a horse is tethered to one corner of a rectangular field of dimensions 70 m m # 52 , by a rope of length 21 m. how much area of the field can it graze?
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A horse is tethered to one corner of a rectangular field of dimensions 70 m by 52 m by a rope 28 m long for grazing. How much area can the horse graze inside? How much area is left ungrazed?
Click here👆to get an answer to your question ✍️ A horse is tethered to one corner of a rectangular field of dimensions 70 m by 52 m by a rope 28 m long for grazing. How much area can the horse graze inside? How much area is left ungrazed?
Question
A horse is tethered to one corner of a rectangular field of dimensions 70 m by 52 m by a rope 28 m long for grazing. How much area can the horse graze inside? How much area is left ungrazed?
Medium Open in App
Updated on : 2022-09-05
Length of the rectangle, l =70 mSolution Verified by Toppr
Breadth of the rectangle, b =52 m
Length of the rope =28 m
Shaded portion AEF indicates the area in which the horse can graze. Clearly, it is the area of a quadrant of a circle of radius, r =28 m
Area of the quadrant AEF =
4 1 ×πr 2 sq. units = 4 1 × 7 22 ×28×28=616m 2
∴ Grazing Area = 616 m
2
Area left ungrazed = Area of the rectangle ABCD - Area of the quadrant AEF
Area of the rectangle ABCD = l×b sq. units
=70×52=3640m 2
∴ Area left ungrazed =3640−616=3024 m
2 .
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A horse is placed for grazing inside a rectangular field 70 m by 52 m. It is tethered to one corner by a rope 21 m long. On how much area can it graze? How much area is left ungrazed?
Answer:
Length of rectangular field = L = 70 m
Breadth of rectangular field = B = 52 m
So, Area of the field = L x B
= 70×52 = 3640
Area of the field is 3640 m^2
And, Area of the quadrant of radius 21 m = 1/4 x 22/7 x 21 x 21
= 346.5 m^2
Area available for grazing = (Area of the field) - (Area of the quadrant of radius 21 m)
= 3640 - 346.5 = 3293.5 m^2
Thus, 3293.5 m^2 area is left ungrazed.Related Questions
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A horse is placed for grazing inside a rectangular field 70 m by 52 m. It is tethered to one corner by a rope 21 m long. On how much area can it graze ? How much area is left ungrazed ?
A horse is placed for grazing inside a rectangular field 70 m by 52 m. It is tethered to one corner by a rope 21 m long. On how much area can it graze ? How much area is left ungrazed ?
Byju's Answer Standard X Mathematics
Area of a Sector of a Circle
A horse is pl... Question
A horse is placed for grazing inside a rectangular field 70 m by 52 m. It is tethered to one corner by a rope 21 m long. On how much area can it graze ? How much area is left ungrazed ?
Open in App Solution
Area of the grazed field
= θ 360 × π r 2 = 90 360 × π ( 21 ) 2 = 1 4 × π ( 21 ) 2 = 346.5 m 2
Total area of the field
= 70 × 52 = 3640 m 2
Area left ungrazed = Total area of the field - Area of the grazed field
= 3640 − 346.5 = 3296.5 m 2 Suggest Corrections 26
SIMILAR QUESTIONS
Q.A horse is placed for grazing inside a rectangular field
70 m by 52 m
and is tethered to one corner by a rope
21 m
long. How much area can it graze?
70 m by 52 m
and is tethered to one corner by a rope
21 m
along. On how much area can it graze?
Q. A horse is placed for grazing inside a rectangular field 70 m by 52 m and is tethered to one corner by a rope 21 m long. Find the area ungrazed by the horse.Q. a horse is placed for grazing inside a rectangular field 70 m by 52 m. it is tethered to one corner by a rope 21 m long . on how much area can it graze?how much area is left ungrazed?Q. A horse is tethered to one corner of a rectangular field of dimensions 70 m by 52 m by a rope 28 m long for grazing. How much area can the horse graze inside? How much area is left ungrazed?
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