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    a long straight wire of circular cross section of radius a carries a steady current i. the current is uniformly distributed across its cross section. the ratio of the magnitudes of magnetic field at a point distant a/2 above the surface of wire to that at a point distant a/2 below its surface is

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    get a long straight wire of circular cross section of radius a carries a steady current i. the current is uniformly distributed across its cross section. the ratio of the magnitudes of magnetic field at a point distant a/2 above the surface of wire to that at a point distant a/2 below its surface is from screen.

    A long straight wire of radius a carries a steady current. The current is uniformly distributed across its cross

    Click here👆to get an answer to your question ✍️ A long straight wire of radius a carries a steady current. The current is uniformly distributed across its cross - section.the ratio of the magnetic field at a/4 inside and a/4 outside from the surface of wire is:

    A long straight wire of radius a carries a steady current. The current is uniformly distributed across its cross-section.the ratio of the magnetic field at

    Question 4 a ​ inside and 4 a ​

    outside from the surface of  wire is: 

    A

    1:1

    B

    7:16

    C

    15:16

    D

    16:9

    Easy Open in App

    Updated on : 2022-09-05

    Solution Verified by Toppr

    Correct option is C)

    Solution :

    We know,magnetic field B in inside points =

    2πR 2 μ 0 ​ ir ​

    [where,R = radius,r = distance of the inside point from the axis and i = total current]

    Distance from the axis at

    4 a ​ inside = (a− 4 a ​ ) = 4 3a ​

    So,Magnetic field at

    4 a ​ inside = 2πa 2 μ 0 ​ ×i× 4 3a ​ ​ = 8πa 3μ 0 ​ i ​

    Distance from the axis at

    4 a ​ outside = (a+ 4 a ​ )

    We also know,magnetic field B at outside points =

    2πr μ 0 ​ i ​

    [r=distance of the outside point from the axis]

    So,magnetic field at

    4 a ​ outside = 2π× 4 5a ​ μ 0 ​ i ​ = 5πa 2μ 0 ​ i ​

    The ratio of the magnetic field at

    4 a ​ inside and 4 a ​

    outside the surface of the wire =

    5πa 2μ 0 ​ i ​ 8πa 3μ 0 ​ i ​ ​ =15:16

    So,the correct option is C.

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    A long straight wire of a circular cross section (radius a) carries a steady current 7 and the current / is uniformly distributed across this cross

    Magnetic field due to a long straight wire of radius a carrying current I at a point distance r from the centre of the wire is given as follows: B=(mu(0)ir)/(2pia^(2))" " for r < a B=(mu(0)ir)/(2pia^(2)) " " for r=a B=(mu(0)ir)/(2pia^(2)) " " for r gt a The variation of magnetic field B with distance r from the centre of wire is shown in the figure.

    Home > English > Class 12 > Physics > Chapter >

    Magnetic Effects Of Current And Magnetism

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    A long straight wire of a circ...

    A long straight wire of a circular cross section (radius a) carries a steady current 7 and the current / is uniformly distributed across this cross-section. Which of the following plots represents the variation of magnitude of magnetic field B with distance from the centre of the wire?

    Text Solution Open Answer in App A B C D Answer

    The correct Answer is A

    Solution

    Magnetic field due to a long straight wire of radius a carrying current I at a point distance r from the centre of the wire is given as follows:

    forr

    B= μ 0 ir 2π a 2

    B=μ0ir2πa2 forr

    B= μ 0 ir 2π a 2 forr=a B=μ0ir2πa2 forr=a B= μ 0 ir 2π a 2 forr>a B=μ0ir2πa2 forr>a

    The variation of magnetic field B with distance r from the centre of wire is shown in the figure.

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    Mohammed 11 day ago
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