if you want to remove an article from website contact us from top.

# from the top of a 7m high building the angle of elevation

Category :

### Mohammed

Guys, does anyone know the answer?

get from the top of a 7m high building the angle of elevation from screen.

## From the top of a 7 m high building, the angle of elevation of the top of a cable tower is 60^o and the angle of depression of its foot is 45^o . The height of the tower in metre is

Click here👆to get an answer to your question ✍️ From the top of a 7 m high building, the angle of elevation of the top of a cable tower is 60^o and the angle of depression of its foot is 45^o . The height of the tower in metre is From the top of a 7m high building, the angle of elevation of the top of a cable tower is 60

Question o

and the angle of depression of its foot is 45

o

. The height of the tower in metre is

A7(

3 ​ −1)

B7

3 ​

C7+

3 ​

D7(

3 ​ +1) Medium Open in App

Updated on : 2022-09-05

Solution Verified by Toppr

Correct option is D) In ΔABE, tan60 o = AB h ​ h=AB 3 ​ ....(i) In ΔABC, tan45 o = AB 7 ​ AB=7   ...(ii)

By equation (i) and equation (ii)

h=7 3 ​

So, height of tower is =h+7=7(

3 ​ +1)

Solve any question of Some Applications of Trigonometry with:-

Patterns of problems

>

1124 58

स्रोत : www.toppr.com

## From the top of 7 m high building, the angle of elevation of the top of a cable tower is 60° and the angle of depression of its foot is 45°. Determine the height of the tower.

From the top of 7 m high building, the angle of elevation of the top of a cable tower is 60° and the angle of depression of its foot is 45°. Determine the height of the tower. Byju's Answer From the top ... Question From the top of 7 m

high building, the angle of elevation of the top of a cable tower is

60°

and the angle of depression of its foot is

45°

. Determine the height of the tower.

Open in App Solution

Solve for the height of the tower : Given, Height of building =7 m .

2. Angle of elevation of the top of a cable tower

=60° .

3. Angle of depression to the foot of a cable tower

=45° . From the figure, tan45°=ABBC ⇒ 1=ABBC ⇒AB=BC=7 m tan60°=EDAD ⇒ 3=ED7 [∵AD=BC] ⇒ ED=73 m Height of tower =ED+CD =73+7 ∵AB=CD ⇒ Height of tower =19.12 m

Hence, height of the tower is

19.12 m

.

Suggest Corrections 39 SIMILAR QUESTIONS

Q. From the top of a

7

m high building, the angle of elevation of the top of a cable tower is

60 ∘

and the angle of depression of its foot is

45 ∘

. Determine the height of the tower.

स्रोत : byjus.com

## Ex 9.1, 12

Ex 9.1 , 12 From the top of a 7 m high building, the angle of elevation of the top of a cable tower is 60° and the angle of depression of its foot is 45°. Determine the height of the tower. Let building be AB & tower be CE Given height of building = AB = 7m From the top of building, angle Check sibling questions

## Ex 9.1, 12 - Chapter 9 Class 10 Some Applications of Trigonometry (Term 2)

Last updated at March 16, 2023 by Teachoo     This video is only available for Teachoo black users

Subscribe Now

Get live Maths 1-on-1 Classs - Class 6 to 12

Book 30 minute class for ₹ 499 ₹ 299

### Transcript

Ex 9.1 , 12 From the top of a 7 m high building, the angle of elevation of the top of a cable tower is 60° and the angle of depression of its foot is 45°. Determine the height of the tower. Let building be AB & tower be CE Given height of building = AB = 7m From the top of building, angle of elevation of top of tower = 60°. Hence, ∠EAD = 60° Angle of depression of the foot of the tower = 45° Hence, ∠CAD = 45° We need to find height of tower i.e. CE Since AB & CD are parallel, CD = AB = 7 m Also, AD & BC are parallel So, AD = BC Since tower & building are vertical to ground ∠ ABC = 90° & ∠ EDA = 90° Now, AD & BC are parallel, taking AC as transversal ∠ ACB = ∠ DAC ∠ ACB = 45° In right angle triangle ABC, tan C = (𝑆𝑖𝑑𝑒 𝑜𝑝𝑝𝑜𝑠𝑖𝑡𝑒 𝑡𝑜 𝑎𝑛𝑔𝑙𝑒" " 𝐶)/(𝑆𝑖𝑑𝑒 𝑎𝑑𝑗𝑎𝑐𝑒𝑛𝑡 𝑡𝑜 𝑎𝑛𝑔𝑙𝑒" " 𝐶) tan 45° = 𝐴𝐵/𝐵𝐶 1 = 𝐴𝐵/𝐵𝐶 1 = (" " 7)/𝐵𝐶 BC = 7m Since BC = AD So, AD = 7m Now, In a right angle triangle ADE, tan A = (𝑆𝑖𝑑𝑒 𝑜𝑝𝑝𝑜𝑠𝑖𝑡𝑒 𝑡𝑜 𝑎𝑛𝑔𝑙𝑒" " 𝐴)/(𝑆𝑖𝑑𝑒 𝑎𝑑𝑗𝑎𝑐𝑒𝑛𝑡 𝑡𝑜 𝑎𝑛𝑔𝑙𝑒" " 𝐴) tan 60° = 𝐸𝐷/𝐴𝐷 √3 = 𝐸𝐷/𝐴𝐷 √3 = 𝐸𝐷/7 7√3 = ED ED = 7√3 Height of tower = ED + DC = 7√3 + 7 =7(√3 + 1)m

Next: Ex 9.1, 13 Important → 