if you want to remove an article from website contact us from top.

    in a flight of 2800km, an aircraft was slowed down due to bad weather. its average speed is reduced by 100km/hr and time increased by 30 minutes. find the original duration of the flight.

    Mohammed

    Guys, does anyone know the answer?

    get in a flight of 2800km, an aircraft was slowed down due to bad weather. its average speed is reduced by 100km/hr and time increased by 30 minutes. find the original duration of the flight. from screen.

    In a flight of 2800 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 100 km/hour and time increased by 30 minutes. Find the original duration of flight.

    Click here👆to get an answer to your question ✍️ In a flight of 2800 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 100 km/hour and time increased by 30 minutes. Find the original duration of flight.

    Question

    In a flight of 2800 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 100 km/hour and time increased by 30 minutes. Find the original duration of flight. 

    A3

    2 1 ​ hours

    B5

    2 1 ​ hours

    C4

    2 1 ​ hours

    D2

    2 1 ​ hours Medium Open in App

    Updated on : 2022-09-05

    Solution Verified by Toppr

    Correct option is A)

    Let the original speed =x km/hr

    ∴ Normal time of flight =

    x 2800 ​

    hours ,New speed =(x−100)km/hr

    ∴ Time of flight, when speed is reduced =

    x−100 2800 ​ hours

    According to the given condition,

    (x−100) 2800 ​ − x 2800 ​ = 60 30 ​ 2 1 ​ = x(x−100) 2800x−2800(x−100) ​ ⇒x 2 −100x−560000=0 ⇒x 2 −800x+700x−560000=0

    ⇒x(x−800)+700(x−800)=0

    ⇒(x−800)(x+700)=0 ⇒x−800=0 x+700=0 ⇒x=800,−700

    Neglecting the -ve value.

    Original speed of the are craft = 800 km/hr

    Original duration of flight =

    800 2800 ​ =3 2 1 ​ hours

    Solve any question of Quadratic Equations with:-

    Patterns of problems

    >

    Was this answer helpful?

    241 11

    स्रोत : www.toppr.com

    In a flight of 2800 km, an aircraft was slowed down due today weather. It's average speed for the trip was reduced by 100 km / hour and the time increased by 30 minutes. Find the original duration of flight.

    In a flight of 2800 km, an aircraft was slowed down due today weather. It's average speed for the trip was reduced by 100 km / hour and the time increased by 30 minutes. Find the original duration of flight.

    Byju's Answer Standard VIII Mathematics

    Relation for Inverse Proportion

    In a flight o... Question In a flight of 2800 k m ,

    an aircraft was slowed down due to today's weather. It's average speed for the trip was reduced by

    100 k m /

    hour and the time increased by

    30

    minutes. Find the original duration of the flight.

    Open in App Solution

    Let the speed of aircraft be

    x k m / h Distance travelled = 2800 k m Time taken = Distance Speed = 2800 x hours

    Given that when the speed is reduced by

    100 k m / h , New speed = ( x – 100 ) k m / h

    , time is increased by

    30 minutes That is, 30 minutes = 30 60 hour = 1 2 hour

    Time taken after the speed was reduced

    = [ 2800 ( x – 100 ) ] hour ∴ [ 2800 x – 100 ] = 2800 x + 1 2 ⇒ [ 2800 x – 100 ] − 2800 x = 1 2 ⇒ 2800 [ x − ( x − 100 ) x ( x − 100 ) ] = 1 2 ⇒ x 2 − 100 x − 560000 = 0 ⇒ x 2 − 800 x + 700 x − 560000 = 0 ⇒ x ( x − 800 ) + 700 ( x − 800 ) = 0 ⇒ ( x + 700 ) ( x − 800 ) = 0 ⇒ x = − 700 or, 800

    Since speed cannot be negative,

    x = 800.

    Thus original duration of the flight

    = 2800 800 = 7 2 hours = 3 hours 30 minutes Suggest Corrections 24

    SIMILAR QUESTIONS

    Q. In a flight of 2800 km, an aircraft was slowed down due to bad weather. Its average speed is reduced by 100 km/h and time increased by 30 minutes. Find the original duration of the flight.Q. In a flight of

    6000 k m

    an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by

    400 k m / h o u r

    and time increased by

    30

    minutes. Find the original duration of flight.

    Q.

    In a flight of 2800km an aircraft was slowed down due to bar weather. If average speed is reduced by 100km/hr and time increase by 30min find the original duration of the flight.

    Q. In a flight of

    600 k m

    , an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by

    200

    km/hr and the time of flight increased by

    30

    minutes. The duration of the flight is:

    Q. In a fight of

    600 k m

    , an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by

    200

    km/hr and the time of flight increased by

    30

    minutes. Find the duration of flight.

    RELATED VIDEOS

    Introduction to Inverse Proportions

    MATHEMATICS Watch in App EXPLORE MORE

    Relation for Inverse Proportion

    Standard VIII Mathematics

    स्रोत : byjus.com

    In a flight of 2800 km, an aircraft was slowed down due to bad weather. Its average speed is reduced by 100 km/h and time increased by 30 minutes. Find the original duration of the flight.

    In a flight of 2800 km, an aircraft was slowed down due to bad weather. Its average speed is reduced by 100 km/h and time increased by 30 minutes. Find the original duration of the flight.

    Advertisement Remove all ads

    In a flight of 2800 km, an aircraft was slowed down due to bad weather. Its average speed is reduced by 100 km/h and time increased by 30 minutes. Find the original duration of the flight.

    Advertisement Remove all ads

    SOLUTION

    Let the original speed of the plane be x km/hr.

    If the speed of the plane is reduced by 100 km/hr, then

    Reduced speed of the plane = (x − 100) km/hr

    Time taken by the plane to reach its destination at original speed,

    t1=2800xhr

    Time taken by the plane to reach its destination at reduced speed,

    t1=2800x-100hr Given,

    Time taken by the plane to reach its destination at reduced speed − Time taken by the

    plane to reach its destination at original speed = 30 minutes

    t2-t1=12hr ⇒2800x-100-2800x=12

    ⇒2800x-2800(x-100)x(x-100)=12

    ⇒2800×x100×2=x2-100x

    ⇒x2-100x-560000=0

    ⇒x2-800x+700x-560000=0

    ⇒x(x-800)+700(x-800)=0

    ⇒(x-800)(x+700)=0 ⇒x-800=0 Or x+700=0 ⇒x=800 or x=-700 ∴x=800 ∴

    [Speed cannot be negative]

    Original speed of flight = 800 km/hr

    ∴ Original duration of flight,

    t1=2800800=72=312Hrs

    Thus, the original duration of the flight is 3 hours 30 minutes.

    Concept: Situational Problems Based on Quadratic Equations Related to Day to Day Activities to Be Incorporated

    Is there an error in this question or solution?

    2011-2012 (March) All India Set 1

    Q 29.2 Q 29.1 Q 30

    APPEARS IN

    2011-2012 (March) All India Set 1 (with solutions)

    VIDEO TUTORIALS

    Q 29.2 | 4 marks VIEW ALL [1] view

    Video Tutorials For All Subjects

    Situational Problems Based on Quadratic Equations Related to Day to Day Activities to Be Incorporated

    video tutorial 00:16:14

    स्रोत : www.shaalaa.com

    Do you want to see answer or more ?
    Mohammed 7 day ago
    4

    Guys, does anyone know the answer?

    Click For Answer