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    a milkman purchases the milk at rs. x per litre and sells it at rs. 2x per litre still he mixes 2 litres water with every 6 litres of pure milk. what is the profit percentage?

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    Question

    A milkman purchases the milk at Rs. x per litre and sells it at Rs. 2x per litre still he mixes 2 litres water with every 6 litres of pure milk. What is the profit percentage?

    Easy Open in App Solution Verified by Toppr

    Let the C.P of 1 liter pure milk be Rs 1 , then

    6 l milk cost ___ 6 rupees = Rs 6 only

    2 l water cost ___ 0 rupees

    8 liter mixture ⇒ S.P = 8×2=16 ruppes

    profit % = 6 16−6 ​ ×100= 6 10×100 ​ = 3 5×100 ​ =166.66%

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    [Solved] A milk man purchases milk at Rs. X per litre and sells it at

    Shortcut TrickGiven: Cost price of milk = Rs. X per litre Selling Price = Rs. 2X per litre He mixes 2 litres of water with every 6 litre of pure milk C

    Home Quantitative Aptitude Profit and Loss Mixture Problems

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    A milk man purchases milk at Rs. X per litre and sells it at Rs. 2X per litre. Still he mixes 2 litres of water with every 6 litre of pure milk. What is his profit percentage?

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    UGC NET Paper 1: Held on 20th Nov 2021 Shift 2

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    33.33 66.66 133.33 166.66

    Answer (Detailed Solution Below)

    Option 4 : 166.66

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    Detailed Solution

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    Shortcut Trick Given:

    Cost price of milk = Rs. X per litre

    Selling Price = Rs. 2X per litre

    He mixes 2 litres of water with every 6 litre of pure milk

    Calculation:

    Profit percent = {[(Profit)/CP] × 100}

    ⇒ (10x/6x) × 100 = 166.66%

    ∴ The profit percentage is 166.66%.

    Alternate MethodGiven:

    Cost price of milk = Rs. X per litre

    Selling Price = Rs. 2X per litre

    He mixes 2 litres of water with every 6 litre of pure milk

    Formula Used:

    Profit = Selling price - Cost price

    Profit percent = {[(SP - CP)/CP] × 100}

    Where, SP = Selling price and CP = Cost price

    Calculation:

    According to the question,

    Cost price of 6 litres milk = Rs. 6

    Cost price of 2litres water = Rs. 0

    Total cost price of mixture = 6x

    Selling price of 6 litres milk and 2litres water = 8 × 2x

    ⇒ 16x

    Profit = Selling price - Cost price

    ⇒ 16x - 6x = 10x

    Profit percent = {[(SP - CP)/CP] × 100}

    ⇒ (10x/6x) × 100 = 166.66%

    ∴ The profit percentage is 166.66%.

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