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    It is given that in a group of 3 students, the probability of 2 student not having the same birthday is 0.992. What is the probability that the 2 students have the same birthday?

    Answer :

    Let E be the event of having the same birthday

    i.e, P(E) = 0.992 But P(E) + P(E―) = 1 ⇒P(E―) = 1 − P(E) ⇒1 − 0.992 = 0.008 ∴

    The probability that the 2 students have the same birthday is 0.008.

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    It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992 . What is the probability that the 2 students have the same birthday?

    Click here👆to get an answer to your question ✍️ It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992 . What is the probability that the 2 students have the same birthday?

    Question

    It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992. What is the probability that the 2 students have the same birthday?

    Let

    Medium Open in App Solution Verified by Toppr B

    ≡ Event that 2 students do not have same birthday

    ∴P( B )=0.992

    So, probability of 2 students having same birthday P(B)=1−P(

    B ) =1−0.992 =0.008 Video Explanation

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    Ex 15.1, 7

    Ex15.1, 7 It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992. What is the probability that the 2 students have the same birthday? Probability that two students are not having same birthday = 0.992 Probability that two students are n

    Check sibling questions

    Ex 15.1, 7 - Chapter 15 Class 10 Probability (Term 1)

    Last updated at May 29, 2018 by Teachoo

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    Transcript

    Ex15.1, 7 It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992. What is the probability that the 2 students have the same birthday? Probability that two students are not having same birthday = 0.992 Probability that two students are not having same birthday = 1 Probability that two students are having same birthday P(not same birthday) = 1 P(same birthday) 0.992 = 1 P(same birthday) P(same birthday) = 1 0.992 P(same birthday) = 0.008 So, probability that 2 students will have the same birthday is 0.008

    Next: Ex 15.1, 8 →

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