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    A charged particle having charge q and mass m is projected into a region of uniform electric field of strength E0, with velocity V0 perpendicular to E0. Throughout the motion, apart from electric force, the particle also experiences a dissipative force of constant magnitude qE 0 and directed opposite to its velocity. If V 0

    A charged particle having charge q and mass m is projected into a region of uniform electric field of strength E0, with velocity V0 perpendicular to E0. Throughout the motion, apart from electric force, the particle also experiences a dissipative force of constant magnitude qE 0 and directed opposite to its velocity. If V 0|=6 m / s, then find its speed when it has turned through an angle of 90∘.Write speed in m / s.

    Byju's Answer Standard XII Physics

    Coefficients of Friction

    A charged par... Question

    A charged particle having charge

    q and mass m

    is projected into a region of uniform electric field of strength

    −→ E 0 , with velocity → V 0 perpendicular to −→ E 0

    . Throughout the motion, apart from electric force, the particle also experiences a dissipative force of constant magnitude

    q E 0

    and directed opposite to its velocity. If

    → V 0 | = 6 m/s

    , then find its speed when it has turned through an angle of

    90 ∘ . Write speed in m/s. Open in App Solution

    Here v

    is speed which is equal to

    v = √ v 2 x + v 2 y and d v d t =

    rate of change in speed

    Consider the situation when the particle has turned through an angle of

    ψ d v d t = − q E 0 m [ 1 − sin ψ ] d v x d t = q E 0 m [ 1 − sin ψ ] ⇒ d v d t = − d v x d t ⇒ v = − v x + C At t = 0 , v = v 0 and v x = 0 ⇒ C = v 0 ⇒ v = v 0 − v x = v 0 − v sin ϕ

    When it has turned through an angle of

    90 ∘ , v = v 0 1 + sin ϕ = 6 1 + 1 = 3 m/s Suggest Corrections 1

    SIMILAR QUESTIONS

    Q. In a certain region free from gravity, electric field is along negative x-direction and it is constant. A particle having mass m and charge q is projected along x-direction with speed

    V 0

    . An additional force

    → F = → C × → V

    is acting on the charge where

    → V

    is velocity vector and

    → C

    is a constant vector. The charge comes out of region with speed

    V 0 2

    as shown in figure, then the magnitude of electric field is :

    Q. A charged particle is projected perpendicular to a uniform electric field of length

    2 m

    and initial velocity of charged particle is

    10 m/s

    . Calculate deflection of the charge in the direction of electric field., when it leaves it.

    Q. A charged particle

    ( mass m and charge q ) moves along x − axis with velocity v 0

    . When it passes through the origin, it enters a region having uniform electric field

    E = − E ^ j which extends up to x = d

    . The equation of path of electron in the region

    x > d is :

    Q. A particle of charge

    q and mass m

    starts moving from the origin under the action of electric field

    → E = E 0 ^ i and → B = B 0 ^ i with velocity → V = V 0 ^ j

    . The speed of particle will become

    2 V 0 after a time:

    Q. A charged particle is projected perpendicular to a uniform electric field of length

    2 m

    and initial velocity of charged particle is

    10 m/s

    . Calculate deflection of the charge in the direction of electric field., when it leaves it.

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    स्रोत : byjus.com

    A particle having charge q and mass m is projected from the origin with v..

    Solution For A particle having charge q and mass m is projected from the origin with velocity v0​[i^+k^] in a uniform magnetic field B=−B0​k at time t=0. If x(t),y(t),z(t) represent x,y and z-co-ordin

    Home Class 12 Physics

    Moving Charges and Magnetism

    Motion in a Magnetic Field

    Question

    Solving time: 5 mins

    A particle having charge q and mass m is projected from the origin with velocity v

    0 ​ [ i ^ + k ^

    ] in a uniform magnetic field

    B =−B 0 ​ k

    at time t=0. If x(t),y(t),z(t) represent x,y and z-co-ordinates of the particle at time t, then select the correct option(s).

    SELECT MULTIPLE OPTION

    A y(t)= qB mv 0 ​ ​ [1−cos( m qB ​ t)] B x(t)= qB mv 0 ​ ​ cos( m qBt ​ ) C y(t)= qB mv 0 ​ ​ [1−sin( m qBt ​ )] D z(t)=v 0 ​ t

    Difficulty level: Hard

    Viewed by: 5,912 students

    Solutions

    (1)

    R= qB mv 0 ​ ​ ,ω= R v 0 ​ ​ = m qB ​ y(t)=R−Rcosωt y(t)= qB mV 0 ​ ​ (1−cos m qBt ​ ) and Z(t)=V 0 ​ t 89 Share

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    A particle of charge q and mass m is projected with a velocity v _0 towards a circular region having a uniform magnetic field B perpendicular and into the plane of paper from point P as shown in the figure. R is the radius and O is the center of the circ

    Answer to: A particle of charge q and mass m is projected with a velocity v _0 towards a circular region having a uniform magnetic field B...

    Magnetic fields

    A particle of charge q and mass m is projected with a velocity v _0 towards a circular region...

    A particle of charge q and mass m is projected with a velocity v _0 towards a circular region... Question:

    A particle of charge

    q q and mass m m

    is projected with a velocity

    v 0 v0

    towards a circular region having a uniform magnetic field

    B B

    perpendicular and into the plane of paper from point

    P P

    as shown in the figure.

    R R is the radius and O O

    is the center of the circular region. If the line

    O P OP makes an angle θ θ

    with the direction of

    v 0 v0

    , then determine the value of

    v 0 v0

    so that particle passes through

    O O .

    Magnetic field

    When a magnetic field is applied to a charged particle, a force is exerted on the charge, which causes it to move in an orbicular path with a certain velocity. That force will be a centripetal force in the magnetic field.

    Answer and Explanation:

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    Let r is the radius of the circular path.

    Therefore, the angle can be calculated as,

    {eq}\begin{align*} \sin \theta &=...

    See full answer below.

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    The Effect of a Magnetic Field on Moving Charges: Physics Lab

    from

    Chapter 16 / Lesson 4

    3.6K

    A magnetic field is the area in which other objects can be affected by a magnet or moving charge. Observe the effect magnetic fields have on moving charges with this lab and analyze the observational data collected.

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