# in an equilateral triangle abc ad , is drawn perpendicular to bc meeting bc in d. the term ad2 is equal to

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## In an equilateral triangle ABC, AD is drawn perpendicular to BC, meeting BC in D. Prove that AD^2 = 3BD^2.

In an equilateral triangle ABC, AD is drawn perpendicular to BC, meeting BC in D. Prove that AD2 = 3BD2.

## In an equilateral ^le ABC, AD is drawn ^r to BC meeting BC in D, prove that AD^2 = 3BD^2.

Click here👆to get an answer to your question ✍️ In an equilateral ^le ABC, AD is drawn ^r to BC meeting BC in D, prove that AD^2 = 3BD^2.

## In an equilateral triangle ABC, AD is drawn perpendicular to BC meeting BC in A Prove that AD^(2) = x BD^(2) Find x.

In an equilateral triangle ABC, AD is drawn perpendicular to BC meeting BC in A Prove that AD^(2) = x BD^(2) Find
x.

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Guys, does anyone know the answer?