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If the momentum of an electron is changed by P, then the de Broglie wavelength associated with it changes by 0.5 % . The initial momentum of electron will be:

If the momentum of an electron is changed by P, then the de Broglie wavelength associated with it changes by 0.5 % . The initial momentum of electron will be:

Byju's Answer Standard XII Physics Line Spectra If the moment... Question

If the momentum of an electron is changed by P, then the de-Broglie wavelength associated with it changes by 0.5%. The initial momentum of electron will be:

A 200P B 400P C P 200 D 100P Open in App Solution

The correct option is B

200P λ = h p

[de -Brogli wavelength]

P = h λ Δ P P = − Δ λ λ P P i n i t i a l = 0.5 100 P i n i t i a l = 200 P Suggest Corrections 23

SIMILAR QUESTIONS

Q. If the momentum of an electron is changed by

p m

, then the de Broglie wavelength associated with it increased by

0.5 %

. The initial momentum of electron will be

Q.

If the momentum of an electron is increased by

Δ p

, then the de-Broglie wavelength associated with it changes by 0.50%. The initial momentum of the electron will be

Q. Find the initial momentum of electron if the momentum of electron is changed by

P m

and the de Broglie wavelegth associated with it changes by

0.50 %.

Q. The de-Broglie wavelength associated with a proton changes by 0.25% if its momentum is changed by

P o

. The initial momentum of proton is

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Standard XII Physics

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If the momentum of an electron is changed by P, then the de

Click here👆to get an answer to your question ✍️ If the momentum of an electron is changed by P, then the de - Broglie wavelength associated with it changes by 0.5

Question

If the momentum of an electron is changed by P, then the de-Broglie wavelength associated with it changes by 0.5%. The initial momentum of an electron will be:

A

400P

B

200 P ​

C

100P

D

200P

Medium Open in App

Updated on : 2022-09-05

Solution Verified by Toppr

Correct option is D)

According to de-Broglie relation:

λ= p h ​

Let, initial momentum =p

1 ​

and associated wavelength is λ

1 ​

and with a decrease in wavelength, momentum will increase.

Thus, Δp=−P and for Δλ=

100 0.5 ​ ×λ 1 ​

Differentiating the de-Broglie relation we get:

λ 1 ​ Δλ ​ =− p 1 ​ Δp ​ and λ 1 ​ 0.005×λ 1 ​ ​ = p 1 ​ P ​ = 100 0.5 ​ p 1 ​ =200P

Option D is correct.

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स्रोत : www.toppr.com

If the momentum of an electron is changed by p, then the de

WE know that lambda=h/P :. Dlambda=-h/(P^(2))dP, (dlambda)/lambda=(-h/(P^(2))dP)/(h//P)=-(dP)/P=(dP)/P (in magnitude) Given (dlambda)/lambda=0.5/100 , dP=P. Let the initial momentum be P(0). Then P/(P(0))=(dlambda)/lambda=0.5/100 or P(0)=100/0.5P=200P

If the momentum of an electron is changed by

p

, then the de - Broglie wavelength associated with it changes by

0.5 %

. The initial momentum of electron will be

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PRADEEP-DUAL NATURE OF RADIATION AND MATTER-EXERCISE

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Updated On: 27-06-2022

Text Solution A 200 P B 400 P C P 200 D 100 P Answer

The correct Answer is a

Solution WE know that λ = h P ∴ D λ = − h P 2 d P , d λ λ = − h P 2 d P h / P = − d P P = d P P

(in magnitude) Given

d λ λ = 0.5 100 , d P = P .

Let the initial momentum be

P 0 . Then P P 0 = d λ λ = 0.5 100 or P 0 = 100 0.5 P = 200 P Answer

Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

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किसी इलेक्ट्रॉन के संवेग को

β

से परिवर्तित करने पर उससे संबद्ध दे ब्रॉग्ली तरंगदैर्ग्य

0 ⋅ 5 %

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Δ p

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645750863 Text Solution

किसी इलेक्ट्रॉन के संवेग को p से परिवर्तन करने पर उससे संबद्ध दे-ब्रोग्ली तरंगदैर्ध्य 0.5% परिवर्तित हो जाती है। तो, इलेक्ट्रॉन का प्रारम्भिक संवेग होगा।

645777390 06:39

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