in the given figure, a chord ab of the circle with centre o and radius 10 cm, that subtends a right angle at the centre of the circle. find the area of the minor segment aqbp. hence find the area of major segment albqa
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get in the given figure, a chord ab of the circle with centre o and radius 10 cm, that subtends a right angle at the centre of the circle. find the area of the minor segment aqbp. hence find the area of major segment albqa from screen.
In figure there is a chord AB of a circle with centre O and radius 10 cm , that subtends a right angle at the centre of the circle. Find the area of the minor segment AQBP . Hence find the area of major segment ALBQA .
Click here👆to get an answer to your question ✍️ In figure there is a chord AB of a circle with centre O and radius 10 cm , that subtends a right angle at the centre of the circle. Find the area of the minor segment AQBP . Hence find the area of major segment ALBQA .
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In figure there is a chord AB of a circle with centre O and radius 10 cm, that subtends a right angle at the centre of the circle. Find the area of the minor segment AQBP. Hence find the area of major segment ALBQA.
Hard Open in App Solution Verified by Toppr ∠ALB= 2 1 ∠AOB= 2 90 =45 0
LQ is perpendicular bisection on AB. Hence by isoceles triangles property.
LA=LB OB=10cm, & OA=10cm AB= 10 2 +10 2 =10 2 cm QB= 2 AB =5 2 cm OQ= OB 2 −QB 2 = 100−50 = 50 =5 2 cm LQ=LO+OQ=(10+5 2 )cm Area of ALBQA= 2 1 ×AB×LQ= 2 1 ×10 2 ×(10+5 2 ) =50(1+ 2 )cm 2 Area of AQBPA= 4 πr 2 −Ar.ofAOB = 4 π×10 2 − 2 1 ×10 2 ⇒28.54cm 2
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In the given figure, a chord AB of the circle with centre O and radius 10 cm, that subtends a right angle at the
In the given figure, a chord AB of the circle with centre O and radius 10 cm, that subtends a right angle ... of major segment A ∠ LBQA. (Use π =3.14)
In the given figure, a chord AB of the circle with centre O and radius 10 cm, that subtends a right angle at the
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Related questions
In Fig. 5 is a Chord Ab of a Circle, with Centre O and Radius 10 Cm, that Subtends a Right Angle at the Centre of the Circle. Find the Area of the Minor Segment Aqbp.
In Fig. 5 is a Chord Ab of a Circle, with Centre O and Radius 10 Cm, that Subtends a Right Angle at the Centre of the Circle. Find the Area of the Minor Segment Aqbp.
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In fig. 5 is a chord AB of a circle, with centre O and radius 10 cm, that subtends a right angle at the centre of the circle. Find the area of the minor segment AQBP. Hence find the area of major segment ALBQA. (use π = 3.14)
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SOLUTION
Given: Radius of the circle, r = 10 cm
Area of the circle =
π(10)2=3.14×100=314cm2
Area of the sector OAPB
=90o360o×π(10)2 =14×314[From(1)] =78.5cm2 Area of ∆BOA =12×BO×OA =12×10×10 =50cm2
Area of the minor segment AQBP = Area of the sector OAPB − Area of the triangle BOA
= (78.5 − 50) cm2 = 28.5 cm2
Area of the major segment ALBQ = Area of the circle − Area of the minor segment AQBP
= (314 − 28.5) cm2 = 285.5 cm2
Concept: Tangent to a Circle
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2015-2016 (March) Foreign Set 1
Q 14 Q 13 Q 15
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2015-2016 (March) Foreign Set 1 (with solutions)
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Guys, does anyone know the answer?