# a particle moves along x axis in such a way that its x coordinate varies with time

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## A particle moves along x

Click here👆to get an answer to your question ✍️ A particle moves along x - axis in such a way that its coordinate (x) varies with time (t) according to the expression, x = 2 - 5t + 6t^2 . Then the initial velocity of the particle is

A particle moves along x-axis in such a way that its coordinate (x) varies with time (t) according to the expression, x=2−5t+6tQuestion 2

. Then the initial velocity of the particle is

**A**

## −5m/sec

**B**

## −3m/sec

**C**

## 6m/sec

**D**

## 3m/sec

Easy Open in App Solution Verified by Toppr

Correct option is A)

The displacement is given as: y=ut+

2 1 at 2

where, u is the initial velocity and a is the acceleration

Comparing with given expression:

y=−5t+6t 2 +2 u=−5m/s, a=12m/s 2

So initial velocity is −5 m/s

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## A particle moves along the X axis in such a way that its X cordinates varies with time as x=2 5 t+6 t2· What will be its initial velocity?

A particle moves along the X axis in such a way that its X cordinates varies with time as x=2 5 t+6 t2· What will be its initial velocity?

Byju's Answer Standard XII Physics Relative Velocity A particle mo... Question

A particle moves along the X axis in such a way that its X cordinates varies with time as x= 2-5t+6t2. What will be its initial velocity?

Open in App Solution

Particle is moving along x-axis so displacement is also along x-axis

Now , ⇒ x = 6t²-5t+2

since , V = dx/dt

Differentiating w.r.t. 't'

⇒ v = 6 × 2t - 5 ⇒ v = 12t - 5 when t=0 V=-5m/s

So initial velocity =-5 m/s

Negative sign states that velocity decreases with time.

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SIMILAR QUESTIONS

**Q.**A particle moves along x-axis in such a way that its coordinate (

x

, in metres) varies with time (

t

) according to the expression,

x = ( 2 − 5 t + 6 t 2 )

. Then the initial velocity of the particle is

**Q.**A particle moves along x-axis in such a way that its coordinate (x) varies with time (t) according to the expression,

x = 2 − 5 t + 6 t 2

. Then the initial velocity of the particle is

**Q.**A particle moves along

x

-axis in such a way that its coordinate

x

varies with time according to the equation

x = 2 − 5 t + 6 t 2

. If the initial velocity of the particle is

v . Find − v .

**Q.**A particle moves along the

x −

axis in such a way that its

x −

coordinates varies with time as

x = 1 – 2 t + 3 t 2

. What will be its initial velocity?

**Q.**A particle moves along x-axis in such a way its coordinate (x) varies with time (t) according to the expression

x = 2 − 5 t + 6 t 2

. its intial velocity is

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Standard XII Physics

## A particle moves along the x

x = 2 - 5t + 6t^(2) rArr v = (dx)/(dt) = - 5 + 12 t , initially t = 0 rArr therefore v = - 5 m//s , a = (d^(2))/(dt^(2)) = 12 m//s^(2) Hence correct answer is (A).

A particle moves along the x-axis in such a way that its x-co-ordinate varies with time as

x = 2 – 5 t + 6 t 2 .

The initial velocity and acceleration of particle will respectively be-

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MOTION-ONE DIMENSION MOTION-EXERCISE - 3 |SECTION - B PREVIOUS YEAR PROBLEMS | JEE MAIN

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Updated On: 27-06-2022

Text Solution A –5 m/s, 12 m/s B 5 m/s, –12 m/s C –5 m/s, –12 m/s D 5 m/s, 12 m/s Solution x = 2 − 5 t + 6 t 2 ⇒ v = d x d t = − 5 + 12 t , initially t = 0 ⇒ ∴ v = − 5 m / s , a = d 2 d t 2 = 12 m / s 2

Hence correct answer is (A).

Answer

Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

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x = 2 − 5 t + 6 t 2 ,

where x is in metres and t is in seconds. The initial velocity of the particle is :–

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