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# imagine you are at the bottom of a six-meter wall. each hour you climb 3 meters but slide down 2 meters. how long until you reach the top?

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### Mohammed

Guys, does anyone know the answer?

get imagine you are at the bottom of a six-meter wall. each hour you climb 3 meters but slide down 2 meters. how long until you reach the top? from screen.

## Puzzle

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## Puzzle | Snail and Wall

Difficulty Level : Medium

Last Updated : 28 Feb, 2020

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Puzzle: A snail wishes to reach a water shore. To do this it must cross a wall which is 30 feet high. It has a time limit of 30 hours to reach atop the wall. The time starts as soon as it starts climbing the wall. However, he faces a problem while climbing. Every hour it climbs the wall 3 feet up, it slides down 2 feet. This occurs every hour. So how many hours will it take for the snail to reach atop the wall?

Solution: Let’s think this thoroughly.

Every hour the snail climbs up 3 feet, it slides down 2 feet. So, the actual height it is climbing in 1 hour is 1 foot.

Similarly, in 25 hours, the snail would have climbed 25 feet, in 26 hours it would have climbed 26 feet and in 27 hours it would have climbed 27 feet, but things change after 27 feet.

As we know, the snail covers 3 feet up in 1 hour. So, in the 28th hour, the snail would have climbed 30 feet up the wall and would have reached atop the wall. Therefore the answer to this riddle is 28 hours.

स्रोत : www.geeksforgeeks.org

## Imagine you are standing at the bottom of a 30

Posted by

u/Apprehensive_Lab3310

1 year ago

## Imagine you are standing at the bottom of a 30-foot wall. You start climbing, and each hour you climb three feet but slide down two feet. Assuming you keep this pattern of climbing, how long will it take you to climb to the top of the wall?

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level 1 burpchelischili · 1 yr. ago 28 hours 3 level 1 Elvesaretall · 1 yr. ago

28. Assuming you climb 3 ft then drop 2. You get to 27ft in 27 hours then climb 3 feet to get to 30.

7 level 2 evanhinton · 1 yr. ago

3

level 2

Apprehensive_Lab3310

OP · 1 yr. ago

1

level 1

SoundbudsSlimCognito

· 1 yr. ago

Oh no the math homework has arrived.

4 level 2

Apprehensive_Lab3310

OP · 1 yr. ago lol 1 level 1 Eye_Doc_Photog · 1 yr. ago

2 level 2

Apprehensive_Lab3310

OP · 1 yr. ago daddy please :) 1 level 1 [deleted] · 1 yr. ago 30 hours.

each hour you’re climbing a foot.

not really extreme math

2 level 2 ScurvyDunk · 1 yr. ago

Possibly 29 hours since before the 30th hour you would be climbing the 3 ft achieving the height before the hour is up and before sliding down the 2 ft. But most likely 30 hours as your reasoning makes more sense

2 level 1 Baam294 · 1 yr. ago 30? 1 level 1 Ginger_Whore · 1 yr. ago

So you’re progressing at a net positive rate of 1ft/hr. 30ft @ 1ft/hr = 30 hours. I could be wrong though, I’m not a mathematician lol!!

1 level 1

SantiagoandtheMarlin

· 1 yr. ago

I didn't come to Reddit to do algebra.

1 level 2

Apprehensive_Lab3310

OP · 1 yr. ago

only if you could understand it wasn't algebra but commonsense, and we both lack it :)

1 level 1 ShackintheWood · 1 yr. ago Almost 28 hours. 1 level 1 cnc3 · 1 yr. ago

Those answering 28 are not taking their height into the equation. If you are 6 feet tall, then the height to be climbed is only 24 feet. /s

1 level 1 Werd616 · 1 yr. ago

This doesn't take into account how high I'd jump to grab the highest area of the wall to start climbing.

1 level 1 328944 · 1 yr. ago

Why the hell am I slipping 2 feet every hour?

The correct answer is get new climbing gear.

