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    A container contains a mixture of two liquids P and Q in the ratio 7:5 .When 9 litres of mixture are drawn off and the container is filled with Q , the ratio of P and Q becomes 7:9 .How many litres of liquid P was contained in the container initially?

    Click here👆to get an answer to your question ✍️ A container contains a mixture of two liquids P and Q in the ratio 7:5 .When 9 litres of mixture are drawn off and the container is filled with Q , the ratio of P and Q becomes 7:9 .How many litres of liquid P was contained in the container initially?

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    A container contains a mixture of two liquids P and Q in the ratio 7:5.When 9 litres of mixture are drawn off and the container is filled with Q, the ratio of P and Q becomes 7:9.How many litres of liquid P was contained in the container initially?

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    [Solved] A vessel contains a mixture of P and Q in the ratio of 5 : 3

    Given: A vessel contains a mixture of P and Q in the ratio of 5 : 3. 16 liters of the mixture is taken out and 5 liters of P is poured in. The new mixture ha

    Home Quantitative Aptitude Mixture Problems To Make a Mixture from Two or More Things

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    A vessel contains a mixture of P and Q in the ratio of 5 : 3. 16 liters of this mixture is taken out and 5 liters of P is poured in. The new mixture has ratio of P to Q as 11 : 6. Find the total original quantity of mixture.

    80 liters 96 liters 98 liters 84 liters

    Answer (Detailed Solution Below)

    Option 2 : 96 liters

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    Detailed Solution

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    Given:

    A vessel contains a mixture of P and Q in the ratio of 5 : 3.

    16 liters of the mixture is taken out and 5 liters of P is poured in.

    The new mixture has ratio of P to Q as 11 : 6.

    Calculation:Short Trick:

    total original quantity of mixture = 80 + 16 = 96 liters

    Detailed Solution:

    P = 5x, Q = 3x

    The quantity of P and Q in 16 liters of the mixture,

    Quantity of P = (16 × 5x)/8x = 10

    Quantity of Q = (16 × 3x)/8x = 6

    Now, 5 liters of P poured in and then ratio becomes 11 ∶ 6

    (5x - 10 + 5)/(3x - 6) = 11/6

    (5x - 5)/(3x - 6) = 11/6

    Solve, x = 12

    So total mixture originally = 8x  = 8 × 12 = 96 liters

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    A vessel contains a mixture of liquid P and Q in the ratio of 3:2. When 20 litres of the mixture is taken out and replaced with 20 litres of liquid Q, the ratio changes to 1:4. How many litres of liquid P were initially present in the vessel?

    Answer (1 of 5): * Statement of the given problem, * * A vessel contains a mixture of liquid P and Q in the ratio of 3 : 2. When 20 litres of the mixture is taken out and replaced with 20 litres of liquid Q, the ratio changes to 1 : 4. How many litres of liquid P were initially present in the...

    A vessel contains a mixture of liquid P and Q in the ratio of 3:2. When 20 litres of the mixture is taken out and replaced with 20 litres of liquid Q, the ratio changes to 1:4. How many litres of liquid P were initially present in the vessel?

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    Sort Antonio Daniels

    Former Learner 2020- ChemistAuthor has 5.3K answers and 2.3M answer views6mo

    P/Q=3/2

    2/5X -2/5(20) + 20 = 4/5X

    X = 30 P??? 3/5(30) = 18 L Related questions

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    Tamoghna Mukhopadhyay

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    Say, initially there was p litres of P & q litres of Q.

    Total initial volm = p+q litres

    In the taken 20 litres there were 12 litres of P & 8 litres of Q.

    After taking 20 litres of Q instead, there were p-12 litres of P & q-8+20 litres of Q. This ratio is 1:4.

    From the initial condition,

    p/q = 3/2 Or, p= 3q/2 =1.5q

    From the final condition,

    (p-12)/(q+12) = 1/4 Or, 4p-48 = q+12 Or, p= (q+60)/4 Or, 4*1.5q = q+60 Or, 6q = q+60 Or, 5q = 60 Or, q = 12 litres.

    p = 1.5*12 = 18 litres.

    Syamal Dey

    Ph.D., Former Sr. Scientist, University of Maryland, USAAuthor has 6.5K answers and 3.7M answer views6mo

    Statement of the given problem,

    A vessel contains a mixture of liquid P and Q in the ratio of 3 : 2. When 20 litres of the mixture is taken out and replaced with 20 litres of liquid Q, the ratio changes to 1 : 4. How many litres of liquid P were initially present in the vessel?

    Let PV & QV denote the amounts (in L) of P & V present in the initial mixture respectively.

    Hence from above data we get following relations,

    PV : QV = 3 : 2 or QV = (2/3)*PV

    [PV - 3*20/(3 + 2)] : [QV - 2*20/(3 + 2) + 20] = 1 : 4

    or (PV - 12) : (QV - 8 + 20) = 1 : 4

    or (PV - 12) : (QV + 12) = 1 : 4

    or 4*PV - 48 = QV + 12

    or 4*PV Related questions

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    Let “V”- litres of milk be in the container.

    After removing 20- litres of the mixture the volume of Q - in the mixture= (V-20) x 3/5

    On adding 20- Litres of Q- to the mixture, the volume of pure Q in the new mixture =(V-20)3/5 + 20 .

    This is now equal to =Vx 4/5

    So (V-20)3/5 + 20= Vx4/5

    So V/5= (20–12)= 8 So V= 40 Litres

    Therefore total volume of the mixture =40 litres

    So volume of “P”- in the initial mixture = 40 x (2/5)

    स्रोत : www.quora.com

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