a prism of refractive index n and angle a is placed in minimum deviation position. if the angle of minimum deviation is equal to the angle a, then the value of a is
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A prism of refractive index mu and angle A is placed in the minimum deviation position. If the angle of minimum deviation is A, then the value of A in terms of mu is:
Click here👆to get an answer to your question ✍️ A prism of refractive index mu and angle A is placed in the minimum deviation position. If the angle of minimum deviation is A, then the value of A in terms of mu is:
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A prism of refractive index μ and angle A is placed in the minimum deviation position. If the angle of minimum deviation is A, then the value of A in terms of μ is:
Asin−1 ( 2 μ )
Bsin−1 2 μ−1
C2cos−1 ( 2 μ )
D2cos−1 ( 8 μ ) Medium Open in App
Updated on : 2022-09-05
Solution Verified by Toppr
Correct option is C)
We can use the formula: μ=sin( 2 A ) sin( 2 A+D )
where D is angle of minimum deviation and A is angle of prism.
According to given condition A=D
∴ μ= sin( 2 A ) sin( 2 A+A ) μ= sin( 2 A ) sin(A) μ= sin( 2 A ) 2sin( 2 A )cos( 2 A ) μ=2cos( 2 A ) ∴ A=2cos −1 ( 2 μ
) which is the required solution.
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A prism of refractive index n and length A is placed in minimum deviation position.
A prism of refractive index n and length A is placed in minimum deviation position. If the angle of minimum deviation is ... (d) 2sin^-1[(4-n^2/4)^½]
A prism of refractive index n and length A is placed in minimum deviation position.
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A prism of refractive index m ...
A prism of refractive index
m m and angle A A
is placed in the minimum deviation position. If the angle of minimum deviation is
A A , then the value of A A in terms of m m is
Updated On: 27-06-2022
( 00 : 21 ) ADVERTISEMENT Text Solution Open Answer in App A sin −1 [ μ 2 ] sin-1[μ2] B sin −1 [ μ 2 −1 − − − − − √ 2 ] sin-1[μ2-12] C 2 cos −1 [ μ 2 ] 2cos-1[μ2] D cos −1 [ μ 2 ] cos-1[μ2] Answer
The correct Answer is C
Solution μ= sin( 2A 2 ) sin( A 2 ) μ=sin(2A2)sin(A2) Answer
Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.
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Guys, does anyone know the answer?