# a milkman purchases the milk at rs. x per litre and sells it at rs. 2x per litre still he mixes 2 litres water with every 6 litres of pure milk. what is the profit percentage?

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get a milkman purchases the milk at rs. x per litre and sells it at rs. 2x per litre still he mixes 2 litres water with every 6 litres of pure milk. what is the profit percentage? from screen.

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## A milkman purchases the milk at Rs. x per litre and sells it at Rs. 2x per litre still he mixes 2 litres water with every 6 litres of pure milk. What is the profit percentage?

Easy Open in App Solution Verified by Toppr

Let the C.P of 1 liter pure milk be Rs 1 , then

6 l milk cost ___ 6 rupees = Rs 6 only

2 l water cost ___ 0 rupees

8 liter mixture ⇒ S.P = 8×2=16 ruppes

profit % = 6 16−6 ×100= 6 10×100 = 3 5×100 =166.66%

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## [Solved] A milk man purchases milk at Rs. X per litre and sells it at

Shortcut TrickGiven: Cost price of milk = Rs. X per litre Selling Price = Rs. 2X per litre He mixes 2 litres of water with every 6 litre of pure milk C

Home Quantitative Aptitude Profit and Loss Mixture Problems

## Question

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## A milk man purchases milk at Rs. X per litre and sells it at Rs. 2X per litre. Still he mixes 2 litres of water with every 6 litre of pure milk. What is his profit percentage?

This question was previously asked in

UGC NET Paper 1: Held on 20th Nov 2021 Shift 2

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33.33 66.66 133.33 166.66

## Answer (Detailed Solution Below)

Option 4 : 166.66

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## Detailed Solution

Download Solution PDF

Shortcut Trick **Given:**

Cost price of milk = Rs. X per litre

Selling Price = Rs. 2X per litre

He mixes 2 litres of water with every 6 litre of pure milk

Calculation:

Profit percent = {[(Profit)/CP] × 100}

⇒ (10x/6x) × 100 = 166.66%

∴ The profit percentage is 166.66%.

**Alternate Method**

**Given:**

Cost price of milk = Rs. X per litre

Selling Price = Rs. 2X per litre

He mixes 2 litres of water with every 6 litre of pure milk

**Formula Used:**

Profit = Selling price - Cost price

Profit percent = {[(SP - CP)/CP] × 100}

Where, SP = Selling price and CP = Cost price

**Calculation:**

According to the question,

Cost price of 6 litres milk = Rs. 6

Cost price of 2litres water = Rs. 0

Total cost price of mixture = 6x

Selling price of 6 litres milk and 2litres water = 8 × 2x

⇒ 16x

Profit = Selling price - Cost price

⇒ 16x - 6x = 10x

Profit percent = {[(SP - CP)/CP] × 100}

⇒ (10x/6x) × 100 = 166.66%

∴ The profit percentage is 166.66%.

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## More Mixture Problems Questions

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Guys, does anyone know the answer?