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    compare the rate of radiation of metal body at 727°c and 227°c

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    Compare the rates of emission of heat of a black body maintained at 727^oC with 227^oC . If the black body is surrounded by an enclosure (black) at 27^oC , what would be the ratio of their rates of loss of heat.

    Click here👆to get an answer to your question ✍️ Compare the rates of emission of heat of a black body maintained at 727^oC with 227^oC . If the black body is surrounded by an enclosure (black) at 27^oC , what would be the ratio of their rates of loss of heat.

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    Compare the rates of emission of heat of a black body maintained at 727

    Question o C with 227 o

    C. If the black body is surrounded by an enclosure (black) at 27

    o

    C, what would be the ratio of their rates of loss of heat.

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    Updated on : 2022-09-05

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    A black body emits maximum radiation near wave length λ

    8 1 SIMILAR QUESTIONS m ​

    . the emissivity of the material is 0.7 if the absolute temperature of the black body is doubled, then

    This question has multiple correct options

    Two copper metal spheres A and B of same mass and surface areas at temperatures at T

    Medium View solution > A ​ =80 o C and T B ​ =50 o

    C are kept separated in a heat resistant box. Due to ______ temperatures of A and B are changing and reaching a constant temperature of ______ C. Heat transfer takes place by ______, but if both spheres are in contact heat transfer is by _______. 

    Medium View solution >

    Which of the  following is more close to a black body? 

    For a black body at a temperature of 727

    Medium View solution > ∘

    C, Its radiated power is 60 watt and temperature of the surrounding is 227

    C If the temperature of the black body is changed to 1227

    C, Then its radiating power will be   

    The υ

    Medium View solution > m ​

    curve for a perfect black body is -

    Medium View solution > MORE FROM CHAPTER

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    Compare the rate of radiation of metal body at 727 ""^(@)C and 227 ""^(@)C.

    Compare the rate of radiation of metal body at 727 ""^(@)C and 227 ""^(@)C.

    Home > English > Class 12 > Physics > Chapter > Question Bank 2021 >

    Compare the rate of radiation ...

    Compare the rate of radiation of metal body at 727

    ∘ C ∘C and 227 ∘ C ∘C .

    Updated On: 27-06-2022

    00 : 010

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    Text Solution Open Answer in App Answer

    The correct Answer is 16

    Answer

    Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

    Related Videos

    645039414 0 4.3 K 1:55

    यदि एक कृष्णिका 10 कैलोरी/से विकिरित करती है। कृष्णिका का ताप

    227 ∘ C 227∘C है। यदि ताप 727 ∘ C 727∘C

    कर दिया जाए, तो विकिरण की दर होगी

    639275027 0 6.6 K 2:43 With rate of 7 cal cm −2 s −1 7 cal cm-2s-1

    , radiations are emitted from the black body at

    227 ∘ C 227∘C

    , the rate of emitted radiations at

    727 ∘ C 727∘C

    will be . . . . . . .

    11749687 100 1.8 K 2:00 A black body at 227 ∘ C 227∘C

    radiates heat at the rate of cal

    c m −2 s −1 cm-2s-1

    . At a temperature of

    727 ∘ C 727∘C

    , the rate of heat radiated in the same unit will be

    646941412 16 8.9 K 3:45 A black body at 227 ∘ C 227∘C

    radiates heat at the rate of

    7cals/c m −2 s −1 7cals/cm-2s-1 At a temperature of 727 ∘ C 727∘C

    ,the rate of heat radiated in the same units will be

    644162141 20 8.3 K

    If a black body radiates 10 calories per second at

    227 ∘ C 227∘C

    , it will radiate at

    727 ∘ C 727∘C

    455366602 0 500

    একটি কৃষ্ণবস্তু deg 227 C উষ্ণতায় 7cal/সিএম^2 হারে শক্তি বিকিরণ করে।ওই একই এককে deg 727 C উষ্ণতায় বস্তুটির শক্তি বিকিরনের হার হবে

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    Compare the rate of radiation of metal bodies at 727 °C and 227 °C.

    Compare the rate of radiation of metal bodies at 727 °C and 227 °C.

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    Compare the rate of radiation of metal bodies at 727 °C and 227 °C.

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    SOLUTION

    Given:

    T1 = 727 °C = 727 + 273 = 1000 K,

    T2 = 227 °C = 227 + 273 = 500 K

    To find: Ratio of radiation

    [(dQdt)1(dQdt)2]

    Formula:

    σ dQdt=σAeT4

    Calculation: 

    From formula, σ (dQdt)1=σAeT14 ...............(1) σ (dQdt)2=σAeT24 ...............(2)

    Dividing equation (1) by (2),

    σ σ

    (dQdt)1(dQdt)2=σAeT14σAeT24=(T1T2)4

    = (1000)4(500)4=16

    The rate of radiation of the metal sphere at 727 °C and 227 °C is 16:1. 

    Concept: Interpretation of Temperature in Kinetic Theory

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    Chapter 3: Kinetic Theory of gases and Radiation - Short Answer I

    Q 6 Q 5 Q 7

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    SCERT Maharashtra Question Bank 12th HSC 2022 Physics (Science) by Maharashtra State Board

    Chapter 3 Kinetic Theory of gases and Radiation

    Short Answer I | Q 6

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