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An α particle moves in a circular path of radius 0.83 cm in the presence of a magnetic field of 0.25 Wb/m2. The de Broglie wavelength associated with the particle will be:

An α particle moves in a circular path of radius 0.83 cm in the presence of a magnetic field of 0.25 Wb/m2. The de Broglie wavelength associated with the particle will be:

Byju's Answer Standard XII Physics Maxwell's Equations An α-particle... Question

An α-particle moves in a circular path of radius

0.83 cm

in the presence of a magnetic field of

0.25 Wb/m2

. The de Broglie wavelength associated with the particle will be:

A 1 A˙ B 0.1 A˙ C 10 A˙ D 0.01 A˙ Open in App Solution

The correct option is D

0.01 A˙

Step 1: Given

Charge of alpha particle:

q=2e=2×1.6×10-19

Radius of circular path:

R=0.83 cm=0.83 ×10-2m

Strength of magnetic field:

B=0.25 Wb/m2

Step 2: Formula Used

R=mvBq λ=hmv

Step 3: Find the de Broglie wavelength

Calculate the value of the product of mass and velocity

R=mvBq ⇒mv=RBq

⇒mv=0.83 m×10-2×0.25×2×1.6×10-19

Calculate the de Broglie wavelength by using the formula

λ=hmv

and substituting the values

λ=6.6×10-340.83 ×10-2×0.25×2×1.6×10-19

=6.6×10-346.6×10-22 =1×10-12 =0.01 A˙

Hence, Option (D) is correct. the de Broglie wavelength is

0.01 A˙

.

Suggest Corrections 1

SIMILAR QUESTIONS

Q. An

α

-particle moves in a circular path of radius

0.83 cm

in the presence of a magnetic field of

0.25 Wb/m 2

. The de-Broglie wavelength associated with the particle will be

Q. An particle moves in a circular path of radius 0.83 cm in the presence of a magnetic field of 0.25 Wb

m 2

. The de Broglie wavelength associated with the particle will be :

Q.

An α

particle moves in circular path of radius

0.83 c m

in the presence of a magnetic field of

0.25 W b / m 2

. Find the De Broglie wavelength associated with the particle

Q. An

α

particle is moving in a circular path of radius in the presence of magnetic field B. The de-Broglie wavelength associated with the particle will be

( q → c h a r g e o n α p a r t i c l e )

Q.

An a-particle moves in a circular path of radius 0.83cm in the presence of a magnetic field of 0.25wb/m^2. The de-broglie wavelength associated with the particle will be

1-10A 2-0.01A 3-1A 4-0.1A View More RELATED VIDEOS

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A alpha particle moves in a circular path of radius 0.83 cm in the presence of a magnetic field is 0.25 Wb/m^2 . the de brogile wavelength association with the particle will be

Click here👆to get an answer to your question ✍️ A alpha particle moves in a circular path of radius 0.83 cm in the presence of a magnetic field is 0.25 Wb/m^2 . the de brogile wavelength association with the particle will be

A α particle moves in a circular path of radius 0.83 cm in the presence of a magnetic field is 0.25Wb/m

Question 2

. the de brogile wavelength association with the particle will be

A10A

0

B0.01A

0

C1A

0

D0.1A

0 Hard Open in App

Updated on : 2022-09-05

Solution Verified by Toppr

Correct option is B)

R= qB mV ​ = qB P ​ (P=mV (momantum) ) R= qB P ​ 0.83×10 −2 = q×0.25 P ​

(charge of α particle =+2e charge)

​ p λ= P h ​ ​ =0.664×10 −21 = 0.664×10 −21 6.6×10 −34 ​ =9.96×10 13 =10×10 −13 =0.01 A 0 ​

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A alpha

We know R = (mv)/(qB) and lambda = (h)/(mv) implies lambda = (h)/(qBR) = (6.6 xx 10^(-34))/(1.6xx10^(-19)xx0.83xx10^(-2)xx0.25) = 0.01 Å

A α

-parhticle moves in a circular path of radius

0.83 c m

in the presence of a magnetic field of

0.25 W b / m 2

. The de-Broglie wavelength assocaiated with the particle will be

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A2Z-SOURCE AND EFFECT OF MAGNETIC FIELD-AIPMTNEET QUESTIONS

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Updated On: 27-06-2022

লিখিত জবাব A 0.01 Å B 1 Å C 0.1 Å D 10 Å Answer

The correct Answer is A

Solution We know R = m v q B and λ = h m v ⇒ λ = h q B R = 6.6 × 10 − 34 1.6 × 10 − 19 × 0.83 × 10 − 2 × 0.25 = 0.01 Å উত্তর

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642677174 Text Solution A α

-parhticle moves in a circular path of radius

0.83 c m

in the presence of a magnetic field of

0.25 W b / m 2

. The de-Broglie wavelength assocaiated with the particle will be

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0.83

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