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a uniform chain of mass m and length l is resting on a rough table and it is about to slide as shown in figure. if it is given a slight disturbance so that it starts sliding, then total work done by frictional force is

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A chain of mass M and length l rests on a rough table with part overhanging. The chain starts sliding down by itself if overhanging part is l/3 . What will be the work performed by the friction force acting on the chain at the moment it slides completely off the table?

Click here👆to get an answer to your question ✍️ A chain of mass M and length l rests on a rough table with part overhanging. The chain starts sliding down by itself if overhanging part is l/3 . What will be the work performed by the friction force acting on the chain at the moment it slides completely off the table?

A chain of mass M and length l rests on a rough table with part overhanging. The chain starts sliding down by itself if overhanging part is

Question 3 l ​

. What will be the work performed by the friction force acting on the chain at the moment it slides completely off the table?

A

3 Mgl ​

B

3 2Mgl ​

C

9 2Mgl ​

D

9 Mgl ​ Medium Open in App

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A chain of mass m and length l rests on a roung surfced table so that one of its ends hangs over the edge. The

A chain of mass m and length l rests on a roung surfced table so that one of its ends hangs over the edge. The chain starts sliding off the table all by itsel

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Linear Momentum & Its Conservation

A chain of mass m and length l...

A chain of mass m and length l rests on a roung surfced table so that one of its ends hangs over the edge. The chain starts sliding off the table all by itself provided the overhanging part equals 1//3of the chain length. What will be the total work performed by the fricition forces acting on the chain by the moment is slides completely off the table ? Friction cofficient is mu

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Updated On: 12-03-2022

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A chain of mass m = 0.80 kg and length l = 1.5 m rests on a rough-surfaced table so that one of its ends hangs over the edge. The chain starts sliding off the table all by itself provided the overhanging part equals

η= 1 3 η=13

of the chain length. What will be the total work performed by the friction forces acting on the chain by the moment it slides completely off the table ?

12305920 6.4 K+ 6.6 K+ 8:51 A chain of mass m=0.80kg m=0.80kg and length l=1.5m l=1.5m

rests on a rough-surfaced table so that one of its ends hangs over the edge. The chain starts sliding off the table all by itself provided the overhanging part equals

η=1/3 η=1/3

of the chain length. What will be the total work performed by the friction forces acting on the chain by the moment it slides completely off the table?

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A uniform metal chain is placed on a rough table such that the one end of chain hangs down over the edge of the table, when one-third of its length hang over the edge, the chain starts sliding. Then the coefficient of static friction is

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A uniform metal chain is placed on a rough table such that the one end of chain hangs down over the edge of the table, when one-third of its length hang over the edge, the chain starts sliding. Then the coefficient of static friction is

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Very Important Questions

Prove that two triangles having the same base and equal areas lie between the same parallels.

In Figure, D,E D,E are points on sides AB AB and AC AC respectively of ABC, ABC, such that ar(BCE)=ar(BCD) . ar(BCE)=ar(BCD).

Show that `DE ll BC .

ABC ABC

is a triangle in which

D D is the mid-point of BC BC and E E is the mid-point of AD . AD. Prove that area of BED= 1 4 areaofABC . BED=14areaofABC. ABCD ABCD is a parallelogram X X and Y Y

are the mid-points of

BC BC and CD CD

respectively. Prove that

ar(AXY)= 3 8 ar(^(gm)ABCD)

ar(AXY)=38ar(^(gm)ABCD)

The area of a trapezium is half the product of its height and the sum of parallel sides. GIVEN : A trapezium

ABCD ABCD in which AB∣∣CD;AB=a,DC=b AB∣∣CD;AB=a,DC=b and AL=CM=h, AL=CM=h, where AL⊥DC AL⊥DC and CM⊥AB CM⊥AB . TO PROVE : ar(trap.ABCD)= 1 2 h(a+b)

ar(trap.ABCD)=12h(a+b)

construction : Join AC AC In Figure, ABCD ABCD

is a trapezium in which

ABDC ABDC and DC=40cm DC=40cm and AB=60cm . AB=60cm. If X X and Y Y

are, respectively, the mid-points of

AD AD and BC BC , prove that : XY=50cm XY=50cm DCYX DCYX is a trapezium ar(trap D . CYX)= 9 11 ar(trap XYBA .

ar(trapD.CYX)=911ar(trapXYBA.