1 level 1

· 1 yr. ago 27ish

You spend 27 going up, then part of the other hour climbing up 3ft

1

स्रोत : www.reddit.com

## A snail climbs a well 3 feet during the day, and during night, it slips 2 feet. If the well is 30 feet deep, how long will it take for the snail to climb?

Answer (1 of 41): A snail climbs a well 3 feet during the day, and during night, it slips 2 feet. If the well is 30 feet deep, how long will it take for the snail to climb? Answer: This snail will advance 1 foot per day. At the start of the 27 day, this snail will be 26 feet up from a 30 foot ...

A snail climbs a well 3 feet during the day, and during night, it slips 2 feet. If the well is 30 feet deep, how long will it take for the snail to climb?

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Sort Thilagavathi A

Lives in Tirupur, Tamil Nadu, India3y

As the snail climbs 3 feet and slips 2 feet its progress in one day is 1 feet.

So in 27 days it can climb 27 feet.

And on 28th day if it climbs 3 feet it will be out of well and it cannot slip down.

So the answer is 28 days.

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Manas Dhruve

Former Software Engineer at Cybage Software (2018–2020)Author has 387 answers and 1.2M answer views3y

Related

A snail is at the bottom of a 30-foot well. Each day he climbs up three feet, but at night he slips back two feet. How many days will it take him to climb out of the well?

Let us solve it logically starting with the first step..

Day 1: Snail climbs THREE feet = +3 and Snail slips back TWO feet at night = +3 -2 = +1 (Considering 24 hours a day obviously)..

Day 2: Same story = +1 (of Day 1) +3 -2 = +2

Day 3: Same story = +2 (of Day 2) +1 = +3

. . .

Day 27: Same story = +26 (of Day 26) + 1 = +27

Day 28: Dramatic End = +27 (0f Day 27) +3 = +30..Now, Snail is out of the well by Sunrise itself (before night)..

So, the ANSWER = 28 DAYS..

Hope it helps :)

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Priyanshu Pyakurel 2y

I wont go in to the specific solution of this problem only but also generalize it rather!

When we solve these questions we should consider maximum height travelled in a day,which might look a bit confusing but it's actually a simple formula from sequence and series.

Tn=a+(n-1)d { let this be equation-1}

here in this case a=max height in first day i.e 3 feet ,Tn=30 and

d=(climbed height-slipped distance) i.e d=(3-2) or, d=1

So now we need to solve for n, i.e no of days to climb it

Solving equation 1, n=(Tn-a)/d + 1 n=30–3/1 + 1 n=27+1 n=28

Therefore it will take 28 days

Ryan Power

Former Sales Assistant at Vue Cinema (2017–2020)2y

Related

A snail is at the bottom of a 30-foot well. Each day he climbs up three feet, but at night he slips back two feet. How many days will it take him to climb out of the well?

28 days, because the snail will end up getting 1 foot higher each day. It will come to a point where he is 27 feet high on the 27th day and then on the 28th day he will climb 3 feet out of the well. So according to my brain 😂 I I think the answer is 28 days.

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Shrey Sharma

Btech in Mechanical Engineering & Laws in India, Govind Ballabh Pant Engineering College, Delhi (Graduated 2012)3y

Related

A snail is at the bottom of a 30-foot well. Each day he climbs up three feet, but at night he slips back two feet. How many days will it take him to climb out of the well?

AT the finish of a day he atlast climbs one feet only..(3 feet climbs a day - 2 feet slipped by night = 1 feet climb a day)

till 25 days he climbs 25 feet ..

On 26th morning he climbs 25 + 3 = 28 feet

At night he slipped by 2 feet so it gets 26 feet at the end of 26th day

On 27th day he climbs 3 feet so it gets 26 + 3 - 29 th feet

at the end of day in night he slipped by 2 so it gets 29 - 2 = 27 feet

On 28 th day he climbs 3 more feet that is 27 + 3 =30 feet complete on 28 th day

स्रोत : www.quora.com

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Mohammed 14 day ago

Guys, does anyone know the answer?