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    in the given figure abcd is a rectangle find the value of x and y

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    In Fig. 1, ABCD is a rectangle. Find the values of x and y .

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    Question

    In Fig. 1,ABCD is a rectangle. Find the values of x and y.

    ∵ ABCD  is a rectangle, the length of opposites sides are equal.

    Easy Open in App Solution Verified by Toppr ⇒AB=CDandAD=BC x+y=30 ...... (1) x−y=14 ..... (2)

    Adding  (1)+(2)⇒2x=44⇒x=

    2 44 ​ =22 cm.

    Subtracting  (1)−(2)⇒2y=16⇒y=

    2 16 ​ =8 cm. ∴x=22 cmandy=8 cm.

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    In fig. 1, ABCD is a rectangle. Find the values of x and y.

    In fig. 1, ABCD is a rectangle. Find the values of x and y.

    Byju's Answer Standard X Mathematics

    Multiplying/Dividing a Negative Entity

    In fig. 1, AB... Question

    In fig. 1, ABCD is a rectangle. Find the values of x and y.

    Open in App Solution

    Given, ABCD is a rectangle.

    ∴ AB = CD ⇒ 30 = x + y

    or x + y = 30 ..... (i)

    Similarly, AD = BC ⇒ 14 = x - y

    or x - y = 14 .......(ii)

    On adding eq. (i) and (ii), we get

    2x = 44 ⇒ x = 22

    Putting the value of x in eq. (i), we get

    22 + y = 30 ⇒ y = 30 -22 ⇒ y = 8 So, x = 22, y = 8. Suggest Corrections 62

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    RS Aggarwal Solutions Class 9 Mathematics Solutions for Quadrilaterals Exercise 10B in Chapter 10 - Quadrilaterals

    Prev Question 13 Next

    In each of the figures given below, ABCD is a rectangle. Find the values of x and y in each case.

    (i)

    Answer:

    (i) From the figure we know that the diagonals are equal and bisect at point O.

    Consider △ AOB We get AO = OB

    We know that the base angles are equal

    ∠ OAB = ∠ OBA = 35

    By using the sum property of triangle

    ∠ AOB + ∠ OAB + ∠ OBA = 180

    By substituting the values we get

    ∠ AOB + 35+ 35 = 180

    On further calculation

    ∠ AOB = 180 - 35 - 35

    By subtraction ∠ AOB = 180 - 70 ∠ AOB = 110

    From the figure we know that the vertically opposite angles are equal

    ∠ DOC = ∠ AOB = y = 110

    In △ ABC

    We know that ∠ ABC = 90

    Consider △ OBC We know that

    ∠ OBC = x = ∠ ABC - ∠ OBA

    By substituting the values

    ∠ OBC = 90 - 35 By subtraction ∠ OBC = 55

    Therefore, x = 55 and y = 110.

    (ii) From the figure we know that the diagonals of a rectangle are equal and bisect each other.

    Consider △ AOB We get OA = OB

    We know that the base angles are equal

    ∠ OAB = ∠ OBA

    By using the sum property of triangle

    ∠ AOB + ∠ OAB + ∠ OBA = 180

    By substituting the values

    110 + ∠ OAB + ∠ OBA = 180

    We know that ∠ OAB = ∠ OBA

    So we get 2 ∠ OAB = 180 - 110 By subtraction 2 ∠ OAB = 70 By division ∠ OAB = 35

    We know that AB || CD and AC is a transversal

    From the figure we know that ∠ DCA and ∠ CAB are alternate angles

    ∠ DCA = ∠ CAB = y = 35

    Consider △ ABC We know that ∠ ACB + ∠ CAB = 90 So we get ∠ ACB = 90 - ∠ CAB

    By substituting the values in above equation

    ∠ ACB = 90 - 35 By subtraction ∠ ACB = x = 55

    Therefore, x = 55 and y = 35.

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