# from the top of a 7m high building the angle of elevation

### Mohammed

Guys, does anyone know the answer?

get from the top of a 7m high building the angle of elevation from screen.

## From the top of a 7 m high building, the angle of elevation of the top of a cable tower is 60^o and the angle of depression of its foot is 45^o . The height of the tower in metre is

Click here👆to get an answer to your question ✍️ From the top of a 7 m high building, the angle of elevation of the top of a cable tower is 60^o and the angle of depression of its foot is 45^o . The height of the tower in metre is

From the top of a 7m high building, the angle of elevation of the top of a cable tower is 60Question o

and the angle of depression of its foot is 45

o

. The height of the tower in metre is

**A**7(

3 −1)

**B**7

3

**C**7+

3

**D**7(

3 +1) Medium Open in App

Updated on : 2022-09-05

Solution Verified by Toppr

Correct option is D)

In ΔABE, tan60 o = AB h h=AB 3 ....(i) In ΔABC, tan45 o = AB 7 AB=7 ...(ii)

By equation (i) and equation (ii)

h=7 3

So, height of tower is =h+7=7(

3 +1)

Solve any question of Some Applications of Trigonometry with:-

Patterns of problems

>

Was this answer helpful?

1124 58

## From the top of 7 m high building, the angle of elevation of the top of a cable tower is 60° and the angle of depression of its foot is 45°. Determine the height of the tower.

From the top of 7 m high building, the angle of elevation of the top of a cable tower is 60° and the angle of depression of its foot is 45°. Determine the height of the tower.

Byju's Answer From the top ... Question From the top of 7 m

high building, the angle of elevation of the top of a cable tower is

60°

and the angle of depression of its foot is

45°

. Determine the height of the tower.

Open in App Solution

**Solve for the height of the tower :**

Given, Height of building =7 m .

2. Angle of elevation of the top of a cable tower

=60° .

3. Angle of depression to the foot of a cable tower

=45° . From the figure, tan45°=ABBC ⇒ 1=ABBC ⇒AB=BC=7 m tan60°=EDAD ⇒ 3=ED7 [∵AD=BC] ⇒ ED=73 m Height of tower =ED+CD =73+7 ∵AB=CD ⇒ Height of tower =19.12 m

**Hence, height of the tower is**

19.12 m

**.**

Suggest Corrections 39

SIMILAR QUESTIONS

**Q.**From the top of a

7

m high building, the angle of elevation of the top of a cable tower is

60 ∘

and the angle of depression of its foot is

45 ∘

. Determine the height of the tower.

## Ex 9.1, 12

Ex 9.1 , 12 From the top of a 7 m high building, the angle of elevation of the top of a cable tower is 60° and the angle of depression of its foot is 45°. Determine the height of the tower. Let building be AB & tower be CE Given height of building = AB = 7m From the top of building, angle

**Check sibling questions**

## Ex 9.1, 12 - Chapter 9 Class 10 Some Applications of Trigonometry (Term 2)

Last updated at March 16, 2023 by Teachoo

Ad

This video is only available for Teachoo black users

Subscribe Now

Get live Maths 1-on-1 Classs - Class 6 to 12

Book 30 minute class for ₹ 499 ₹ 299

### Transcript

Ex 9.1 , 12 From the top of a 7 m high building, the angle of elevation of the top of a cable tower is 60° and the angle of depression of its foot is 45°. Determine the height of the tower. Let building be AB & tower be CE Given height of building = AB = 7m From the top of building, angle of elevation of top of tower = 60°. Hence, ∠EAD = 60° Angle of depression of the foot of the tower = 45° Hence, ∠CAD = 45° We need to find height of tower i.e. CE Since AB & CD are parallel, CD = AB = 7 m Also, AD & BC are parallel So, AD = BC Since tower & building are vertical to ground ∠ ABC = 90° & ∠ EDA = 90° Now, AD & BC are parallel, taking AC as transversal ∠ ACB = ∠ DAC ∠ ACB = 45° In right angle triangle ABC, tan C = (𝑆𝑖𝑑𝑒 𝑜𝑝𝑝𝑜𝑠𝑖𝑡𝑒 𝑡𝑜 𝑎𝑛𝑔𝑙𝑒" " 𝐶)/(𝑆𝑖𝑑𝑒 𝑎𝑑𝑗𝑎𝑐𝑒𝑛𝑡 𝑡𝑜 𝑎𝑛𝑔𝑙𝑒" " 𝐶) tan 45° = 𝐴𝐵/𝐵𝐶 1 = 𝐴𝐵/𝐵𝐶 1 = (" " 7)/𝐵𝐶 BC = 7m Since BC = AD So, AD = 7m Now, In a right angle triangle ADE, tan A = (𝑆𝑖𝑑𝑒 𝑜𝑝𝑝𝑜𝑠𝑖𝑡𝑒 𝑡𝑜 𝑎𝑛𝑔𝑙𝑒" " 𝐴)/(𝑆𝑖𝑑𝑒 𝑎𝑑𝑗𝑎𝑐𝑒𝑛𝑡 𝑡𝑜 𝑎𝑛𝑔𝑙𝑒" " 𝐴) tan 60° = 𝐸𝐷/𝐴𝐷 √3 = 𝐸𝐷/𝐴𝐷 √3 = 𝐸𝐷/7 7√3 = ED ED = 7√3 Height of tower = ED + DC = 7√3 + 7 =7(√3 + 1)m

**Next**: Ex 9.1, 13 Important →

Ask a doubt Facebook Whatsapp

Made by

### Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

Guys, does anyone know the answer?