a milkman purchases the milk at rs. x per litre and sells it at rs. 2x per litre still he mixes 2 litres water with every 6 litres of pure milk. what is the profit percentage?
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get a milkman purchases the milk at rs. x per litre and sells it at rs. 2x per litre still he mixes 2 litres water with every 6 litres of pure milk. what is the profit percentage? from screen.
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A milkman purchases the milk at Rs. x per litre and sells it at Rs. 2x per litre still he mixes 2 litres water with every 6 litres of pure milk. What is the profit percentage?
Easy Open in App Solution Verified by Toppr
Let the C.P of 1 liter pure milk be Rs 1 , then
6 l milk cost ___ 6 rupees = Rs 6 only
2 l water cost ___ 0 rupees
8 liter mixture ⇒ S.P = 8×2=16 ruppes
profit % = 6 16−6 ×100= 6 10×100 = 3 5×100 =166.66%
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[Solved] A milk man purchases milk at Rs. X per litre and sells it at
Shortcut TrickGiven: Cost price of milk = Rs. X per litre Selling Price = Rs. 2X per litre He mixes 2 litres of water with every 6 litre of pure milk C
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A milk man purchases milk at Rs. X per litre and sells it at Rs. 2X per litre. Still he mixes 2 litres of water with every 6 litre of pure milk. What is his profit percentage?
This question was previously asked in
UGC NET Paper 1: Held on 20th Nov 2021 Shift 2
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33.33 66.66 133.33 166.66
Answer (Detailed Solution Below)
Option 4 : 166.66
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Detailed Solution
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Shortcut Trick Given:
Cost price of milk = Rs. X per litre
Selling Price = Rs. 2X per litre
He mixes 2 litres of water with every 6 litre of pure milk
Calculation:
Profit percent = {[(Profit)/CP] × 100}
⇒ (10x/6x) × 100 = 166.66%
∴ The profit percentage is 166.66%.
Alternate MethodGiven:Cost price of milk = Rs. X per litre
Selling Price = Rs. 2X per litre
He mixes 2 litres of water with every 6 litre of pure milk
Formula Used:Profit = Selling price - Cost price
Profit percent = {[(SP - CP)/CP] × 100}
Where, SP = Selling price and CP = Cost price
Calculation:According to the question,
Cost price of 6 litres milk = Rs. 6
Cost price of 2litres water = Rs. 0
Total cost price of mixture = 6x
Selling price of 6 litres milk and 2litres water = 8 × 2x
⇒ 16x
Profit = Selling price - Cost price
⇒ 16x - 6x = 10x
Profit percent = {[(SP - CP)/CP] × 100}
⇒ (10x/6x) × 100 = 166.66%
∴ The profit percentage is 166.66%.
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Guys, does anyone know the answer?