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# in the figure given below a bullet of mass m moving with speed u

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## A ball is thrown vertically upwards with speed u , if it experiences a constant air resistance force of magnitude f , then the speed with which ball strikes the ground, (weight of ball is w ) is

Click here👆to get an answer to your question ✍️ 4. A bullet of mass m, moving with a speed of u penetrates a block of wood of thickness x and emerges with a speed v. The force of resistance offered by the wood is given by (a) † (- 12) (b) * (u? - v?) (c) (12-u?) ott\" (12 –u?) Question ## 4. A bullet of mass m, moving with a speed of u penetrates a block of wood of thickness x and emerges with a speed v. The force of resistance offered by the wood is given by (a) † (- 12) (b) * (u? - v?) (c) (12-u?) ott" (12 –u?)

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Updated on : 2022-09-05

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## A uniform thin rod of mass M and length L is hinged by a frictionless pivot at its end O, as shown in the diagram. A bullet of mass m moving horizontally with a velocity v, strikes the free end of the rod and gets embedded in it. The angular velocity of the system about O, just after the collision is,

A uniform thin rod of mass M and length L is hinged by a frictionless pivot at its end O, as shown in the diagram. A bullet of mass m moving horizontally with a velocity v, strikes the free end of the rod and gets embedded in it. The angular velocity of the system about O, just after the collision is, Byju's Answer Standard XII Physics Friction A uniform thi... Question

A uniform thin rod of mass

M and length L

is hinged by a frictionless pivot at its end

O

, as shown in the diagram. A bullet of mass

m

moving horizontally with a velocity

v

, strikes the free end of the rod and gets embedded in it. The angular velocity of the system about

O

, just after the collision is, A m v L ( M + m ) B 2 m v L ( M + 2 m ) C 3 m v L ( M + 3 m ) D m v L M Open in App Solution

The correct option is C

3 m v L ( M + 3 m ) Let ω

be the angular velocity acquired by the system (rod + bullet) immediately after the collision.

Since no external torque acts, the angular momentum of the system is conserved, thus

m v L = I ω − ( 1 ) Where I

is the moment of inertia of the system about an axis passing throug

O

and perpendicular to the rod.

∴ I = M O I of rod about O + M O I

of bullet stuck at its lower end about

O = 1 3 M L 2 + m L 2 = 1 3 ( M + 3 m ) L 2 − ( 2 ) Using Eq. ( 1 ) in Eq. ( 2 ) , we have, m v L = 1 3 ( M + 3 m ) L 2 ω ∴ ω = 3 m v L ( M + 3 m ) Hence, ( C )

Suggest Corrections 24 SIMILAR QUESTIONS

Q. Moment of inertia of uniform rod of mass 'M' and length 'L' about an axis through its centre and perpendicular to its length is given by

M L 2 12

. Now consider one such rod pivoted at its centre, free to rotate in a vertical plane. The rod is at rest in the vertical position. A bullet of mass 'M'moving horizontally at a speed 'v' strikes and embedded in one end of the rod. The angular velocity of the rod just after the collision will be

Q. A uniform rod of mass

m and length l

is free to rotate about a fixed horizontal axis passing through hinge. A small ball of mass

m

moving horizontally with velocity

v o

strikes the rod at depth

y

from hinge as shown in figure. If angular velocity of rod and velocity of ball just after the collision, be

ω and v

respectively, then which of the following statements are wrong?

Q. A rod of mass

m and length L

, pivoted at one of its ends, is hanging vertically. A bullet of the same mass moving at speed

v

strikes the rod horizontally at a distance

x

from its pivoted end and gets embedded in it. The combined system now rotates with angular speed

ω

about the pivot. The maximum angular speed

ω M is achieved for x = x M .Then Q. A uniform thin rod of mass,

M = 1 kg and length, L = 2 m

is hinged by a frictionless pivot at its one end

O

as shown in figure. A bullet of mass,

m = 50 g

moving horizontally with a velocity

v = 1500 ms − 1

strikes the free end of the rod and gets embedded in it the angular velocity of the system about

O

just after the collision is- Q. A uniform rod of mass

m and length L

can rotate freely on a smooth horizontal plane about a vertical axis hinged at point

O

. A point mass having same mass

m

coming with an initial speed

u

perpendicular to the rod, strikes the rod in-elastically at its free end. Find out the angular velocity of the rod just after collision?

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स्रोत : byjus.com

## SOLVED: 16. In the figure given below, a bullet of mass m movingwith speed u strikes a rod AB of mass M andlength L at the end B and gets embedded into it.If initially the rod is vertical and hinged at end A.then angular speed of the system just aftercollision will be[NCERT Pg. 173]Bammν(1)L(3m+M)Mv(2) L(3m+M)3mvB [(3m+M)3Mv(4)L(3m+M)No spamming irrelevant answers will be reported

VIDEO ANSWER: The thin road is pivoted from its center and the bullet hits at a distance. L. Y four and 888-349-8884 888-349-8884 888-349-8884 888-349-8884 888-349-8884 888-349-8884 888-349-8884 888-349-8884 888-349-8884 888-349-8884 888-349-8884 