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# how many numbers are there from 300 to 400 which are divisible by 2 but not divisible by 3?

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### Mohammed

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## What number between 300 and 400 is divisible by 3 not 2?

There are 17 numbers between 300 and 400 that are divisible by three but not divisible by two. They are: 303, 309, 315, 321, 327, 333, 339, 345, 351, 357, 363, 369, 375, 381, 387, 393 and 399. Subjects > Math > Other Math

## What number between 300 and 400 is divisible by 3 not 2?

Wiki User ∙ 8y ago Best Answer Copy

There are 17 numbers between 300 and 400 that are divisible by three but not divisible by two. They are: 303, 309, 315, 321, 327, 333, 339, 345, 351, 357, 363, 369, 375, 381, 387, 393 and 399.

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### How many numbers between 400 and 600 are divisible by nine?

There are 22 numbers between 400 and 600 that are divisible by nine.

### What is a number between 400-500 that is divisible by 3 and not 2?

To find out if a number is divisible by 3 add up all it's digest and check if the total is divisible by 3. to check if a number is divisible by 2 check if the last digit is divisible by 2. So one such number is 405.

400

### How many numbers between 400 and 800 are divisible by 13?

The first number is 403 and the last number in the series would be 793. There are 31 of them.

### Divisible by 3 between 400 and 500?

Related questions

### What is a prime number that is between 300-400 that is divisible by 3 but not 2?

A prime number is divisible only by 1 or itself.

### What number between 300 and 400 is divisible by 2 3 and 5?

330 is one such number.

Try 300

### What whole number is between 300 and 400?

It is: (300+400)/2 = 350

453

400

## Pariksha

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Single Correct

Find the number of numbers between 300 to 400 (both included), that are not divisible by 2, 3, 4, and 5.

Total numbers = 101

Step 1: Numbers not divisble by 2 = All even numbers = 51 numbers rejected.

Step 2: Remaining numbers = 50.

Divisible by 3 = first number 300, last number = 399. As even numbers have already been removed, hence count out only odd numbers between 300 and 400 divisible by 3.

Thus, first number = 303, last number = 399, difference = 6.

Hence, remove: 399−303 6 +1=17

∴ 50 - 17 = 33 numbers left.

Step 3: We needn't remove additional terms for divisibilty by 4 since this would elimnate only even numbers which have already been eliminated.

Step 4: Among 33 odd numbers, we now have to remove those numbers that are divisible by 5 and not divisible by 3.

Between 300 and 400, the first odd number divisible by 5 is 305 and the last is 395.

Thus, \dfrac {395 - 305}{10} + 1 = 10

However, some of these numbers have already been removed to get 33 numbers. We need to remove all numbers divisble by 3 from these 10 numbers. We can find out that 315 is the first number and the last number disible by 3 is 375 and the difference is 30.

Thus, \dfrac {375 - 305}{30} + 1 = 3

These 3 numbers were already removed when we removed numbers divisble by 3.

Hence, for numbers divisible by 5, we need to remove only those numbers that are odd, divisble by 5 but not divisble by 3 i.e. 10 - 3 = 7.

So the numbers left are: 33 - 7 = 26.

Hence, option 3 is the right answer.

स्रोत : www.pariksha.co

## Find the no. of numbers between 300 to 400, that are not divisible by 2,3 ,4 & 5?

Answer (1 of 7): 26 Method 1 Number of numbers which are less than 300 and not divisible by 2, 3, and 5 = 300(1 - 1/2)(1 - 1/3)(1 - 1/5) = 80 Number of numbers which are less than 390 and not divisible by 2, 3, and 5 = 390(1 - 1/2)(1 - 1/3)(1 - 1/5) = 104 So, there are 104 - 80 = 24 number... Find the no. of numbers between 300 to 400, that are not divisible by 2,3 ,4 & 5?

