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ayush and deeksha made pictures. ayush made his picture on a rectangular sheet of length 60 cm and breadth of 20 cm while deeksha made hers on a rectangular sheet of length 40 cm and breadth 35 cm. both these pictures have to be separately framed. find the difference between their costs of framing, if the cost of framing is ₹3 per cm.

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get ayush and deeksha made pictures. ayush made his picture on a rectangular sheet of length 60 cm and breadth of 20 cm while deeksha made hers on a rectangular sheet of length 40 cm and breadth 35 cm. both these pictures have to be separately framed. find the difference between their costs of framing, if the cost of framing is ₹3 per cm. from screen.

Ayush and Deeksha made pictures Ayush made his picture on the rectangular sheet of length 60cm and breadth

Ayush and Deeksha made pictures Ayush made his picture on the rectangular sheet of length 60cm and breadth 20cm while deekhsha made hers on a rectangular sheet of length 40cm and breatmdth 35cm Both these pictures have to be separately framed and laminated Who has to - Maths - Perimeter and Area

Ifrah, asked a question

Subject: Maths, asked on 19/12/16

Ayush and Deeksha made pictures . Ayush made his picture on the rectangular sheet of length 60cm and breadth 20cm while deekhsha made hers on a rectangular sheet of length 40cm and breatmdth 35cm. Both these pictures have to be separately framed and laminated. Who has to pay more for framing, if the cost of framing is rs 3.00 per cm If the cost of laminationis rs 2.00 per cm2 , whi has to pay more for lamination ?

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Lovina Kansal answered this

Dear student

Ayush's Case:Perimeter of rectangular sheet=2l+b=260+20cm=160cmCost of framing=Rs3×160=Rs480Area of rectangular sheet=l×b=60×20=1200cm2Cost of lamination=Rs2×1200=Rs2400cm2Deeksha'S case:Perimeter of rectangular sheet=2l+b=240+35cm=150cmCost of framing=Rs3×150=Rs450Area of rectangular sheet=l×b=40×35=1400cm2Cost of lamination=Rs2×1400=Rs2800cm2So,  Ayush will pay more for framing and Deeksha will pay more for lamination.

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NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area InText Questions

CBSE students can refer to NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area InText Questions and Answers are provided by experts in order to help students secure good marks in exams. Class 7 Maths NCERT Solutions Chapter 11 Perimeter and Area InText Questions Try These (Page 205) Question 1. Ayush and Deeksha […]

NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area InText Questions

CBSE students can refer to NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area InText Questions and Answers are provided by experts in order to help students secure good marks in exams.

Class 7 Maths NCERT Solutions Chapter 11 Perimeter and Area InText Questions

Try These (Page 205)

Question 1.

Ayush and Deeksha made pictures. Ayush made his picture on a rectangular sheet of length 60 cm and breadth 20 cm while Deeksha made hers on a rectangular sheet of length 40 cm and breadth 35 cm. Both of these pictures have to be separately framed and laminated. Who has to pay more for framing, if the cost of framing is ₹ 3.00 per cm?

If the rate of lamination is ₹ 2.00 per cm2, who has to pay more for lamination?

Solution:

For finding the cost of framing, we need to find the perimeter and then multiple it by the rate for framing.

In case of Ayush :

Perimeter of the rectangular sheet = 2 (Length + Breadth)

= 2 × (60 + 20) cm = 2 × 80 cm = 160 cm

∴ Cost of framing at the rate of ₹ 3 per cm

= ₹ (3 × 160) = ₹ 480

In case of Deeksha :

Perimeter of the rectangular sheet

= 2 × (40 + 35) cm

= 2 × 75 cm = 150 cm

∴ Cost of framing at the rate of ₹ 3 per cm

= ₹ (3 × 150) = ₹ 450

Thus, Ayush paid more for framing (as 480 > 450).

For finding the cost of lamination, we need to find the area and then multiply it by the rate for lamination.

In the case of Ayush :

Area of the rectangular sheet

= (60 × 20) cm2 =1200 cm2

∴ Cost of lamination at the rate of ₹ 2 per cm2

= ₹ (2 × 1200) = ₹ 2400

In the case of Deeksha :

Area of the rectangular sheet

= (40 × 35) cm2 = 1400 cm2

∴ Cost of lamination at the rate of ₹ 2 per cm2

= ₹ (2 × 1400) = ₹ 2800

Thus, Deeksha paid more for lamination (as 2800 > 2400).

Try These (Page 205)

Question 1.

What would you need to find, area, or perimeter to answer the following?

(i) How much space does a blackboard occupy?

Solution:

For finding the space occupied by a blackboard, we should find the area of the blackboard.

(ii) What is the length of a wire required to fence a rectangular flower bed?

Solution:

For fencing a rectangular flower bed, we need to find the perimeter of the flower bed.

(iii) What distance would you cover by taking two rounds of a triangular park?

Solution:

For finding the distance covered by taking two rounds of a triangular park, we need to find the perimeter of the park and then multiply it by 2.

(iv) How much plastic sheet do you need to cover a rectangular swimming pool?

Solution:

For finding the plastic sheet required to cover a rectangular swimming pool, we need to find the area of the pool.

Try These (Page 206)

Question 1.

Tanya needed a square of side 4 cm for completing college. She had a rectangular sheet of length 28 cm and breadth 21 cm [See fig. (i)] She cuts off a square of side 4 cm from the rectangular sheet. Her friend saw the remaining sheet

[See fig.(ii)] and asked Tanya, “Has the perimeter of the sheet increased or decreased now?”

(i) Has the total length of side AD increased after cutting off the square?

Solution:

There has been a change in the length of side AD after cutting the square.

(ii) Has the area increased or decreased?

Solution:

The area has decreased.

(iii) Tanya cuts off one more square from the opposite side. (See fig.) Will (the perimeter of the remaining sheet increase further?

Solution:

Yes, the perimeter increases.

(iv) Will the area increase or decrease further?

Solution:

The area will decrease.

(v) So, what can we infer from this?

Solution:

Clearly, if the perimeter increases, it is not necessary that the area also increases.

Try These (Page 206)

Question 1.

Experiment with several such shapes and cut-outs. You might find it useful to draw these shapes on squared sheets and compute their areas and perimeters. You have seen that increase in perimeter does not mean that area will also increase.

Solution:

Do yourself (Based on the experiment).

Question 2.

Give two. examples where area increases as the perimeter increases.

Solution: (i)

Consider a rectangle ABCD.

Area (ABCD) = A1 = 8 × 3 cm2 = 24 cm

Perimeter (ABCD) = P1 = 2(8 + 3) cm = 22 cm

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ayush and deekhsa made a picture.ayush made his picture on a rectangular sheet of the length 60 cm and

Ayush and deekhsa made a picture.ayush made his picture on a rectangular sheet of the length 60 cm and breadth… Get the answers you need, now!

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