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    a bullet of mass 25 g moving with a velocity of 200 cm/s is stopped within 5 cm of the target. the average resistance offered by the target is

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    Click here👆to get an answer to your question ✍️ ELITE 12. A bullet of mass 25g moving with a velocity or 200m/s is stopped within 5 cm of target, the average resistance offered by target is (1) 10 KN (2) 20 KN (3) 30 KN (4) 40 KN

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    ELITE 12. A bullet of mass 25g moving with a velocity or 200m/s is stopped within 5 cm of target, the average resistance offered by target is (1) 10 KN (2) 20 KN (3) 30 KN (4) 40 KN

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    A ball of mass 25 g, moving with a velocity of 2 ms^(

    A ball of mass 25 g, moving with a velocity of 2 ms^(-1) is stopped within 5 cm. The average resistance offered to the ball is

    Home > English > Class 11 > Physics > Chapter > Laws Of Motion >

    A ball of mass 25 g, moving wi...

    A ball of mass 25 g, moving with a velocity of

    2m s −1 2ms-1

    is stopped within 5 cm. The average resistance offered to the ball is

    Updated On: 27-06-2022

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    647716085 48 8.1 K 2:42

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    643981655 0 4.3 K 2:07

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    A bullet of mass 50 g is moving with a velocity of 500 m/s^ 1. It penetrates 10 cm into a still target and comes to rest. Calculate: Physics Q&A

    A bullet of mass 50 g is moving with a velocity of 500 m/s^ 1. It penetrates 10 cm into a still target and comes to rest. Calculate: (a) the kinetic energy possessed by the bullet, and (b) the average retarding force offered by the target. Get the answer to this question and access a vast question bank that is tailored for students.

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    A bullet of mass 50 g is moving with a velocity of 500 m/s^ 1. It penetrates 10 cm into a still target and comes to rest. Calculate: Physics Q&A

    Question A bullet of mass 50g

    is moving with a velocity of

    500m/s . It penetrates 10cm

    into a still target and comes to rest. Calculate:

    the kinetic energy possessed by the bullet, and

    the average retarding force offered by the target

    Open in App Solution

    Step 1: Given

    Mass of the bullet, m=50g=0.05kg

    Velocity of the bullet,

    v=500 m/s

    Distance penetrated by the bullet,

    s=10cm=0.1m

    Step 2: Calculate the kinetic energy

    KE=12mv2 =12×0.05×(500)2 =6250 kg-m2/s2 =6250 J

    Step 3: Determine the average retarding force

    Work done is given by,

    W=Force×Distance

    In this situation, Work done = Resistance force x distance

    W=KE=6250=F×0.1 ⇒F=62500 N

    Therefore,the kinetic energy possessed by the bullet is

    6250 N

    the average retarding force offered by the target is

    62500 N Suggest Corrections 2

    SIMILAR QUESTIONS

    Q. A bullet of mass 50g is moving with a velocity of 500m/s.It penetrates a 10cm into a still target and comes to rest. Calculate the kinetic energy possessed by the bullet and the retarding force offered by the targetQ. A bullet of mass

    50 g

    is moving with a velocity of

    500 m s − 1 . It penetrates 10 c m

    into a still target and comes to rest. Calculate the average retarding force offered by the target.

    Q. A bullet of mass

    50 g

    is moving with a velocity of

    500 m s − 1 . It penetrates 10 c m

    into a still target and comes to rest. Calculate the loss in kinetic energy of the bullet.

    Q.

    A bullet of mass 20g travelling with a velocity of 350ms-1 , comes to rest after penetrating 40cm in a still target. Find the resistive force offered by the still target and the retardation caused by it.

    Q. A bullet of mass

    10 g

    strikes a fixed target and penetrates

    8 c m

    into it before coming to rest. if the average force of resistance offered by the target is

    100 N

    , with what velocity does it strike?

    View More

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