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# e is a point on the side ad produced of a parallelogram

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## E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that ABE ∼ CFB .

Click here👆to get an answer to your question ✍️ E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that ABE ∼ CFB . Class 10 >>Maths >>Triangles

>>Criteria for Triangle Similarity

>>E is a point on the side AD produced of

Question

## E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that △ABE∼△CFB.

Medium Open in App

Updated on : 2022-09-05

In △ABE and △CFB,

Solution Verified by Toppr

∠ABE=∠CFB (Alternate angles)

∠BAE=∠BCF (opposite angles of a parallelogram)

∴ By AA criterion of similarity, △ABE ∼ △CFB Video Explanation Solve any question of Triangles with:-

Patterns of problems

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स्रोत : www.toppr.com

## Question 8 E is a point on the side AD produced of a parallelogram ABCD and BE intersect CD at F. Show that Δ ABE ∼Δ CF B.

Question 8 E is a point on the side AD produced of a parallelogram ABCD and BE intersect CD at F. Show that Δ ABE ∼Δ CF B. Byju's Answer Standard X Mathematics AAA Similarity Question 8 E ... Question Question 8

E is a point on the side AD produced of a parallelogram ABCD and BE intersect CD at F. Show that

Δ A B E ∼ Δ C F B . Open in App Solution In Δ A B E and Δ C F B , ∠ A = ∠ C

(Opposite angles of a parallelogram)

∠ A E B = ∠ C B F

(Alternate interior angles as AE || BC)

∴ Δ A B E ∼ Δ C F B

(By AAA similarity criterion)

Suggest Corrections 13 Video Solution NCERT - Grade 10 - Mathematics - Triangles - Q21

MATHEMATICS

07:37 Min | 72 Views

Rate SIMILAR QUESTIONS

Q.

E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that ΔABE ∼ ΔCFB

Q. In the figure given below,

E

is a point on the side

A D

produced of a parallelogram

A B C D and B E intersects C D at F . Show that △ A B E ∼ △ C F B . Q.

State True or False-

E is a point on the side produced of a parallelogram and intersects at F.

△ A B E is similar to △ C F B :

Q. Point E bisects side CD of a parallelogram ABCD and CF intersects DA produced at G such that

C F | | A E

, where F is a point on AB. The value of

A D × G F – C F × A G is

Q.

A B C D

is a parallelogram. The circle through

A , B and C intersect C D

(produced if necessary) at

E . Prove that A E = A D . View More EXPLORE MORE AAA Similarity

Standard X Mathematics

स्रोत : byjus.com

## Ex 6.3, 8

Ex 6.3, 8 E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that ΔABE ∼ ΔCFB Given: A parallelogram ABCD where E is point on side AD produced & BE intersects CD at F To Prove: ΔABE ∼ ΔCFB. Proof: In parallelogram ABCD , opposite angles are Check sibling questions

## Ex 6.3, 8 - Chapter 6 Class 10 Triangles (Term 1)

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### Transcript

Ex 6.3, 8 E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that ΔABE ∼ ΔCFB Given: A parallelogram ABCD where E is point on side AD produced & BE intersects CD at F To Prove: ΔABE ∼ ΔCFB. Proof: In parallelogram ABCD , opposite angles are equal, Hence, ∠A = ∠C Also, In parallelogram ABCD opposite sides are parallel, AD ∥ BC Now since AE is AD extended, AE ∥ BC and BE is the traversal ∴ ∠ AEB = ∠ CBF Now in Δ ABE & Δ CFB ∠A = ∠C ∠ AEB = ∠ CBF ∴ Δ ABE ∼ Δ CFB Hence proved

Next: Ex 6.3, 9 → 