a number when divided by 143 leaves 31 as remainder. what will be the remainder when the same number is divided by 13?
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A number when divided by 143 leaves 31 as remainder. What will be the remainder when the same number is divided by 13 ? a 0 b 1 c 3 d 5
A number when divided by 143 leaves 31 as remainder. What will be the remainder when the same number is divided by 13 ? a 0 b 1 c 3 d 5
Byju's Answer Standard X Mathematics
Euclid's Division Lemma
A number when... Question
A number when divided by 143 leaves 31 as remainder. What will be the remainder when the same number is divided by 13 ?
(a) 0 (b) 1 (c) 3 (d) 5
Open in App Solution
The number can be expessed by 143n+31 (euclid division lemma, a = bq+r) where n is any natural number.
Now as 143 is divisible by 13, 143n leaves no remainer or zero as remainder when divided by 13.
So we only need to focus on 31 now.
31 divided by 13 leaves remainder 5
Hence the answer is 5.
Suggest Corrections 23 SIMILAR QUESTIONS
Q.A number when divided by 143 leaves 31 as remainder. What will be the remainder when the same number is divided by 13 ?
(a) 0 (b) 1 (c) 3 (d) 5
Q. A number when divided by 143 leaves 31 as remainder. What will be the remainder when the same number is divided by 13 ?Q. A number when divided by 143 leaves 31 as remainder. What will be the remainder when the same number is divided by 13?(a) 0 (b) 1 (c) 3 (d) 5
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A number when divided by 143 leaves 31 as remainder. What will be the remainderwhen the same number is divided by 13 ?
Click here👆to get an answer to your question ✍️ A number when divided by 143 leaves 31 as remainder. What will be the remainderwhen the same number is divided by 13 ?
Question
when the same number is divided by 13 ?
A0
B1
C3
D5
Hard Open in App Solution Verified by Toppr
Correct option is C)
A number when divided by 143 leaves 31 as remainder
The given number is of the form 143x+31=13(11x)+13×2+5
13(11x+2)+5
∴ The remainder when the given number is divided by 13 is 5
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A number when divided by 143 leaves 31 as remainder. What will be
A number when divided by 143 leaves 31 as remainder. What will be the remainder when the same number is divided by 13? a 0 b 1 c 3 d 5
Previous Question Next Question Question :
A number when divided by 143 leaves 31 as remainder. What will be the remainder when the same number is divided by 13? a 0 b 1 c 3 d 5
Answer :
d 5 We know Dividend = Divisor × Quotient + Remainder. It is given that: Divisor = 143 Remainder = 13 So the given number is in the form of 143x + 31 where x is the quotient. ∴ 143x + 31 = 13 11x + 13 × 2 + 5 = 13 11x + 2 + 5 Thus the remainder will be 5 when the same number is divided by 13.
Related Answer
A number when divided by `143` leaves `31` as remainder. What will be the remainder, when the same number is divided by `13` ?
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Guys, does anyone know the answer?