a disc of radius r is rolling purely on a flat horizontal surface
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A disc of radius R is rolling purely on a flat horizontal surface, with a constant angular velocity. The angle between the velocity and the acceleration vectors of point P is :
Click here👆to get an answer to your question ✍️ A disc of radius R is rolling purely on a flat horizontal surface, with a constant angular velocity. The angle between the velocity and the acceleration vectors of point P is :
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A disc of radius R is rolling purely on a flat horizontal surface, with a constant angular velocity. The angle between the velocity and the acceleration vectors of point P is :
Zero
B45o
C135o
Dtan−1 (1/2) Medium Open in App
Updated on : 2022-09-05
Solution Verified by Toppr
Correct option is B)
The acceleration vector is always in the horizontal direction for any point on the disc. The velocity of point P is composed if two components- one in the horizontal direction and the other in the vertical direction perpendicular to the radius. Both of these are equal to v and thus their resultant is2 v at an angle of 45 0
to the horizontal. Thus we get the angle between the velocity and the acceleration vectors.
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A disc of radius R is rolling purely on a flat horizontal surface, with a constant angular velocity.
A disc of radius R is rolling purely on a flat horizontal surface, with a constant angular velocity.The angle between ... (C) 135º (D) tan -1 (1/2)
A disc of radius R is rolling purely on a flat horizontal surface, with a constant angular velocity.
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A disc of radius R is rolling purely on a flat horizontal surface, with a constant angular velocity. The angle between the velocity and acceleration vectors of point P is .
.A disc of radius R is rolling purely on a flat horizontal surface, with a constant angular velocity. The angle between the velocity and acceleration vectors of point P is .
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A disc of radius R is rolling ...
A disc of radius `R` is rolling purely on a flat horizontal surface, with a constant angular velocity. The angle between the velocity and acceleration vectors of point `P` is
.
Updated On: 27-06-2022
( 00 : 30 ) ADVERTISEMENT Text Solution Open Answer in App A zero B `45^@` C `135^@` D `tan^-1(1//2)` Answer
The correct Answer is B
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