# an army contingent of 612 members is to march behind an army band of 48 members in a parade. the two group are to march in the same number of columns. what is the maximum number of columns in which they can march?

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## An army contingent of 612 members is to march behind an army band of 48 columns in a parade. The two groups are to march in the same number of columns. What is the maximum number of columns in which they can march?

Click here👆to get an answer to your question ✍️ An army contingent of 612 members is to march behind an army band of 48 columns in a parade. The two groups are to march in the same number of columns. What is the maximum number of columns in which they can march?

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## An army contingent of 612 members is to march behind an army band of 48 columns in a parade. The two groups are to march in the same number of columns. What is the maximum number of columns in which they can march?

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An army contingent of 612 members is to march behind an army band of 48 members.

Here, HCF of 612 and 48 will give the maximum number of columns in which the two groups can march.

So, using Euclid's division algorithm

612=48×12+36 ⇒48=36×1+12 →36=12×3+0 ∴HCF(612,48)=12

Hence, the maximum no of columns in which they can march is 12

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## An army contingent of 612 members is to march behind an army band of 48 members in a parade.

An army contingent of 612 members is to march behind an army band of 48 members in a parade. ... maximum number of columns in which they can march?

## An army contingent of 612 members is to march behind an army band of 48 members in a parade.

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## An army contingent of 612 members is to march behind an army band of 48 members in a parade. The two groups are to march in the same number fo columns. What is the maximum number of columns in which they can march ?

Clearly, the maximum number of Columns = HCF ( 612,48) Now ,612 = (2^(2) xx 3^(2) xx 17) and 48 = ( 2^(4) xx 3) HCF = ( 612,48) = ( 2^(2) xx3) = ( 4xx3) = 12 Requreid number of columns = 12

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An army contingent of 612 memb...

An army contingent of 612 members is to march behind an army band of 48 members in a parade. The two groups are to march in the same number fo columns. What is the maximum number of columns in which they can march ?

Updated On: 27-06-2022

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Text Solution Open Answer in App Solution

Clearly, the maximum number of

Columns = HCF ( 612,48)

Now ,612=( 2 2 × 3 2 ×17) ,612=(22×32×17) and 48=( 2 4 ×3) 48=(24×3) HCF = (612,48)=( 2 2 ×3)=(4×3)=12

(612,48)=(22×3)=(4×3)=12

Requreid number of columns = 12

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Guys, does anyone know the answer?