# a car travels 3 km in 10 minutes to reach the destination. on the return journey, the car travels the same distance in 15 minutes. what is the average speed of the car in its entire journey?

### Mohammed

Guys, does anyone know the answer?

get a car travels 3 km in 10 minutes to reach the destination. on the return journey, the car travels the same distance in 15 minutes. what is the average speed of the car in its entire journey? from screen.

## A car travels the first one third of a certain distance with a speed of 10 km/hr, the next one third with a speed of 20 km/hr and the last one third distance with a speed of 60 km/hr The average speed of the car for the whole journey is

Click here👆to get an answer to your question ✍️ A car travels the first one third of a certain distance with a speed of 10 km/hr, the next one third with a speed of 20 km/hr and the last one third distance with a speed of 60 km/hr The average speed of the car for the whole journey is

Question

## A car travels the first one third of a certain distance with a speed of 10 km/hr, the next one third with a speed of 20 km/hr and the last one third distance with a speed of 60 km/hr The average speed of the car for the whole journey is

**A**

## 18 km/hr

**B**

## 24 km/hr

**C**

## 30 km/hr

**D**

## 36 km/hr

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Updated on : 2022-09-05

Solution Verified by Toppr

Correct option is A)

Let the total distance travelled be x km Then total time taken =10 x/3 + 20 x/3 + 60 x/3 = 30 x + 60 x + 180 x = 180 6x+3x+x = 180 10x = 18 x

hrs Then average speed = =

Totaltimetaken

Totaldistancetravelled

= x/18 x km/hr = 18 km/hr

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## A car travels a certain distance at 24 km/h and comes back at 36 km/h. What is the average speed of the car for the total journey.?

Answer (1 of 9): It is the harmonic mean of 24 and 36 gives the avg speed in the total journey and hence it is 2/{(1/24)+(1/36)}=144/5=28.8 kmph. Ans..

A car travels a certain distance at 24 km/h and comes back at 36 km/h. What is the average speed of the car for the total journey.?

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Sort Jayanth Mankavil

Studied at Little Flower English Medium School, Nilambur3y

Here is a simple equation

V average = 2V1V2/(V1+V2)

Here V1 = 24km/hr V2= 36km/hr

Substitute these values in the equation, you will be getting 28.8km/hr as the answer.

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A car travels a distance of 100km at the speed of 25 km/h. It covers the next 25 km of its journey at the speed of 5 km/h and the last 50 km of its journey at the speed of 25 km/h. What is the average speed of the car?

Rahul Rai

B. Tech from G.B Pant University of Technology, Pantnagar, Uttarakhand (Graduated 2018)3y

Ans is 28.8 km/h.

Assume the distance for one side is ‘s’. Therefore the total time taken for forward and backward journey is (s/24)+(s/36) which equals 5s/72.

Av speed = total distance /total time

Here total distance is 2s (forward and backward)

So, av speed= 2s/(5s/72) which equals 28.8 km/hr.

Pandita Rahul

Lived in Anantnag, Jammu and Kashmir, IndiaAuthor has 231 answers and 514.7K answer views3y

Use formula 2xy/x+y, where x and y speeds

Avg speed= 2×24×36/24+36=48×36/60=28.8 km/hr

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Abhilash Kumar

Design Engineer (2018–present)3y

where s s

equals the average speed,

a a

equals the speed for the first half of the distance, and

b b

equals the speed for the second half of the distance

Therefore, s=(2*24*36)/(24+36)

s=28.8 Kph

(Source:How to Calculate Average Speed

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Let the distance be x, the time taken for going =x/24 and the time taken for coming back is x/36. Therefore the total time taken is x/24+x/36= 5x/72. In this time, the car covered 2x distance (going and coming back). Therefore average speed = 2x/(5x/72)=144/5= 28.8km/h

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Former Retired, former Engineering Company directorAuthor has 984 answers and 259.1K answer views4y

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HsBadarinath

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Factors of 24 = 2x2x2x3 36 = 2x2x3x3

LCM = 2x2x2x3x3 = 72

Suppose the journey is 72 km long.

The car cover the outward journey in 72/24in 3 hours.

The return journey takes 72/36 = 2 hours.

So the average speed = (total distance covered)/(total time of travel)

= (72+72)/(3+2) = 144/5

= 28.2 km/hr. Answer.

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## [Solved] A car covers the first 78 km. of the journey in 90 minutes a

Given: Total Distance cover = 78 + 50 = 128 km Total time taken = 90 + 70 = 160 minutes = \(160\over 60\) hours Formula use: Average speed = Total

Home Quantitative Aptitude Speed Time and Distance Average Speed

## Question

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## A car covers the first 78 km. of the journey in 90 minutes and the remaining 50 km. in 70 minutes. What is the average speed of the car?

This question was previously asked in

Kerala SET Paper 1: Held on February 2017

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50 km/hour 48 km/hour 40 km/hour 55 km/hour

## Answer (Detailed Solution Below)

Option 2 : 48 km/hour

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## Detailed Solution

Download Solution PDF

**Given:**

Total Distance cover = 78 + 50 = 128 km

Total time taken = 90 + 70 = 160 minutes =

16060 hours

**Formula use:**

Average speed = Total Distance Travelled / Total Time taken

**Calculation:**

Average speed = 12816060 Average speed = 128160×60

Average speed = 48 km/hour

Therefore, the average speed of the car is 48 km/hour.

Hence, the correct answer is **48 km/hour**.

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## More Average Speed Questions

**Q1.**Given below are two statements : Statement I: If a person covers a certain distance at x kmph and an equal distance at y kmph. Then, the average speed during the whole journey is

(x+y2xy)

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611149

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48013

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**Q8.**X and Y travel a distance of 90 km each such that the speed of Y is greater than that of X. The sum of their speeds is 100 km/h and the total time taken by both is 3 hours 45 minutes. The ratio of the speed of X to that of Y is:

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## More Speed Time and Distance Questions

**Q1.**A boat travel 240 km downstream in 3 hours and the time is taken by the boat to travel the same distance in upstream in 6 hours. Find the speed of stream (in kmph).

**Q2.**Given below are two statements : Statement I : If two trains of length x km and y km are moving in the same direction at u kmph and v kmph respectively, where u > v, then time taken by faster train to cross the slower train is equal to

(x+yu+v)

hrs. Statement II : If two trains are moving in opposite directions at u kmph and v kmph, Then, their relative speed is equal to (u + v) kmph. In the light of the above statements, choose the correct answer from the options given below :

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(x+y2xy)

kmph. Statement II: If the ratio of the speeds of x and y is a:b, then the ratio of the respective time taken by them to cover the same distance is b:a. In the light of the above statements, choose the correct answer from the options given below :

Guys, does anyone know the answer?