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    in the figure, a man of true mass m is standing on a weighing machine placed in a cabin. the cabin is joined by a string with a body of mass m. assuming no friction, and negligible mass of cabin and weighing machine,

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    get in the figure, a man of true mass m is standing on a weighing machine placed in a cabin. the cabin is joined by a string with a body of mass m. assuming no friction, and negligible mass of cabin and weighing machine, from screen.

    In the figure, a man of true mass m is standing on a weighing m

    Solution for the question - in the figure, a man of true mass m is standing on a weighing machineplaced in a cabin. the cabin is joined by a string with a body

    Physics- GENERAL Easy Question

    In the figure, a man of true mass M is standing on a weighing machine placed in a cabin. The cabin is joined by a string with a body of mass m. Assuming no friction, and negligible mass of cabin and weighing machine, the measured mass of man is (normal force between the man and the machine is proportional to the mass)

    measured mass of man is

    acceleration of man is

    acceleration of man is

    measured mass of man is M.

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    In the figure, a man of true mass M is standing on a weighing machine placed in a cabin. The cabin is joined by a string with a body of mass m. Assuming no friction, and negligible mass of cabin and weighing machine, the measured mass of man is:

    Click here👆to get an answer to your question ✍️ In the figure, a man of true mass M is standing on a weighing machine placed in a cabin. The cabin is joined by a string with a body of mass m. Assuming no friction, and negligible mass of cabin and weighing machine, the measured mass of man is:

    Question

    In the figure, a man of true mass M is standing on a weighing machine placed in a cabin. The cabin is joined by a string with a body of mass m. Assuming no friction, and negligible mass of cabin and weighing machine, the measured mass of man is:

    A

    M+m Mm ​

    B

    M−m Mm ​

    C

    M

    D

    depends on g

    Medium Open in App

    Updated on : 2022-09-05

    Solution Verified by Toppr

    Correct option is A)

    weight measure by weighting machine =M(g−a)

    from F.B.D of lift T=m(g−a).....(1) from F.B.D of pully T=ma......(2) ma=m(g−a) mg=ma+ma mg=a(m+m) a= m+m M ​ g weight=m(g−a) =m(g− m+m mg ​ ) = m+m m(m+m−m)g ​ w= m+m mmg ​ mass= m+m mm ​ ​

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    In fig., a man true mass M is standing on a weighing machine placed in a cabin. The cabin is joined by a string a body of mass m. Assuming no friction, and negligible mass of cabin and weighing machine, the measured mass of man is (normal force between the man and the machine is proportional to the mass)

    Mg-T=Ma ..(i) T=ma ..(ii) Solving Eqs. (i) and (ii) , a=(Mg)/(M+m) FBD of man, Mg-N = Ma implies N=(Mmg)/((M+m)).

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    In fig., a man true mass M is ...

    In fig., a man true mass M is standing on a weighing machine placed in a cabin. The cabin is joined by a string a body of mass m. Assuming no friction, and negligible mass of cabin and weighing machine, the measured mass of man is (normal force between the man and the machine is proportional to the mass)

    Updated On: 27-06-2022

    00 : 30

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    Text Solution Open Answer in App A

    The measured mass of man is

    Mm (M+m) Mm(M+m) B

    The acceleration of man is

    mg (M+m) mg(M+m) . C

    The acceleration of man is

    Mg (M+m) Mg(M+m) . D

    The measured mass of man is

    M M Answer

    The correct Answer is A::C

    Solution Mg−T=Ma Mg-T=Ma ..(i) T=ma T=ma ..(ii)

    Solving Eqs. (i) and (ii) ,

    a= Mg M+m a=MgM+m FBD of man, Mg−N=Ma⇒N= Mmg (M+m) Mg-N=Ma⇒N=Mmg(M+m) .

    Answer

    Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

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    is standing on a weighing machine kept in a box of mass

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    30kg 30kg

    .

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