# a bullet of mass 25 g moving with a velocity of 200 cm/s is stopped within 5 cm of the target. the average resistance offered by the target is

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## A bullet of mass 25g moving with velocity 200m s^

Click here👆to get an answer to your question ✍️ ELITE 12. A bullet of mass 25g moving with a velocity or 200m/s is stopped within 5 cm of target, the average resistance offered by target is (1) 10 KN (2) 20 KN (3) 30 KN (4) 40 KN

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## ELITE 12. A bullet of mass 25g moving with a velocity or 200m/s is stopped within 5 cm of target, the average resistance offered by target is (1) 10 KN (2) 20 KN (3) 30 KN (4) 40 KN

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## A ball of mass 25 g, moving with a velocity of 2 ms^(

A ball of mass 25 g, moving with a velocity of 2 ms^(-1) is stopped within 5 cm. The average resistance offered to the ball is

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A ball of mass 25 g, moving wi...

A ball of mass 25 g, moving with a velocity of

2m s −1 2ms-1

is stopped within 5 cm. The average resistance offered to the ball is

Updated On: 27-06-2022

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## A bullet of mass 50 g is moving with a velocity of 500 m/s^ 1. It penetrates 10 cm into a still target and comes to rest. Calculate: Physics Q&A

A bullet of mass 50 g is moving with a velocity of 500 m/s^ 1. It penetrates 10 cm into a still target and comes to rest. Calculate: (a) the kinetic energy possessed by the bullet, and (b) the average retarding force offered by the target. Get the answer to this question and access a vast question bank that is tailored for students.

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A bullet of mass 50 g is moving with a velocity of 500 m/s^ 1. It penetrates 10 cm into a still target and comes to rest. Calculate: Physics Q&A

Question A bullet of mass 50g

is moving with a velocity of

500m/s . It penetrates 10cm

into a still target and comes to rest. Calculate:

the kinetic energy possessed by the bullet, and

the average retarding force offered by the target

Open in App Solution

**Step 1: Given**

Mass of the bullet, m=50g=0.05kg

Velocity of the bullet,

v=500 m/s

Distance penetrated by the bullet,

s=10cm=0.1m

**Step 2: Calculate the kinetic energy**

KE=12mv2 =12×0.05×(500)2 =6250 kg-m2/s2 =6250 J

**Step 3: Determine the average retarding force**

Work done is given by,

W=Force×Distance

In this situation, Work done = Resistance force x distance

W=KE=6250=F×0.1 ⇒F=62500 N

**Therefore,**

**the kinetic energy possessed by the bullet is**

6250 N

**the average retarding force offered by the target is**

62500 N Suggest Corrections 2

SIMILAR QUESTIONS

**Q.**A bullet of mass 50g is moving with a velocity of 500m/s.It penetrates a 10cm into a still target and comes to rest. Calculate the kinetic energy possessed by the bullet and the retarding force offered by the target

**Q.**A bullet of mass

50 g

is moving with a velocity of

500 m s − 1 . It penetrates 10 c m

into a still target and comes to rest. Calculate the average retarding force offered by the target.

**Q.**A bullet of mass

50 g

is moving with a velocity of

500 m s − 1 . It penetrates 10 c m

into a still target and comes to rest. Calculate the loss in kinetic energy of the bullet.

**Q.**

A bullet of mass 20g travelling with a velocity of 350ms-1 , comes to rest after penetrating 40cm in a still target. Find the resistive force offered by the still target and the retardation caused by it.

**Q.**A bullet of mass

10 g

strikes a fixed target and penetrates

8 c m

into it before coming to rest. if the average force of resistance offered by the target is

100 N

, with what velocity does it strike?

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