if you want to remove an article from website contact us from top.

# a particle of mass m, charge q and kinetic energy k enters a transverse uniform magnetic field b. after 10 seconds magnitude of momentum of the particle is

Category :

### Mohammed

Guys, does anyone know the answer?

get a particle of mass m, charge q and kinetic energy k enters a transverse uniform magnetic field b. after 10 seconds magnitude of momentum of the particle is from screen.

## A particle of mass m, charge q and kinetic energy t enters a transverse uniform magnetic field of induction B. After 3 s, the kinetic energy of the particle will be

Click here👆to get an answer to your question ✍️ A particle of mass m, charge q and kinetic energy t enters a transverse uniform magnetic field of induction B. After 3 s, the kinetic energy of the particle will be Question

A

B

C

D

## 4T

Medium Open in App

Updated on : 2022-09-05

Solution Verified by Toppr

Correct option is C)

after passing through a magnetic field, the magnitude of its mass and velocity of the particle remains same, so its energy does not change that is kinetic energy will remain T.

Hence (C) is correct answer

Solve any question of Moving Charges and Magnetism with:-

Patterns of problems

>

127 7

स्रोत : www.toppr.com

## [Solved] A particle of mass m, charge Q and kinetic energy T ent

CONCEPT: Magnetic Field: The field around the magnet that exerts a magnetic force on the magnetic substances is called a magnetic field. When a cha Home Physics Moving Charges and Magnetism Motion in a Magnetic Field Circulating Charged Particle

## Question

A particle of mass m, charge Q and kinetic energy T enters a transverse uniform magnetic field of induction

B→

. After 3 seconds the kinetic energy of the particle will be -

T 4 T 3 T 2 T

## Answer (Detailed Solution Below)

Option 1 : T

India's Super Teachers for all govt. exams Under One Roof

FREE

Demo Classes Available*

## Detailed Solution

CONCEPT:Magnetic Field: The field around the magnet that exerts a magnetic force on the magnetic substances is called a magnetic field.

When a charged particle enters a region of the uniform magnetic field,

it experiences a magnetic force which remains perpendicular to its motion due to which the particle undergoes a uniform circular motion.

As the magnetic force remain perpendicular to the motion, work done by the magnetic force on the particle = 0

Work done is given by the change in kinetic energy since work done is zero so is the kinetic energy.

Change in kinetic energy of the particle is "0".Work done (W) = Force (F).displacement (s) Cosθ

Where θ is the angle between F and s

EXPLANATION:

In the case of magnetic force,

The force acting is perpendicular to the velocity of the particle,

So θ = 90°

Work done (W) = F s cos90° = 0

The kinetic energy of the particle will remain constant i.e. T.

The correct option is 1.

Share on Whatsapp

Stay updated with Physics questions & answers with Testbook. Know more about Moving Charges and Magnetism and ace the concept of Motion in a Magnetic Field and Circulating Charged Particle

India’s #1 Learning Platform

Start Complete Exam Preparation

Daily Live MasterClasses

Practice Question Bank

Mock Tests & Quizzes

Trusted by 3,16,38,270+ Students

‹‹ Previous Ques Next Ques ››

## More Motion in a Magnetic Field Questions

Q1. Two protons are moving in a magnetic field B. The proton 1 is moving perpendicular to the direction of the magnetic field with the speed v and the proton 2 is moving at an angle 30° to the magnetic field with the speed 2v. Find the ratio of the time period for proton 1 to proton 2.Q2. Two similar charged particles A and B are moving in a magnetic field such that the direction of motion is perpendicular to the magnetic field. If the momentum of the particle A is double of the particle B, then find the ratio of the time period of the particle A to particle B.Q3. Two similar charged particles are moving with the same speed in a magnetic field B. The particle A is moving perpendicular to the field whereas the particle B is moving at an angle 45° to the field. Find the ratio of the radius of the path of particle A to particle B.Q4. A charged particle enters a uniform magnetic field at a right angle to the magnetic field. The field exists for a length equal to 1.5 times the radius of the circular path of the particle in the field. The particle will deviate from its path byQ5. A charge particle of mass 'm' and charge 'q' is moving with a speed 'v' in a magnetic field B. If the radius of the circular path traced by a charge particle is 'r'. Then find the ratio of q/m.Q6. A proton and an electron enter in the uniform magnetic (B) field with velocity (v) at right angle to the magnetic field then which charge experience maximum force?Q7. ________ can be accelerated by cyclotron.Q8. An electron is moving in a circular path of radius 0.02 m in a magnetic field of intensity 10-2 T. Find the speed of the electron.Q9. Which of the following quantity of the charged particle does not change in the cyclotron:Q10. A proton and an electron both are moving upward and enters into a uniform magnetic field. The direction of the magnetic field is perpendicular to the plane of paper and inward. Then both the particles will move:

