# a hemispherical depression is cut from one face of a cubical block, such that diameter l of hemisphere is equal to the edge of cube. find the surface area of the remaining solid.

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## A hemispherical depression is cut out from one face of the cubical wooden block such that the diameter l of the hemisphere is equal to the edge of the cube. Determine the surface area of the remaining solid.

Click here👆to get an answer to your question ✍️ A hemispherical depression is cut out from one face of the cubical wooden block such that the diameter l of the hemisphere is equal to the edge of the cube. Determine the surface area of the remaining solid.

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## A hemispherical depression is cut out from one face of the cubical wooden block such that the diameter l of the hemisphere is equal to the edge of the cube. Determine the surface area of the remaining solid.

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Updated on : 2022-09-05

Consider the diagram shown below.Solution Verified by Toppr

It is given that a hemisphere of radius

2 l

is cut out from the top face of the cuboidal wooden block.

Therefore, surface area of the remaining solid

= surface area of the cuboidal box whose each edge is of length l − Area of the top of the hemispherical part + curved surface area of the hemispherical part

=6l 2 −πr 2 +2πr 2 =6l 2 −π( 2 l ) 2 +2π( 2 l ) 2 =6l 2 − 4 πl 2 + 2 πl 2 = 4 l 2 (24+π) sq.units

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## A hemispherical depression is cut out from one face of a cubical wooden block such that the diameter l of the hemisphere is equal to the edge of the cube. Determine the surface area of remaining solid

A hemispherical depression is cut out from one face of a cubical wooden block such that the diameter l of the hemisphere is equal to the edge of the cube. Determine the surface area of the remaining solid. Thus, the surface area of the remaining solid is ¼ l2 (π + 24).

## A hemispherical depression is cut out from one face of a cubical wooden block such that the diameter l of the hemisphere is equal to the edge of the cube. Determine the surface area of the remaining solid

**Solution:**

The figure below of the solid is created as per the given information along with the top view of the solid.

From the figure, it’s clear that the surface area of the remaining solid includes TSA of the cube, CSA of the hemisphere, and excludes the base of the hemisphere.

Surface area of the remaining solid = TSA of the cubical part + CSA of the hemispherical part - Area of the base of the hemispherical part

The remaining area of the solid can be found by using the formulae;

TSA of the cube = 6 l2, where l is the length of the edge of the cube

CSA of the hemisphere = 2πr2

Area of the base of the hemisphere = πr2, where r is the radius of the hemisphere

Diameter of the hemisphere = Length of the edge of the cube = l

Radius of the hemisphere, r = l / 2

Surface area of the remaining solid = TSA of the cubical part + CSA of the hemispherical part - Area of the base of the hemispherical part

= 6 l2 + 2πr2 - πr2 = 6 l2 + πr2 = 6 l2 + π (l/2)2 = 6 l2 + πl2 / 4 = ¼ l2 (π + 24)

Thus, the surface area of the remaining solid is ¼ l2 (π + 24).

**☛ Check:**NCERT Solutions for Class 10 Maths Chapter 13

**Video Solution:**

## A hemispherical depression is cut out from one face of a cubical wooden block such that the diameter l of the hemisphere is equal to the edge of the cube. Determine the surface area of the remaining solid

NCERT Solutions Class 10 Maths Chapter 13 Exercise 13.1 Question 5

**Summary:**

The surface area of the remaining solid if a hemispherical depression is cut out from one face of a cubical wooden block such that the diameter l of the hemisphere is equal to the edge of the cube is ¼ l2 (π + 24).

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## Ex 13.1, 5

Ex 13.1, 5 A hemispherical depression is cut out from one face of a cubical wooden block such that the diameter l of the hemisphere is equal to the edge of the cube. Determine the surface area of the remaining solid. Here, diameter of the hemisphere is equal to the edge of the cube So, diame

**Check sibling questions**

## Ex 13.1, 5 - Chapter 13 Class 10 Surface Areas and Volumes (Term 2)

Last updated at Aug. 5, 2021 by Teachoo

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### Transcript

Ex 13.1, 5 A hemispherical depression is cut out from one face of a cubical wooden block such that the diameter l of the hemisphere is equal to the edge of the cube. Determine the surface area of the remaining solid. Here, diameter of the hemisphere is equal to the edge of the cube So, diameter = side of cube = l Here, base of hemisphere would not be included in the total solid area of wooden cube . Surface area of solid = Area of cube + Curved surface area of hemisphere Base area of hemisphere Area of cube Here, side = l Area of cube = 6(Side)2 = 6l2 Curved surface area of hemisphere Diameter of hemisphere = l Hence, radius = r = (Diameter )/2 = /2 Curved Surface area of hemisphere = 2 2 = 2 ( /2)^2 =2 ^2/4 = ( ^2)/2 Base area of hemisphere Base of hemisphere is a circle with radius = radius of hemisphere = r = /2 Base area of hemisphere = 2 = ( /2)^2 = ^2/4 = ( ^2)/4 Now, Surface area of solid = Area of cube + Curved surface area of hemisphere Base area of hemisphere = 6l2 + ( ^2)/2 ( ^2)/4 = 6l2 + (2 ^2 ^2)/4 = 6l2 + ( ^2)/4 = l2 (6 + /4) = l2 ((6(4) + )/4) = l2 ((24 + )/4) = 1/4l2 ( + 24) Hence, Surface area of solid = 1/4l2 ( + 24)

**Next**: Ex 13.1, 6 →

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### Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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