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# if 1st january 2008 is tuesday, then what day of the week lies on 1st january, 2009?

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## January 1, 2008 is Tuesday. What day of the week lies on Jan 1, 2009?

Click here👆to get an answer to your question ✍️ January 1, 2008 is Tuesday. What day of the week lies on Jan 1, 2009?

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B

C

D

## Sunday

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Updated on : 2022-09-05

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Correct option is C)

The year 2008 is a leap year. So, it has 2 odd days.

1st day of the year 2008 is Tuesday (Given)

So, 1st day of the year 2009 is 2 days beyond Tuesday.

Hence, it will be Thursday.

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### Discussion :: Calendar - General Questions (Q.No.14)

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«« Calendar - General Questions

14.

January 1, 2008 is Tuesday. What day of the week lies on Jan 1, 2009?

[A]. Monday [B]. Wednesday [C]. Thursday [D]. Sunday Answer: Option C Explanation:

The year 2008 is a leap year. So, it has 2 odd days.

1st day of the year 2008 is Tuesday (Given)

So, 1st day of the year 2009 is 2 days beyond Tuesday.

Hence, it will be Thursday.

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Sorabh Khullar said: (Sep 21, 2011)

If 21/09/2011 is wednesday then what will be the day on 21/9/2015.

Give the proper solution to the question

Suresh Ageeru said: (Sep 24, 2011)

The year 2011 is not a leap year, so it has only 1 odd day.

So, 1 day beyond wednesday, answer is thursday.

Jiban Jyoti Parida said: (May 7, 2012)

The year 2011is not a leap year but the 2012 is a leap year.

So the odd day is 2.

And the day will be 2 day beyond Wednesday is Monday.

Rajan said: (Feb 4, 2014)

2009-2008 = 1. And 1 leap year. So,1+1 = 2.

Tuesday+2 = Thursday (correct).

Bilal said: (Jun 24, 2016)

That is completely incorrect. 2008 was a common year because it started on a Tuesday. That means January 1 2009 was a Wednesday.

Bilal Mallick said: (Jun 24, 2016)

All of you are incorrect. Look, the rule on the calendar is that when a year divisible by 4 starts on a Tuesday is NOT a leap year.

January 1, 2008, was a Tuesday, Tuesday + 1= Wednesday. January 1, 2009, was a Wednesday (absolutely correct).

Nana Yaw said: (Nov 1, 2016)

@Bilal you are wrong.

According to 2009 calender it's Thursday.

If 1st february, 2012 is wednesday, what was the day of the week on 1st february, 2011? Please explain the answer.

Sumit Thappa said: (Sep 10, 2019)

Simply,

Divide this year by 4 i.e. 2008/4. It is divisible so we got to know that it is a leap year and leap year has 2 odd days as 366/4=52 weeks and 2 days. So the day will be 2 days ahead. So Tuesday + 2 = Thursday.

Priyanka V said: (Oct 5, 2019)

I had a doubt. From 1st Jan 2008 to 31st December 2008 is 366 days. So checking divisibility by 7, we get 2 odd days. So we can say that the last 2 days of the year (i.e. 30th and 31st Dec 2008) will be Wednesday and Thursday.

So from the question, actually 1st-Jan-2009 should be the next day i.e. 'Friday' right?

Please correct me if I am wrong!

Matt said: (Jun 23, 2020)

@Priyanka

Don't add 1st Jan 2008 in your calculation. (2nd Jan 2008 to 1st Jan 2009) in total 366 days, hence 2 odd days.

Divya Agrawal said: (Aug 28, 2020)

Pema Yangdon said: (Oct 30, 2020)

Right @Divya Agrawal.

I also got Wednesday as answer.

Khader Hussain Sha said: (Dec 9, 2020)

@All.

The question in 1 Jan 2008, we know that 2008 is a leap year, assume that if 2008 was an non-leap year then it.

Will have 365 days, so when you divide 365/7 = 1 odd day all right, the day will we Wednesday but as it is a leap year it has 366 days now 366/7 = 2 odd days, now add to the date of 1 Jan 2008 = Tuesday + 2 Thursday.