## More Moving Charges and Magnetism Questions

Q1. According to Fleming's right-hand rule, if the forefinger indicates the direction of the magnetic field and the thumb shows the direction of motion of the conductor, then the stretched middle finger will predict the direction ofQ2. The magnetic field produced by a current-carrying straight wire at a point outside the wire dependsQ3. Read the following statements and choose the correct option. Assertion(A) - When an electric current passes through a wire, it behaves like a magnet. Reason(R) - Wires are usually made up of magnetic materialsQ4. Which of the following devices does not involve the principle of ‘magnetic effect of electric current’ in its working?Q5. The magnetic field is the strongest atQ6. A α-particle enters in a magnetic field of strength (3î + 2ĵ) with velocity (5 × 105 î). The Magnetic force experienced by the particle will be :Q7. The source of magnetic field is:Q8. The direction of the magnetic field by a current-carrying conductor is given by -

स्रोत : testbook.com

## A particle of mass m, charge q and kinetic energy T enters in a transverse uniform magnetic field of induction B. After the 3 s, the kinetic energy of the particle will be

A particle of mass m, charge q and kinetic energy T enters in a transverse uniform magnetic field of induction B. After the 3 s, the kinetic energy of the par

Home > English > Class 12 > Physics > Chapter >

Magnetic Effect Of Current

>

A particle of mass m, charge q...

A particle of mass m, charge q and kinetic energy T enters in a transverse uniform magnetic field of induction B. After the 3 s, the kinetic energy of the particle will be

Updated On: 27-06-2022

Get Answer to any question, just click a photo and upload the photo and get the answer completely free,

UPLOAD PHOTO AND GET THE ANSWER NOW!

Text Solution Open Answer in App A 3T B 2T C T D 4T Answer

The correct Answer is c

Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

## Related Videos 15665516 2.1 K 5.6 K 0:36

A particle of mass m, charge q and kinetic energy T enters in a transverse uniform magnetic field of induction B. After the 3 s, the kinetic energy of the particle will be

646941428 200 1.9 K 1:50

A particle of mass m, charge Q and kinetic energy T enters a transverse uniform magnetic , field of induction

B ⃗ B→

. After 3 seconds the kinetic energy of the particle will be:

67774784 0 2.1 K 1:20

द्रव्यमान m आवेश q तथा गतिज ऊर्जा K का एक कण एकसमान चुंबकीय क्षेत्र B में लंबवत प्रवेश करता है। 3 सेकण्ड, के पश्चात् कण की गतिज ऊर्जा होगी:

644163738 0 5.3 K 3:41

A charged particle (+q) enters into a uniform magnetic field region of induction B and desribes a circle. The kinetic energy of the charged particle is 112163232 94 100 6:25

द्रव्यमान m, आवेश Q और गतिज ऊर्जा K का एक कण उत्प्रेरक

B ⃗ B→

के अनुप्रस्थ अचर चुंबकीय क्षेत्र ,में प्रवेश करता है T सेकण्ड के उपरान्त इस कण की गतिज ऊर्जा होगी - 646107699 100 6.9 K 7:29

द्रव्यमान m आवेश Q और गतिज ऊर्जा T का एक कण उत्प्रेरक

B ⃗ B→

के अनुप्रस्थ अचर चुम्बकीय फील्ड (क्षेत्र) में प्रवेश करता है। तीन सैकण्ड के उपरान्त इस कण की गतिज ऊर्जा होगी :

Add a public comment...

Popular Chapters by Class:

Class 6 Algebra

Basic Geometrical Ideas

Data Handling Decimals Fractions Class 7

Algebraic Expressions

Comparing Quantities

Congruence of Triangles

Data Handling

Exponents and Powers

Class 8

Algebraic Expressions and Identities

Comparing Quantities

Cubes and Cube Roots

Data Handling

Direct and Inverse Proportions

Class 9

Areas of Parallelograms and Triangles

Circles Coordinate Geometry Herons Formula

Introduction to Euclids Geometry

Class 10

Areas Related to Circles

Arithmetic Progressions

Circles Coordinate Geometry

Introduction to Trigonometry

Class 11 Binomial Theorem

Complex Numbers and Quadratic Equations

Conic Sections

Introduction to Three Dimensional Geometry

Limits and Derivatives

Class 12

Application of Derivatives

Application of Integrals

Continuity and Differentiability

Determinants

Differential Equations