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# in young’s double slit experiment, the distance of the screen from the double-slit is 2 m. when light of wavelength 550 nm is incident on the double-slit arrangement, fringes of width 2 mm are obtained on the screen. determine the distance of separation between the slits. also find the fringe width when the source of light is replaced by a source of light of wavelength 440 nm.

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### Mohammed

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get in young’s double slit experiment, the distance of the screen from the double-slit is 2 m. when light of wavelength 550 nm is incident on the double-slit arrangement, fringes of width 2 mm are obtained on the screen. determine the distance of separation between the slits. also find the fringe width when the source of light is replaced by a source of light of wavelength 440 nm. from screen.

## Young's double slit experiment is performed with light of wavelength 550 mm . The separation between the slits is 1.10 mm and screen is placed at distance of 1 m . What is the distance between the consecutive bright of dark fringes.

Click here👆to get an answer to your question ✍️ Young's double slit experiment is performed with light of wavelength 550 mm . The separation between the slits is 1.10 mm and screen is placed at distance of 1 m . What is the distance between the consecutive bright of dark fringes.

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A

B

C

D

## None of these

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Updated on : 2022-09-05

Solution Verified by Toppr

Correct option is C)

Distance between consecutive bright fringe or dark fringes =β

β= d λD ​ = 1.1×10 −3 550×10 −9 ×1 ​ =500×60 −6 =0.5 mm

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## 48. In Young's double slit experiment, the distance of the screen from th..

Solution For 48. In Young's double slit experiment, the distance of the screen from the double-slit is 2 m. Wher. light of wavelength 550 nm is incident on the double-slit arrangement, fringes of widt

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## 48. In Young's double slit experiment, the distance of the screen from the double-slit is 2 m. Wher. light of wavelength 550 nm is incident on the double-slit arrangement, fringes of width 2 mm are obtained on the screen. Determine the distance of separation between the slits. Also find the fringe width when the source of light is replaced by a source of light of wavelength 440 nm.

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Updated on: Mar 15, 2023

## Solutions

(7)

Fringe width, β= d λD ​ Slit width, d= β λD ​ d= 2×10 −3 550×10 −9 ×2 ​ d=5.5×10 −4 m=0.55 mm Now, if λ ′ =440 nm β ′ = d λ ′ D ​ β ′ = 5.5×10 −4 440×10 −9 ×2 ​ β ′ =1.6×10 −3 m=1.6 mm

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## In Young's double slit experiment, the distance of the screen from the double

In Young's double slit experiment, the distance of the screen from the double-slit is 2 m. When light of wavelength 550 nm is incident on the double-slit - 5510…