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Sort Ravi Handa

Founder of www.handakafunda.com, teach online courses on NumbersAuthor has 755 answers and 8.8M answer views7y

26 Method 1

Number of numbers which are less than 300 and not divisible by 2, 3, and 5

= 300(1 - 1/2)(1 - 1/3)(1 - 1/5) = 80

Number of numbers which are less than 390 and not divisible by 2, 3, and 5

= 390(1 - 1/2)(1 - 1/3)(1 - 1/5) = 104

So, there are 104 - 80 = 24 numbers between 300 and 390 which are not divisible by 2, 3, and 5

Now, between 390 and 400, there are only 2 more such numbers which are not divisible by 2, 3, and 5 = 391, 397

Total valid numbers = 24 + 2 = 26

Concept used:

To find out the number of numbers less than N, which are not divisible by a or b or c or d or e .... is

N(1 - Related questions

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Divya Sharma

Software Engineer at Dell EMC India (2018–present)Updated 5y

Use venn diagram ;)

n(2)+n(3)+n(5)-n(2 U 3)-n(3 U 5)-n(5 U 2) + n(2 U 3 U 5)=50+33+20–16–6–10+3=74 (this is no. That are divisible by 2 ,3,4 or 5) so out of 100, 26 (100–74) are not divisible by any.

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Rohit Chavan

Product Developer at BMC Software (2019–present)Author has 73 answers and 192.5K answer views4y

Thanks for the A2A.

There are already some wonderful answers but i would like to approach this question from the perspective of Permutations & combinations which will be helpful for solving many more related questions based on numbers.

Assuming that we require the numbers exclusive of the limits i.e 300 to 400 .

Consider the number as follows -(since we require numbers upto 400 , its 100’s place will always be 3)

3 _ _

Let us focus on the units place first,

It is easy to see that for a number not divisible by 2 & 5 its unit digit must not contain 0,2,4,5,6,8.

So , the possible numbers to fill the uni

Soumya Chakraborty

100 %ile and 100 %age in Quantitative Aptitude, Common Admission Test (CAT)Author has 87 answers and 442.9K answer views6y

-A2A-

First of all the constraint regarding 4 is redundant here. We are already looking for numbers which are not divisible by 2 and if a number is not divisible by 2, it can anyhow not be divisible by 4.

Rephrasing the question how many numbers between 300 and 400 are not divisible by 2, 3 and 5.

The easiest way to solve this question would be apply the concept of Euler’s number. Euler’s number of a number tells how many positive integers less than the number are also co prime to the number. In this case we are looking for numbers not divisible by 2, 3 or 5; so first let's multiply 2*3*5=30. Now

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Doug Bell

Software architect, Java Guru, lead developer of "Dungeon Master"Author has 448 answers and 563.1K answer views6y

First, any number divisible by 4 is divisible by 2, so we can ignore 4 leaving 2, 3 & 5.

1/2 of numbers are not divisible by 2; 2/3 are not divisible by 3 and 4/5 are not divisible by 5. That gives 1/2 * 2/3 * 4/5 = 8/30 = 4/15 of numbers that are not divisible by 2, 3 or 5.

The question states "between" 300 to 400 without clarifying whether that is inclusive or exclusive, but exclusive seems like the most natural interpretation. With a first value 301 and a final value 399, there are 399 - 301 + 1 = 99 values.

99 * 4/15 = 26 2/5

The least common multiple of 2, 3 & 5 is 30, so the distribution o

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Thiago Rippel

Studied Mechanical Engineering & Mathematics at Federal University of Rio De Janeiro (UFRJ)2y

This has been sufficiently done mathematically in the other answers, so I’ll just give a quick and dirty way of doing this, which is with some coding. :) Here’s the code I wrote in Python, which checks this in under a second:

number = 0

#Notice we don't need to check 4, because if a number is divisible by 4, it's

#also divisible by 2, and we're already checking the numbers which are NOT

#divisible by 2 in the first if.

for n in range(300,401):

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Mohammed 13 day ago

Guys, does anyone know the answer?