If the question was like 1 Jan 2008 in Tuesday then what is 1 Jan 2007, the answer would be Monday, as 2007 is the simple year.

Shreya said: (Jan 6, 2022)

the answer should be friday according to me because 2008 odd days are 2 and 1 of 1st jan 2009 so it should be 2+1=3 tues +3 i.e friday

Dawa Gyaltshen said: (Jul 24, 2022)

09-last two digit of the given year.

09/4=2[quoteint]. 1-date given.

0-number of month (JFM=033, AMJ=614, JAS =625 and OND= 035).

6-no.of year (1600-1699=6, 1700-1799=4, 1800-1899=2,1900-1999=0, and 2000-2099=6).

Sum of all=18.

Sum/7= 4(remainder).

4 = Thursday (0=Sunday......,.6 = saturday).

D R Mishra said: (Nov 20, 2022)

Yes, Thursday is the right Answer.

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## January 1, 2008 is Tuesday. What day of the week lies on Jan 1, 2009?

Answer (1 of 5): The first day and the last day of a general year is always same. But the last day of a leap year is always one day more. Example: 2019 is a general year. The first day of 2019 is Tuesday and the last day as well. 2020 is a leap year. If the first day of 2020 is Wednesday then ...

January 1, 2008 is Tuesday. What day of the week lies on Jan 1, 2009?

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Sort Vikrant Singh

B.Tech (CS) from Dr. A.P.J. Abdul Kalam Technical University (Graduated 2016)3y

The first day and the last day of a general year is always same. But the last day of a leap year is always one day more.

Example: 2019 is a general year.

The first day of 2019 is Tuesday and the last day as well.

2020 is a leap year. If the first day of 2020 is Wednesday then the last day will be Thursday.

Since, 2008 is a leap year. (You can check by dividing the last two digits by 4), and the first day is Tuesday , the last day 31st December 2008 will be one more i.e Wednesday.

So, on 1st January 2009 it will be Thursday.

No formula. Only concept and common sense.

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Since days of a week is a periodic event with a period of 7 days .It means that the same day of the week will come if you add 7 days to the same day.

Let's understand with an example.

As from above calender , Sunday is repeating at the date after adding 7 days to the previous date.

Total days between 1 January 2008 to 1 January 2009=Jan+Feb+Mar+……+Dec.+1

=30+29+31+30+31+30+31+31+30+31+30+31+1

=366 days

Therefore, 366/7 days =( 7*52 + 2 ) days .

After division the remainder tells that the next Tuesday will come at 2 days before 1 January of 2009 i.e 30 December 2008 will be Tuesday. Then 1 January 200

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2008 is a leap year, so no. of days between these two dates is 366, 52 weeks & 2 days, so Jan 1, 2009 is a Thursday

Anjisha Mohan

M.sc mathematics from University of Delhi (Graduated 2019)3y

2008 is a leap year ..so 366 days

1 week has 7 days ..so dividing 366 by 7

366/7 = 52 weeks +2 days

So jan1,2009 is Tuesday +2 days so THURSDAY.

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Gap between these two days = 367 (2008 being leap year)

On dividing 367 by 7, we get 52 with 3 as remainder.

Hence there are 52 complete weeks and 3 supplementary days.

1st supplementary day will be Tuesday (January 1 was Tuesday).

Hence 3rd supplementary or January 1, 2009 was Thursday.

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1st January 2008 was actually a Tuesday. 24 May 2008 was a Saturday, but if 1st January was a Sunday, it would have been a Thursday.

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If 4th january 2008 falls on friday, which day of the week is 4th january 2009?

For every gain of year, the date also gains a day. Suppose 4th feb, 2009 is saturday then 4th feb 2010 will be sunday. Just add a day.

Now the reverse of the above also holds true . That is, for every loss of year a day is lost. Suppose 4th February 2010 was a sunday then 4th February 2009 will be a saturday.

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