# find the area of quadrant whose circumference is 22cm

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## Find the area of a quadrant of a circle whose circumference is 22 cm

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## Find the area of a quadrant of a circle whose circumference is 22 cm

Easy Open in App Solution Verified by Toppr wehave C=22cm ⇒2πr=22cm ⇒2× 7 22 ×r=22 ∴r=3.5cm Now,

areaofquadrantofacircle=

4 πr 2 = 7 22 × 4 (3.5) 2 = 28 22×12.25 =9.625cm 2 .

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## Find the area of a quadrant of a circle whose circumference is 22 cm. We find the radius of the circle (r) from the circumference (c), C = 2πr, and area of the circle using A = πr^2.

Find the area of a quadrant of a circle whose circumference is 22 cm. We find the radius of the circle (r) from the circumference (c), C = 2πr, and area of the circle using A = πr^2.

## Find the area of a quadrant of a circle whose circumference is 22 cm

**Solution:**

Let the radius of the circle be 'r'

Thus, the circumference C = 2πr

Therefore, r = C/2π

A quadrant of a circle means one of the four equal parts.

Therefore, the area of a quadrant = 1/4 × Area of a circle = 1/4 × πr2

Circumference (C) = 22 cm

Therefore, radius (r) = C/2π

= 22/(2 × 22/7) = (22 × 7)/(2 × 22) = 7/2 cm

Therefore, the area of a quadrant = 1/4 × πr2

= 1/4 × 22/7 × 7/2 × 7/2

= 77/8 cm2

**☛ Check:**NCERT Solutions Class 10 Maths Chapter 12

**Video Solution:**

## Find the area of a quadrant of a circle whose circumference is 22 cm.

NCERT Solutions Class 10 Maths Chapter 12 Exercise 12.2 Question 2

**Summary:**

The area of a quadrant of a circle whose circumference is 22 cm is 77/8 cm2.

**☛ Related Questions:**

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## Ex 12.2, 2

Ex 12.2, 2 Find the area of a quadrant of a circle whose circumference is 22 cm. Area of quadrant = 1/4× area of circle = 1/4×("π"r2 ) Now, we need to find r. It is given that Circumference = 2πr 22 = 2πr 22/2 = πr 11 = πr 11/𝜋 = r

**Check sibling questions**

## Ex 12.2, 2 - Chapter 12 Class 10 Areas related to Circles (Term 1)

Last updated at March 16, 2023 by Teachoo

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### Transcript

Ex 12.2, 2 Find the area of a quadrant of a circle whose circumference is 22 cm. Area of quadrant = 1/4 area of circle = 1/4 (" "r2 ) Now, we need to find r. It is given that Circumference = 2 r 22 = 2 r 22/2 = r 11 = r 11/ = r r = 11/ r = 11/(22/7) r = 11 7/22 r = 7/2 cm Now, area of quadrant = 1/4 area of circle = 1/4(" "r2) = 1/4 22/7 (7/2)^2 = 1/4 22/7 (7 7)/(2 2) = 1/2 11/1 7/4 = 77/8 cm2

**Next**: Ex 12.2, 3 Important →

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### Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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