# in finding the hcf of two numbers by division method, four successive quotients are 4, 3, 6 and 5 respectively. and final divisor is 12. what are the two numbers?

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Guys, does anyone know the answer?

get in finding the hcf of two numbers by division method, four successive quotients are 4, 3, 6 and 5 respectively. and final divisor is 12. what are the two numbers? from screen.

## In finding the HCF of two numbers by division method four successive quotient are 4,3,6 and 5 respectively. and final divisor is 12. What are two numbers?

In finding the HCF of two numbers by division method four successive quotient are 4,3,6 and 5 respectively. and final divisor is 12. What are two numbers?

## [Solved] In finding the HCF of two numbers by division method, the qu

Detailed Solution: AS we know, Dividend = Divisor × quotient + remainder Last divisor = 105 and quotient = 2 Dividend (c) = 105 × 2 = 210 Now

## The H.C.F. of two numbers, obtained in three steps of division is 7 and the first 3 quotients are 2, 4 and 6 respectively. Find the numbers.

Click here👆to get an answer to your question ✍️ The H.C.F. of two numbers, obtained in three steps of division is 7 and the first 3 quotients are 2, 4 and 6 respectively. Find the numbers.

Guys, does anyone know the answer?