starting from is acted on by a force producing a velocity v = √(k × s) where k is a constant and s is displacement .The work done by the force in the first 't' seconds is:

Click here👆to get an answer to your question ✍️ A body of mass m starting from rest is acted on by a force producing a velocity v = vk x s where k is a constant and s is displacement. The work done by the force in the first t seconds is: A m²kt2 8 mkat YOUR ANSWER YOU MISSED makat

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## A body of mass m starting from rest is acted on by a force producing a velocity v = vk x s where k is a constant and s is displacement. The work done by the force in the first t seconds is: A m²kt2 8 mkat YOUR ANSWER YOU MISSED makat

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## SOLVED: A body of mass m starting from rest is acted on by a force producing a velocity v = √(k × s) where k is a constant and s is displacement. The work done by the force in the first t seconds is: A. m^2k^2t^28 B. mk^2t^24 C. m k^2t^28 D. m^2k^2t4

VIDEO ANSWER: We have been told that there is an object and the mass of it is, and that a force asked increases the speed of it from 0m/s. Two, we meet up again. The object increases its speed from rest to meter per second The object travels half a D

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