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# if 1.4 g of calcium oxide is formed by the complete decomposition of calcium carbonate, then the amount of calcium carbonate taken and the amount of carbon dioxide formed will be respectively

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## If 1.4 g calcium oxide is formed by the complete decomposition of calcium carbonate , then the amount of calcium carbonate taken and the amount of carbon dioxide formed will be respectively :

Click here👆to get an answer to your question ✍️ If 1.4 g calcium oxide is formed by the complete decomposition of calcium carbonate , then the amount of calcium carbonate taken and the amount of carbon dioxide formed will be respectively :

Question

A

B

C

D

## 5.0g and 1.1g

Medium Open in App Solution Verified by Toppr

Correct option is C)

Chemical reaction for decomposition of calcium carbonate is :

CaCO 3 ​ →CaO+CO 2 ​ Molar mass of CaCO 3 ​ =100g/mol

Molar mass of CaO=56g/mol

Molar mass of CO 2 ​ =44g/mol

According to law of conservation of mass:

Mass of CaCO 3 ​

= Mass of CaO + Mass of CO

2 ​

If we have one mole of calcium carbonate it will decompose to give one mole of calcium oxide and one mole of carbon dioxide.

56 g of CaO is obtained from decomposition of 100 g of CaCO

3 ​ .

So 1.4 g of CaO is obtained from decomposition of [(100×1.4)÷56=2.5g] of CaCO

3 ​ . Mass of CO 2 ​

= (2.5−1.4) g = 1.1 g

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## MCQ : If 1.4 g of calcium oxide is formed by the complete decomposition of calcium carbonate then the amount of calcium carbonate taken and the amount of carbon dioxide formed will be respectively

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If 1.4 g of calcium oxide is formed by the complete decomposition of calcium carbonate, then the amount of calcium carbonate taken and the amount of carbon dioxide formed will be respectively :

Back to Search CBSE Class 9 Science 9 Question (a) 2.2 g and 1.1 g (b) 1.1 g and 2.5 g (c) 2.5 g and 1.1 g (d) 5.0 g and 1.1 g Answer

(c) 2.5 gm and 1.1 gm

Explanation:

Molecular mass of CaCO3: 40 + 12 + (16 × 3) = 100g

Molecular mass of CaO: 40 + 16 = 56g

Molecular mass of CO2: 12 + (16 × 2) = 44g

Reaction for the decomposition of calcium carbonate:

CaCO3  →  CaO  +  CO2

100g           56g       44g

X              1.4 g        Y

56 g of CaO is obtained when 100g of CaCO3 is burnt.

Therefore, to get 1.4g of CaO, the amount of CaCO3 to be burnt will be

100 × 1.4 56 = 2.5 g 100×1.456=2.5g For CO2,

100g of CaCO3 yields 44g of CO2

Therefore, 2.5g of CaCO3 will yield;

44 × 2.5 100 = 1.1 g 44×2.5100=1.1g

Jan 12, 2022 | Views: 394 🚀

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## If 1.4 G of Calcium Oxide is Formed by the Complete Decomposition of Calcium Carbonate, Then the Amount of Calcium Carbonate Taken and the Amount of Carbon Dioxide Formed Will Be Respectively :

If 1.4 G of Calcium Oxide is Formed by the Complete Decomposition of Calcium Carbonate, Then the Amount of Calcium Carbonate Taken and the Amount of Carbon Dioxide Formed Will Be Respectively :

If 1.4 g of calcium oxide is formed by the complete decomposition of calcium carbonate, then the amount of calcium carbonate taken and the amount of carbon dioxide formed will be respectively :

### OPTIONS

2.2 g and 1.1 g 1.1 g and 2.5 g 2.5 g and 1.1 g 5.0 g and 1.1 g Advertisement Remove all ads

### SOLUTION

2.5 gm and 1.1 gm

Molecular mass of CaCO3: 40 + 12 + (16 × 3) = 100g

Molecular mass of CaO: 40 + 16 = 56g

Molecular mass of CO2: 12 + (16 × 2) = 44g

Reaction for the decomposition of calcium carbonate:

CaCo3 → CaO + CO2

100g      56g    44g

X          1.4g     Y

56 g of CaO is obtained when 100g of CaCO3 is burnt.

Therefore, to get 1.4g of CaO, the amount of CaCO3 to be burnt will be

100×1.456=2.5g For CO2,

100g of CaCO3 yields 44g of CO2

Therefore, 2.5g of CaCO3 will yield;

g 44×2.5100=1.1g

Concept: Difference Between Atoms and Molecules

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Chapter 3: Atoms and Molecules - Very Short Answers [Page 131]

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Lakhmir Singh Class 9 Chemistry - Science Part 2

Chapter 3 Atoms and Molecules

Very Short Answers | Q 65 | Page 131

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