FAQs on Linear Momentum & Its Conservation

Work Done By A Force

Nature Of The Work Done

Work Depends On The Frame Of Reference

Graphical Representation Of Work

Work Done By A Variable Force

Work Done By Gravitational Forces

Work Done By Static And Kinetic Friction

Work Done By Spring Forces

Work Done By Interacting Forces

Work Done By Pseudo Force

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31 FRICTION

Learning Objectives

Discuss the general characteristics of friction.

Describe the various types of friction.

Calculate the magnitude of static and kinetic friction.

Friction is a force that is around us all the time that opposes relative motion between surfaces in contact but also allows us to move (which you have discovered if you have ever tried to walk on ice). While a common force, the behavior of friction is actually very complicated and is still not completely understood. We have to rely heavily on observations for whatever understandings we can gain. However, we can still deal with its more elementary general characteristics and understand the circumstances in which it behaves.

Friction

Friction is a force that opposes relative motion between surfaces in contact.

One of the simpler characteristics of friction is that it is parallel to the contact surface between surfaces and always in a direction that opposes motion or attempted motion of the systems relative to each other. If two surfaces are in contact and moving relative to one another, then the friction between them is called kinetic friction. For example, friction slows a hockey puck sliding on ice. But when objects are stationary, static friction can act between them; the static friction is usually greater than the kinetic friction between the surfaces.

Kinetic Friction

If two surfaces are in contact and moving relative to one another, then the friction between them is called kinetic friction.

Imagine, for example, trying to slide a heavy crate across a concrete floor—you may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion it is easier to keep it in motion than it was to get it started, indicating that the kinetic friction force is less than the static friction force. If you add mass to the crate, say by placing a box on top of it, you need to push even harder to get it started and also to keep it moving. Furthermore, if you oiled the concrete you would find it to be easier to get the crate started and keep it going (as you might expect).

(Figure)is a crude pictorial representation of how friction occurs at the interface between two objects. Close-up inspection of these surfaces shows them to be rough. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. A considerable force can be resisted by friction with no apparent motion. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them. Part of the friction is due to adhesive forces between the surface molecules of the two objects, which explain the dependence of friction on the nature of the substances. Adhesion varies with substances in contact and is a complicated aspect of surface physics. Once an object is moving, there are fewer points of contact (fewer molecules adhering), so less force is required to keep the object moving. At small but nonzero speeds, friction is nearly independent of speed.

Frictional forces, such as , always oppose motion or attempted motion between surfaces in contact. Friction arises in part because of the roughness of the surfaces in contact, as seen in the expanded view. In order for the object to move, it must rise to where the peaks can skip along the bottom surface. Thus a force is required just to set the object in motion. Some of the peaks will be broken off, also requiring a force to maintain motion. Much of the friction is actually due to attractive forces between molecules making up the two objects, so that even perfectly smooth surfaces are not friction-free. Such adhesive forces also depend on the substances the surfaces are made of, explaining, for example, why rubber-soled shoes slip less than those with leather soles.

The magnitude of the frictional force has two forms: one for static situations (static friction), the other for when there is motion (kinetic friction).

When there is no motion between the objects, the magnitude of static friction is

where is the coefficient of static friction and is the magnitude of the normal force (the force perpendicular to the surface).

Magnitude of Static Friction

Magnitude of static friction is

where is the coefficient of static friction and is the magnitude of the normal force.

The symbol means less than or equal to, implying that static friction can have a minimum and a maximum value of . Static friction is a responsive force that increases to be equal and opposite to whatever force is exerted, up to its maximum limit. Once the applied force exceeds , the object will move. Thus

Once an object is moving, the magnitude of kinetic friction is given by

where is the coefficient of kinetic friction. A system in which is described as a system in which friction behaves simply.

Magnitude of Kinetic Friction

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