# lonised hydrogen atoms and alpha particles enter perpendicular to a uniform magnetic field b. if they enter with same kinetic energy then ratio of their time periods will be

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## Ionized hydrogen atoms and α particles with same momenta enters perpendicular to a constant magnetic field B. The ratio of radii of their paths i.e. rH:rαwill beA. 2: 1B. 1: 2C. 4: 1D. 1: 4

Ionized hydrogen atoms and α particles with same momenta enters perpendicular to a constant magnetic field B. The ratio of radii of their paths i.e. rH:rαwill beA. 2: 1B. 1: 2C. 4: 1D. 1: 4

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Ionized hydrogen atoms and α particles with same momenta enters perpendicular to a constant magnetic field B. The ratio of radii of their paths i.e. rH:rαwill beA. 2: 1B. 1: 2C. 4: 1D. 1: 4

Question

Ionized hydrogen atoms and

α

-particles with same momenta enters perpendicular to a constant magnetic field

B

. The ratio of radii of their paths i.e.

r H : r α will be A 2 : 1 B 1 : 2 C 4 : 1 D 1 : 4 Open in App Solution

The correct option is **A** 2 : 1

q H q α = 1 2 r = m v q B For same momenta, r ∝ 1 q r H r α = q α q H = 2 1 Suggest Corrections 3

SIMILAR QUESTIONS

**Q.**Ionized hydrogen atoms and

α

-particles with same momenta enters perpendicular to a constant magnetic field

B

. The ratio of radii of their paths i.e.

r H : r α will be

**Q.**A proton and an

α

- particle (Helium nucleus) enters a uniform magnetic field with their direction of velocity perpendicular to the direction of magnetic field.

( i i i ) If proton and α

- particle enter the magnetic field, perpendicular to it with same momentum, then the ratio of the radii of curvature of proton and

α - particle will be [ 1 Mark ]

**Q.**A proton and an

α

- particle (Helium nucleus) enters a uniform magnetic field with their direction of velocity perpendicular to the direction of magnetic field.

( i v ) If proton and α

- particle enter the magnetic field, perpendicular to it with same kinetic energy, then the ratio of the radii of curvature of proton and

α - particle will be [ 1 Mark ]

**Q.**A proton and an

α

- particle (Helium nucleus) enters a uniform magnetic field with their direction of velocity perpendicular to the direction of magnetic field.

( i i ) If proton and α

- particle enter the magnetic field, perpendicular to it with same velocity, then the ratio of the radii of curvature of proton and

α - particle will be [ 1 Mark ]

**Q.**A proton, deutron and an

α

-particle enter a magnetic field perpendicular to field with same velocity. What is the ratio of the radii of circular paths?

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## Ionized hydrogen atoms and alpha

Click here👆to get an answer to your question ✍️ Ionized hydrogen atoms and alpha - particles with same momenta enters perpendicular to a constant magnetic field, B. The ratio of their radii of their paths rH : ralpha will be :

Ionized hydrogen atoms and α-particles with same momenta enters perpendicular to a constant magnetic field, B. The ratio of their radii of their paths rQuestion H :r α will be :

**A**

## 2:1

**B**

## 1:2

**C**

## 4:1

**D**

## 1:4

Medium Open in App

Updated on : 2022-09-05

Solution Verified by Toppr

Correct option is A)

We know,r H = e×B P r α = 2e×B P

(As α has 2e of charge on it)

r α r H = 2eB P eB P ⟹ r α r H = 1 2

Hence option A is correct answer

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## Ionized hydrogen atoms and alpha

r=(mv)/(qB)=(p)/(qB)rArr r alpha(1)/(q) (r(n))/(r)=(q(alpha))/(q(n))=(2)/(1)=2:1

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Ionized hydrogen atoms and alp...

Ionized hydrogen atoms and

α− α-

particle with moments enters perpendicular to a constant megnetic field. B. The ratio of their radii of their paths

r H : r α rH:rα be :

Updated On: 27-06-2022

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Text Solution Open Answer in App A 1:4 1:4 B 2:1 2:1 C 1:2 1:2 D 4:1 4:1 Answer

The correct Answer is B

Solution r= mv qB = p qB ⇒rα 1 q r=mvqB=pqB⇒rα1q r n r = q α q n = 2 1 =2:1 rnr=qαqn=21=2:1 Answer

Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

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A deuteron and an alpha particle having equal kinetic energy enter perpendicular into a magnetic field. Let

r d and r α rdandrα

be their respective radii of circular path. The value of

r d r α rdrα is equal to : Show More Comments

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Guys, does anyone know the answer?