# a train can travel 50% faster than a car. both start from point a at the same time and reach point b 75 kms away from a at the same time. on the way, however, the train lost about 12.5 minutes while stopping at the stations. the speed of the car is

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get a train can travel 50% faster than a car. both start from point a at the same time and reach point b 75 kms away from a at the same time. on the way, however, the train lost about 12.5 minutes while stopping at the stations. the speed of the car is from screen.

## A train can travel 50

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## A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:

**A**

## 100 kmph

**B**

## 110 kmph

**C**

## 120 kmph

**D**

## 130 kmph

Easy Open in App Solution Verified by Toppr

Correct option is C)

Let speed of the car be kmph.Then, speed of the train =

100 150 ×=( 2 3 ×)kmph ∴ x 75 − (3/2)x 75 = 10×60 125 ⇒ x 75 − x 50 = 24 5 ⇒x=( 5 25×24 )=120kmph

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## A train can travel 50 % faster than a car. Both start from point A at the same time and reach point B 75 kilometres away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car isA. 100 kmphB. 110 kmphC. 130 kmphD. 120 kmph

A train can travel 50 % faster than a car. Both start from point A at the same time and reach point B 75 kilometres away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car isA. 100 kmphB. 110 kmphC. 130 kmphD. 120 kmph

Byju's Answer Standard X Mathematics

Sum and Product of Roots of a Quadratic Equation

A train can t... Question

A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kilometres away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is

A 100 kmph B 110 kmph C 120 kmph D 130 kmph Open in App Solution

The correct option is **D **120 km/h

**Step 1, Given data**

Speed of the train is 50% more than the speed of the car

Distance = 75 km

Time lost by the train = 12.5 min =

12.5 60 h

**Step 2, Finding the speed**

Let the speed of the car be x kmph.

Then, speed of the train

= 150 x 100 = 3 x 2 km/h

According to the question

∴ 75 2 − 75 ( 3 2 ) x = 125 10 × 60 ⇒ 75 x − 50 x = 5 24 After solving ⇒ x = [ 25 × 24 50 ] = 120 km/h

Hence the speed of the car is 120 km/h

Sum and Product of Roots of a Quadratic Equation

Standard X Mathematics

Suggest Corrections 30

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## [Solved] A train can travel 50% faster than a car. Both start from po

Given: Speed of train = 150% of the speed of the car Formula used: Speed = Distance/Time Calculation: Let the speed of the car be x km/h So the spee

Home Quantitative Aptitude Speed Time and Distance

## Question

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## A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is

This question was previously asked in

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100 km/hr 110 km/hr 120 km/hr 130 km/hr

## Answer (Detailed Solution Below)

Option 3 : 120 km/hr

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## Detailed Solution

Download Solution PDF

**Given:**

Speed of train = 150% of the speed of the car

**Formula used:**

Speed = Distance/Time

**Calculation:**

Let the speed of the car be x km/h

So the speed of the train will be 1.5x km/h

According to the question

⇒ 75/x - 75/1.5x = 12.5/60

⇒ (112.5 - 75)/1.5x = 12.5/60

⇒ 37.5/1.5x = 12.5/60

⇒ 1.5x = 37.5 × (60/12.5)

⇒ x = 180/1.5 ⇒ x = 120 km/h

**∴ The speed of the car is 120 km/h**

**Concept used:**

When the distance is constant

Speed ∝ 1/TIme

**Calculation:**

The ratio of speed of the Tain and the Car is

⇒ 3 : 2

**Train**

**Car**

**Speed**

3 2

**Time**

2 3

The difference of the time is 12.5 minutes

⇒ 3x - 2x = 12.5/60 hours

⇒ x = 12.5/60 hour

Time taken by car is

⇒ 3 × 12.5/60 = 12.5/20

Speed of the car is ⇒ 75/(12.5/20) ⇒ (75 × 20)/12.5 ⇒ 120 km/h

**∴ The speed of the car is 120 km/h**

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