# find out how many distinct three-digit numbers can be formed using all the digits of 3, 4, and 7?

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## Find out how many distinct three

Given, total different things=n the number of permutations of n things taken one at a time =.^(n)P(1)=hn, now if we taken two at a time (repetition is allowed), then first place can be filled by n ways and second place can again be filled in n ways. thereforeThe number of permutations of n things takenn two at a time =.^(n)P(1)xx.^(n)P(1)=nxxn=n^(2) Similarly, the number of permutations of n things taken three at a time=n^(3) The number of permutations of n things taken r at a time =n^(r). hence, the total number of permutations =n+n^(2)+n^(3)+ . . .+n^(r) =(n(n^(r)-1))/((n-1)) [sum of r terms of a GP]

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Find out how many distinct th...

Find out how many distinct three-digit numbers can be formed using all the digits of 1, 2, and 3.

Updated On: 27-06-2022

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Given, total different things=n

the number of permutations of n things taken one at a time

= . n P 1 =hn =.nP1=hn

, now if we taken two at a time (repetition is allowed), then first place can be filled by n ways and second place can again be filled in n ways.

∴ ∴

The number of permutations of n things takenn two at a time

= . n P 1 × . n P 1 =n×n= n 2 =.nP1×.nP1=n×n=n2

Similarly, the number of permutations of n things taken three at a time

= n 3 =n3

The number of permutations of n things taken r at a

time = n r =nr

. hence, the total number of permutations

=n+ n 2 + n 3 +...+ n r =n+n2+n3+...+nr = n( n r −1) (n−1) =n(nr-1)(n-1)

[sum of r terms of a GP]

Answer

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## How many three digit numbers can be formed by 3 and 7 only?

Answer (1 of 11): > How many 3-digit numbers can you make with just 3 and 7? First, I am going to show you how to figure it out the long way. We are going to list the permutations: 333 337 — changing last digit of 333 to 7 373 — changing the position of the 7 one to the left 733 — ditto 377...

How many three digit numbers can be formed by 3 and 7 only?

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Sort Gurusubrahmanyam K

MBBS from Government Villupuram Medical College,Villupuram (Expected 2024)Author has 54 answers and 78K answer views4y

There are 8 possibilities : 333,337,373,377,733,737, 773 and 777.

Or you can use permutations :___. There are 2 possibilities for all three boxes. Hence answer =2x2x2

CHEERS! Related questions

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How many 3-digit numbers can you make with just 3 and 7?

How many 3-digit numbers can you make with just 3 and 7?

First, I am going to show you how to figure it out the long way. We are going to list the permutations:

333

337 — changing last digit of 333 to 7

373 — changing the position of the 7 one to the left

733 — ditto

377 — changing the last 2 digits of 333 to 7s

737 — shifting the position of the 7s one to the right

773 — ditto

777 — changing all 3 digits of 333 to 7s

So, if either 7 or 3 must comprise all digits (but it doesn't have to contain both), then there are eight permutations. If it must contain at least one 3 and at least one 7, then there are

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Komal Saini

Financial Planner (2017–present)Author has 103 answers and 43.6K answer viewsUpdated 4y

Each digit can either be a 3 or a 7, hence two states, and since there are three columns we get two states to the third power or 2^3=8.

Marianne Bauer

Author has 274 answers and 109.4K answer views1y

Related

How many 3-digit numbers can you make with just 3 and 7?

You cannot create 3-digit numbers with only 2 digits unless you repeat digits.

2*2*2=8

Here are 8 three-digit numbers that can be formed with 3 and 7:

333 337 373 377 733 737 773 777

Related questions

How many three-digit numbers can be formed using the digits 5, 7, 8, and 2?

How many four-digit numbers have 3, 4, or both?

How many 3-digit numbers can be formed by 3, 4, and 5?

How many three-digit numbers use only the digits 0, 1, and 5?

How many 3-digit numbers can be formed without using 2, 3, 5, and 7?

Lance Berg

Author has 18.9K answers and 28.6M answer views4y

Generally, questions like this give several more details.

First, are repetitions allowed? If no repetitions are allowed, this is trivial; zero, you have only two digits and need to fill three numerals.

Second, are we talking whole numbers, or are decimal expansions acceptable?

Third are we talking positive numbers, or are negative numbers acceptable?

If we are talking positive integers only, with repetitions permitted, then there are two possible choices for each of three numerals, so 2*2*2=8 combinations.

If negative integers are allowed, then for each of the above combinations there is a matching

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Sam Ryan

Studied at Currently Attending College4y

333, 337, 373, 733 777, 773, 737, 377

8 three-digit numbers can be formed by 3 and 7 only.

Unless you are able to find more.

Edit: Thank you Terry Turner for pointing out my mistake!

Shivraj

Studied at Saraswati Vidya Mandir SchoolsUpdated 4y

Without wasting time let's start !!!

So three digit numbers from 3 & 7?

333,777 377,733 373,737 337,773

So final answer is 8 three digit numbers can be formed by Number 3 & 7.

Hope you like the answer.

Happy reading.

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James Buddenhagen

Lives in Xico,Veracruz.Mexico (2006–present)Author has 2.6K answers and 3M answer views4y

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How many 2 digit numbers can be formed by using numbers 5 and 4?

44, 45, 54, 55

That’s it, unless this is a trick question.

Dana F Anderson

Just interested in math is all. Kinda a hobby.Author has 9.5K answers and 5.4M answer views4y

Related

How many four-digit numbers are formed using the digits 7, 8, 3 and 5?

Since you didn’t state that digits cannot be repeated, the answer is 4^4 = 256 different numbers.

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## Using the digits 3,5 and 7 without any repitition, how many distinct numbers can be formed?

Using the digits 3,5 and 7 without any repitition, how many distinct numbers can be formed?

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Using the digits 3,5 and 7 without any repitition, how many distinct numbers can be formed?

Question

Using the digits 3, 5 and 7 (without any repitition), how many distinct numbers can be formed?

A 7 B 5 C 4 D 6 Open in App Solution

The correct option is **D** 6

Given digits are 3, 5 and 7.

Distinct numbers can be formed by shifting the digits as shown below.

Number formed Hundreds place Tens place Units place

753 7 5 3 735 7 3 5 573 5 7 3 537 5 3 7 375 3 7 5 357 3 5 7

So, a total of 6 distinct numbers can be formed using these digits.

Suggest Corrections 1

SIMILAR QUESTIONS

**Q.**Using the digits 3, 5, and 7 (without any repetition), how many distinct numbers can be formed?

**Q.**How many three-digit numbers can be formed using 1, 7, and 8, without repetition?

**Q.**How many three-digit numbers beginning with

7 and ending in 5

can be formed from the digits

1 , 2 , 3 , 4 , 5 and 7

without repetition of any digit?

**Q.**How many 2 digit numbers can be formed using the digits 0, 1, 2,3,4,5 without repetition?

**Q.**How many numbers can be formed between 40,000 and 60,000 using the digits 2, 3,4,5,6 without repetition?

View More

Guys, does anyone know the answer?