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# calculate the mole fraction of toluene in the vapour phase which is in equilibrium

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## Calculatethe mole fraction of toluene in the vapour phase which is in equilibrium with a solution of benzene and toluene having a mole fraction of toluene 0.5. (The vapour pressure of pure benzene is 119 torr and that of toluene is 37 torr at the same temperature)

Calculatethe mole fraction of toluene in the vapour phase which is in equilibrium with a solution of benzene and toluene having a mole fraction of toluene 0.5. (The vapour pressure of pure benzene is 119 torr and that of toluene is 37 torr at the same temperature) Elevation in Boiling Point

Calculatethe ... Question

Calculatethe mole fraction of toluene in the vapour phase which is in equilibrium with a solution of benzene and toluene having a mole fraction of toluene 0.5. (The vapour pressure of pure benzene is 119 torr and that of toluene is 37 torr at the same temperature)

Open in App Solution Suggest Corrections 9 SIMILAR QUESTIONS

Q. Benzene and toluene form an ideal solution. Vapour Pressure of pure benzene is 100 torr while that of pure toluene is 50 torr. If mole fraction of benzene in liquid phase is

1 3

, calculate the mole fraction of benzene in vapour phase.

Q. A cylinder contains

0.9

moles of benzene vapour and

0.1

moles of toluene vapour at

50 o C

. The pure vapour pressure of benzene liquid and the pure vapour pressure of toluene liquid at

50 o

C are 600 torr and 200 torr respectively.

What is the mole fraction of liquid benzene in the solution?

Q. Vapour pressure of pure benzene is

119 torr and of toluene is 37.0 torr

at the same temperature. Then mole fraction of toluene in vapour phase which is in equilibrium with a solution of benzene and toluene having a mole fraction of toluene

0.50 , will be:

Q. Calculate the mole fraction of toluene in the vapour phase which is in equilibrium with a solution of benzene and toluene having a mole fraction of toluene 0.50. The vapour pressure of pure benzene is 119 torr; that of toluene is 37 torr at the same temperature. ( If the answer is

x , then write x × 10 − 3

)(rounding off to 3 digits)

Q. What is the composition of the vapour which is in equilibrium at

30 ∘ C

with a benzene-toluene solution with a mole fraction of benzene of

0.40 ?

and with a mole fraction of benzene of

0.60 ? [ P ∘ b = 119 torr and P ∘ t = 37 torr] View More

स्रोत : byjus.com

## Calculate the mole fraction of toluene in the vapour phase which is in equilibrium with a solution of benzene and toluene having a mole fraction of toluene 0.50. The vapour pressure of pure benzene is 119 torr; that of toluene is 37 torr at the same temperature. ( If the answer is x , then write x × 10^

Click here👆to get an answer to your question ✍️ Calculate the mole fraction of toluene in the vapour phase which is in equilibrium with a solution of benzene and toluene having a mole fraction of toluene 0.50. The vapour pressure of pure benzene is 119 torr; that of toluene is 37 torr at the same temperature. ( If the answer is x , then write x × 10^-3 )(rounding off to 3 digits) Calculate the mole fraction of toluene in the vapour phase which is in equilibrium with a solution of benzene and toluene having a mole fraction of toluene 0.50. The vapour pressure of pure benzene is 119 torr; that of toluene is 37 torr at the same temperature. ( If the answer is x, then write x×10

Question −3

)(rounding off to 3 digits)

Hard Open in App

Updated on : 2022-09-05

Solution Verified by Toppr

Correct option is A)

The partial pressure of toluene in the vapour phase is

P T ​ =P T 0 ​ X T ​

=37 torr×0.5=18.5 torr.

Here, P T 0 ​

is the vapour pressure of pure toluene and X

T ​

is the mole fraction of toluene in the liquid phase.

The partial pressure of benzene in the vapour phase is

P B ​ =P B 0 ​ X B ​

=119 torr×0.5=59.5 torr.

Here, P B 0 ​

is the vapour pressure of pure benzene and X

B ​

is the mole fraction of benzene in the liquid phase.

The total pressure is P

T ​ +P B ​

=18.5 torr+59.5 torr=78 torr.

The mole fraction of toluene in the vapour phase is Y

T ​ .

It is given by the expression Y

T ​ = totalpressure P T ​ ​ = 78 18.5 ​ =0.237.

Hence, the mole fraction of toluene in the vapour phase is 0.237.

Hence the correct answer is 237

Solve any question of Solutions with:-

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## Calculate the mole fraction of toluence in the vapour phase which is in equilibrium with a solution of benzene and toluene having a mole fraction of toluene 0.50. The vapour pressure of pure benzene is 199 torr, that of toluene is 37 torr at the same temperature.

C(6)H(6)"-A",C(7)H(8)"-B" X("B")=0.50,X("A")=1-0.5 =0.5 Pt=X("A")P("B")^(0)+X("B")P("B")^(0),P("B")=X("B")P("B")^(0) Y("B")=(P("B"))/(Pt) (X("B")P("B")^(0))/(X("A")P("A")^(0)+X("B")P("B")^(0))=(0.5xx37)/(0.5xx119+0.5xx37)=37/156=0.237 Home > English > Class 12 > Chemistry > Chapter > Solutions >

Calculate the mole fraction of...

Calculate the mole fraction of toluence in the vapour phase which is in equilibrium with a solution of benzene and toluene having a mole fraction of toluene 0.50. The vapour pressure of pure benzene is 199 torr, that of toluene is 37 torr at the same temperature.

Updated On: 27-06-2022

Solution

`C_(6)H_(6)"-A",C_(7)H_(8)"-B"`

`X_("B")=0.50,X_("A")=1-0.5`

=0.5

`Pt=X_("A")P_("B")^(0)+X_("B")P_("B")^(0),P_("B")=X_("B")P_("B")^(0)`

`Y_("B")=(P_("B"))/(Pt)`

`(X_("B")P_("B")^(0))/(X_("A")P_("A")^(0)+X_("B")P_("B")^(0))=(0.5xx37)/(0.5xx119+0.5xx37)=37/156=0.237` Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

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